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2 | PROJECT : | PAGE : | |||||||||||||
3 | CLIENT : | DESIGN BY : | |||||||||||||
4 | JOB NO. : | DATE : | REVIEW BY : | ||||||||||||
5 | Design of Conventional Slabs on Expansive Soil Grade Based on 2015 IBC/ACI 360 | ||||||||||||||
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7 | 1. DESIGN METHODS | ||||||||||||||
8 | 1,1 | DIVIDE AN IRREGULAR FOUNDATION PLAN INTO OVERLAPPING RECTANGLES AND USING | |||||||||||||
9 | THIS SPREADSHEET DESIGN EACH RECTANGULAR SECTION SEPARATELY. | ||||||||||||||
10 | 1,2 | THE POST-TENSION INSTITUTE (PTI) METHOD IS ACCEPTABLE FOR THE DESIGN OF | |||||||||||||
11 | NONPRESTRESSED SLAB ON GRADE (2015 IBC 1808.6.2). THE DESIGNER MAY SELECT EITHER | ||||||||||||||
12 | NONPRESTRESSED REINFORCEMENT USING THIS SPREADSHEET, OR POST-TENSIONED | ||||||||||||||
13 | REINFORCEMENT IF REQUIRED (ACI 360, 9). | ||||||||||||||
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28 | 2. INPUT DATA & DESIGN SUMMARY | ||||||||||||||
29 | 2.1 SOILS PROPERTIES | ||||||||||||||
30 | ALLOWABLE SOIL-BEARING PRESSURE | qallow | = | 2000 | psf | ||||||||||
31 | EDGE MOISTURE VARIATION DISTANCE | em | = | 4 | ft, for center lift | ||||||||||
32 | = | 4,5 | ft, for edge lift | ||||||||||||
33 | DIFFERENTIAL SOIL MOVEMENT | ym | = | 2,68 | in, for center lift | ||||||||||
34 | = | 0,3 | in, for edge lift | ||||||||||||
35 | 2.2 STRUCTURAL DATA AND MATERIALS PROPERTIES | ||||||||||||||
36 | SLAB LENGTH | L | = | 164 | ft | ||||||||||
37 | SLAB WIDTH | B | = | 125 | ft | ||||||||||
38 | SLAB THICKNESS | t | = | 5 | in | ||||||||||
39 | PERIMETER LOADING | P | = | 270 | plf | ||||||||||
40 | MAX BEARING LOADING ON THE SLAB | Pb | = | 270 | plf | ||||||||||
41 | ADDED DEAD LOAD | DL | = | 50 | psf | ||||||||||
42 | LIVE LOAD | LL | = | 125 | psf | ||||||||||
43 | AVERAGE STIFFENING BEAM SPACING, L DIRECTION | SL | = | 30 | ft | ||||||||||
44 | AVERAGE STIFFENING BEAM SPACING, B DIRECTION | SB | = | 30 | ft | THE DESIGN IS ADEQUATE. | |||||||||
45 | STIFFENING BEAM DEPTH | h | = | 24 | in | ||||||||||
46 | STIFFENING BEAM WIDTH | b | = | 20 | in | ||||||||||
47 | CONCRETE STRENGTH | f'c | = | 3 | ksi | ||||||||||
48 | REINFORCEMENT IN THE BOTTOM OF STIFFENING BEAM | 2 | # | 6 | |||||||||||
49 | SLAB REINFORCEMENT | # | 4 | @ | 18 | in o.c., with | 1,5 | in clear from top of slab, each way. | |||||||
50 | |||||||||||||||
51 | 3. ASSUME A TRIAL SECTION | ||||||||||||||
52 | 3.1 ASSUME BEAM DEPTH AND SPACING | ||||||||||||||
53 | ALLOWABLE DIFFERENTIAL DEFLECTION, FOR CENTER LIFT, AT L DIRECTION | ALLOWABLE DIFFERENTIAL DEFLECTION, FOR CENTER LIFT, AT B DIRECTION | |||||||||||||
54 | Dallow = 12 MIN(L, 6b) / CD = | 1,60 | in | Dallow = 12 MIN(B, 6b) / CD = | 1,60 | in | |||||||||
55 | Where | b = | 8 | ft | Where | b = | 8 | ft | |||||||
56 | CD = | 360 | CD = | 360 | |||||||||||
57 | ALLOWABLE DIFFERENTIAL DEFLECTION, FOR EDGE LIFT, AT L DIRECTION | ALLOWABLE DIFFERENTIAL DEFLECTION, FOR EDGE LIFT, AT B DIRECTION | |||||||||||||
58 | Dallow = 12 MIN(L, 6b) / CD = | 0,80 | in | Dallow = 12 MIN(B, 6b) / CD = | 0,80 | in | |||||||||
59 | Where | b = | 8 | ft | Where | b = | 8 | ft | |||||||
