ABCDEFGHIJKLMNOPQR
1
32
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34
1 st cycle
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Step 1:
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Assume xu=246.08
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Step 2:
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Cu=1450676.24
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Step 3
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Strain =0.00247
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From the table, we get the following values for fst:
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44
Strainstress
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0.00241342.80
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0.00247344.44
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0.00276351.80
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So fst=344.44
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Step 4
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So Tu = fst x Ast =1484615.426
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Cu is not equal to Tu.
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To find an improved value of xu:
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Xu used in this cycle =246.08
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xu obtained by assuming Cu = Tu in this cycle
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=260.50
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Average of the above two values
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=253.29
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This is the trial value of xu for the next cycle
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2 nd cycle
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Step 1:
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Assume xu=253.29
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Step 2:
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Cu=1467645.833
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Step 3
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Strain =0.00230
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From the table, we get the following values for fst:
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Strainstress
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0.00192324.80
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0.00230338.89
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0.00241342.80
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So fst=338.89
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Step 4
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So Tu = fst x Ast =1460708.847
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85
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Cu is not equal to Tu.
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To find an improved value of xu:
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Xu used in this cycle =253.29
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xu obtained by assuming Cu = Tu in this cycle
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=250.34
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Average of the above two values
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=251.82
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This is the trial value of xu for the next cycle
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3 rd cycle
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Step 1:
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Assume xu=251.82
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Step 2:
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Cu=1464177.34
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Step 3
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Strain =0.00234
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From the table, we get the following values for fst:
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106
Strainstress
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0.00192324.80
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0.00234340.14
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0.00241342.80
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So fst=340.14
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Step 4
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So Tu = fst x Ast =1466087.938
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Cu is not equal to Tu.
118
To find an improved value of xu:
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Xu used in this cycle =251.82
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xu obtained by assuming Cu = Tu in this cycle
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=252.63
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Average of the above two values
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=252.22
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This is the trial value of xu for the next cycle
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4 th cycle
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Step 1:
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Assume xu=252.22
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Step 2: