ABCDEFGHIJKLMNOPQRSTUVWXYZ
1
One stage from LEO
2
3
11
Speed in AU/yr (only used for hypothetical delta-V), not end result
This section works from Au/yr
To confirm against New Horizons
To confirm against Voyager 1, set
4
1.4960E+11AU
back to required delta-V from
data, use a13-14 as 300,300k
a24 to 373k to get correct V at 4 AU.
5
52,145.9m/s
Earth orbit, assuming no gravity
a24-27 as 720k, 100k, 85k, 380.
Jupiter to 5.285 AU, 12381 m/s
6
1.36E+09E/kg
assist from Jupiter
These are just to get the C3 about
and 570 m/s (from Horizons).
7
1.33E+20MG of sun|
right (2% off), but gets the velocities
8
8.87E+08
Extra energy at Earth radius
|
at 2,3,4 AU just right (both tangential
Correct answer is 20870 m/s at 8 AU
9
2.25E+09
E/kg (solar escape but not earth)
|
and radial). Difference is likely Earth's
10
29,784.48Speed of Earth|
non-circular orbit. Then plug in for
11
3.99E+14GM for earth|
Jupiter (5.34, 12680, -509). These are
12
6378
Radius of Earth (km)
|
the actual values for Jupiter on the
13
300
Perigee of Earth orbit (km)
|
date of the New Horizons flyby.
14
300000
Apogee of Earth orbit (km)
|
Set the ISP to 0 for the Jupiter
15
6.68E+06
perigee from center (m)
|
assist, making it unpowered.
16
3.06E+08
apogee from center (m)
|
Finally, set the flyby distance to 32.4
17
10808.8
Speed at perigee
|Jupiter radius.
18
7725.8
Two limiting cases, double check: orbital speed (circular LEO orbit)
|
19
10926.0
orbital speed (super highly eccentric orbit)
|
Then at the very end, you can compare
20
2.31E+09
Final E/kg at perigee, assuming speed in A3
|
against the New Horizons numbers
21
67917.6
Final V (solar system frame)
|
from the JPL trajectory.
22
27324.3
delta v needed from orbit, if no other assists
|
52.09 AU, v=13838 m/s
23
24
1,200,000Fuel mass
Now work forward, this time including powered Jupiter gravity assist
25
100000
payload mass (kg)
26
85000stage dry mass
27
380isp
This section just to compute a conventional C3
28
7497.5
delta v provided by stage
14688.3
v earth frame, after Earth escape
29
18306.4
v (Earth relative), m/s
Convert back to solar system coordinates
215.7C3
30
1.68E+08e/kg
31
1.08E+08
e/kg, after earth escape
32
14688.3
V, m/s after Earth escape,earth relative
33
44,472.8
V m/s, solar frame
34
9.89E+08
e/kg, solar frame
Table for comparison plot to JPL
35
1.02E+08
e/kg after solar escape
Assuming no further assist
233.026
36
25439.2v at 4.0 AU
For checking against JPL
|328.196
37
11118.2
4 AU transverse velocity (m/s)
|425.439
38
22881.0
4 AU radial velocity (m/s)
|523.631
39
14268.7v at infinity|622.345
40
3.01au/yr|
41
42
1.2669E+17GM for Jupiter
43
5.200
Distance from sun (AU)
If you don't have specific values here (as from JPL Horizons),
44
13061.4
Tangential speed of orbit around sun (m/s)
use 5.2 AU, sqrt(mu/r), and 0 (circular orbit)
45
0Radial speed13061.4
Example of sqrt(MuSun/JupiterDist)
46
0.00
Angle of orbit to pure tangent
Not used; we assume Jupiter is just translating; coordinate systems are aligned
47
48
2.72E+08
e/kg at jupiter distance
This section assumes we can do a passive gravity
49
23,341
v (solar sys coords) at Jupiter
turn at Jupiter. In the Jupiter frame,
50
8,552
v (along orbit), by conservation of angular momentum
incoming and outgoing velocities are
51
21,718
v (perpendicular to orbit)
equal. So find incoming velocity, then
52
-4,509
speed, along orbit, in Jupiter frame
apply the same velocity in the direction
53
22,181
incoming velocity, Jupiter frame
of Jupiter's orbit. Does not check for feasibility.
54
35,242
outgoing velocity, solar frame, assuming turn is possible
55
6.21E+08
e/kg at jupiter distance
56
4.50E+08e/kg at infinity
57
30,013v at infinity
58
6.33
au/year, passive gravity assist at Jupiter
These are theoretical best results. The required bend may end up
59
101.73
degrees bend, Jupiter frame
hitting Jupiter. See next section for more realistic calculations
60
61
71,492
Jupiter radius (km)
62
1.05
Flyby perijove in units of radius
63
75066600
Flyby distance (from center), m
64
1.29eccentricity
Eqns from https://ocw.mit.edu/courses/aeronautics-and-astronautics/16-07-dynamics-fall-2009/lecture-notes/MIT16_07F09_Lec16.pdf, page 6
65
101.48
turn angle (degrees)
66
67
2.46E+08
incoming e/kg, Jupiter frame
100000initial mass
68
1.93E+09at perijove5000payload
69
62187.6
speed at perijove
5000empty stage
70
8575.7delta V added380isp
71
70763.4new speed8575.7delta v
72
2.50E+09new e/kg
73
8.16E+08
new e/kg after exiting Jupiter gravity well
74
40399.6
exit speed, Jupiter frame
75
1.97New eccentricity
76
61.11
New turning angle
77
78
81.30
Total tuning angle (1/2 of first part, 1/2 of second)
79
-101.49
entrance angle, jupiter frame
80
159.80
exit angle, jupiter frame
81
-37915.85
x comp jupiter frame
82
13946.96y componnt
83
50977.2x solar frame
84
13946.96
tangential v, solar frame
85
52850.7
final v, solar frame
29509.8gained by flyby
86
1.40E+09
e/kg, solar frame
87
1.23E+09
e/kg after solar escape
88
49517.6v at infinity
89
10.45au/year
Table for comparison plot to JPL
90
552.980
91
8dist in AU
For example with known results, plug in distance here
652.419
92
1.34E+09e/kg752.014
93
51708.55m/sec851.709
94
20870m/sec
Plug in known value of velocity, e.g. from JPL Horizons
951.470
95
147.765%Error1051.278
96
97
98
99
100