60 | CD = | 720 | CD = | 720 | |||||||||||
61 | BEAM DEPTH, FOR CENTER LIFT, AT L DIRECTION | BEAM DEPTH, FOR CENTER LIFT, AT B DIRECTION | |||||||||||||
62 | h = [(ym L)0.205 SB1.059 P0.523 em1.296 / 380 Dallow ]0.824 = | 13,56 | in | h = [(ym B)0.205 SL1.059 P0.523 em1.296 / 380 Dallow ]0.824 = | 12,95 | in | |||||||||
63 | BEAM DEPTH, FOR EDGE LIFT, AT L DIRECTION | BEAM DEPTH, FOR EDGE LIFT, AT B DIRECTION | |||||||||||||
64 | h = [L0.35 SB0.88 em0.74 ym0.76 / 15.9 Dallow P0.01]1.176 = | 8,47 | in | h = [B0.35 SL0.88 em0.74 ym0.76 / 15.9 Dallow P0.01]1.176 = | 7,58 | in | |||||||||
65 | GOVERNING h = | 13,56 | in | < | ACTUAL h = | 24,00 | in | [Satisfactory] | |||||||
66 | 3.2 DETERMINE SECTION PROPERTIES | ||||||||||||||
67 | L DIRECTION | B DIRECTION | |||||||||||||
68 | As = | 17 | in2 | n = | 6 | beams | As = | 22 | in2 | n = | 7 | beams | |||
69 | Es / Ec = | 9,29 | yb = | 18,75 | in | Es / Ec = | 9,29 | yb = | 19,00 | in | |||||
70 | CGS = | 21,75 | in | St = | 64268 | in3 | CGS = | 22,25 | in | St = | 80834 | in3 | |||
71 | A = | 9935 | in2 | Sb = | 17995 | in3 | A = | 12703 | in2 | Sb = | 21276 | in3 | |||
72 | I = | 337410 | in4 | I = | 404232 | in4 | |||||||||
73 | |||||||||||||||
74 | 4. CALCULATE MAXIMUM APPLIED SERVICE MOMENTS | ||||||||||||||
75 | 4.1 CENTER LIFT MOMENT AT L DIRECTION | CENTER LIFT MOMENT AT B DIRECTION | |||||||||||||
76 | ML = A0 (B em1.238 + C) = | 4,96 | ft-kips / ft | MB = (58 + em) ML / 60, for L /B > 1.1 | = | 5,12 | ft-kips / ft | ||||||||
77 | Where | A0 = (L0.013 SB0.306 h0.688 P0.534 ym0.193) / 727 = | 0,891 | MB = ML, for L /B < 1.1 | |||||||||||
78 | |||||||||||||||
79 | B = 1, for em < 5 | = | 1,00 | ||||||||||||
80 | B = MIN[(ym - 1) / 3, 1], for em > 5 | ||||||||||||||
81 | |||||||||||||||
82 | C = 0, for em < 5 | = | 0,00 | ||||||||||||
83 | C = MAX{[8 - (P - 613) / 255] (4 - ym) / 3], 0}, for em > 5 | ||||||||||||||
84 | |||||||||||||||
85 | 4.2 EDGE LIFT MOMENT AT L DIRECTION | EDGE LIFT MOMENT AT B DIRECTION | |||||||||||||
86 | ML = SB0.10 (h em)0.78 ym0.66 / (7.2 L0.0065 P0.04) = | 2,63 | ft-kips / ft | MB = h0.35 (19 + em) ML / 57.75, for L /B > 1.1 | = | 3,25 | ft-kips / ft | ||||||||
87 | MB = ML, for L /B < 1.1 | ||||||||||||||
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89 | 5. CHECK FLEXURAL CONCRETE STRESSES | ||||||||||||||
90 | 5.1 ALLOWABLE CONCRETE STRESSES | ||||||||||||||
91 | FLEXURAL TENSILE STRESS | ft,allow = - 6 (fc')0.5 = | -0,329 | ksi | |||||||||||
92 | FLEXURAL COMPRESSIVE STRESS | fc,allow = - 0.45 fc' = | 1,350 | ksi | |||||||||||
93 | |||||||||||||||
94 | 5.2 TOP STRESS, FOR CENTER LIFT MOMENT, AT L DIRECTION | TOP STRESS, FOR CENTER LIFT MOMENT, AT B DIRECTION | |||||||||||||
95 | f = - ML / St = | -0,116 | ksi | f = - MB / St = | -0,125 | ksi | |||||||||
96 | Then f | > | ft,allow | [Satisfactory] | Then f | > | ft,allow | [Satisfactory] | |||||||
97 | < | fc,allow | [Satisfactory] | < | fc,allow | [Satisfactory] | |||||||||
98 | |||||||||||||||
99 | 5.3 BOTTOM STRESS, FOR CENTER LIFT MOMENT, AT L DIRECTION | BOTTOM STRESS, FOR CENTER LIFT MOMENT, AT B DIRECTION | |||||||||||||
100 | f = ML / Sb = | 0,413 | ksi | f = MB / Sb = | 0,474 | ksi |