ABCDEFGHIJKLMNOPQRSTUVWXYZ
1
DESIGN OF HOLLOW BLOCK SLAB :-
2
3
SLAB ID :-
S-8 ( a-direction)
4
5
1)- APPLIED LOADS :-
6
- Mu (+ive)=mt
7
- Mu (-ive)R=0,00mt
8
- Mu (-ive)L=0,00mt
9
- QuR=4,40t
10
- QuL=4,40t
11
- Wu =1,17t/m
12
13
14
2)- PROPERTIES OF MATERIAL :-
15
- Fcu=250Kg/cm2
16
- Fy ( Steel)=3600Kg/cm2
17
- Fy ( Stirr.)=2400Kg/cm2
18
19
20
3)- DIMENSIONS OF SLAB :-
21
- Thickness of solid slab (ts) =
45cm
22
- Total thickness of H.B.S (t) =
220cm
23
- Width of rib (b)
=45cm
24
25
26
4)- DESIGN OF T-SEC. AT M (+ive) :-
a=550,5408
27
a)- ( 0.531 Fy2 / B.Fcu ) As2 - ( 0.9 Fy.d ) As + Mu = 0
b=-704700
28
Ascal =0,00cm2c=0
29
X1=1280,014124
30
b)- Asb = b.d ( ( 4550 / 6300 + Fy ).Fcu / Fy + ( 0.85 Fcu ( B - b ) ts ) / ( b.d.Fy )
X2=0
31
Asb =325,66cm2
Ascal < 0.5 Asb -- ( O.K )
32
33
c)- Asmin1 = 9 / Fy ( b.d )
=24,47cm2
34
Asmin2 = 1.33 Ascal.
=0,00cm2
35
Asmin =0,00cm2
36
37
Asfinal=0,00cm2
38
Use218/Rib
39
40
41
5)- DESIGN OF R-SEC. AT M (-ive)R :-
a=550,5408
42
a)- ( 0.531 Fy2 / B.Fcu ) As2 - ( 0.9 Fy.d ) As + Mu = 0
b=-704700
43
Ascal =0,00cm2c=0
44
X1=1280,014124
45
b)- Asb = B.d ( ( 4550 / 6300 + Fy ).Fcu / Fy
X2=0
46
Asb =347,09cm2
Ascal < 0.5 Asb -- ( O.K )
47
48
c)- Asmin1 = 9 / Fy ( B.d )
=27,19cm2
49
Asmin2 = 1.33 Ascal.
=0,00cm2
50
Asmin =0,00cm2
51
52
Asfinal=0,00cm2
53
Use212/Rib
54
55
56
6)- DESIGN OF R-SEC. AT M (-ive)L :-
57
a)- ( 0.531 Fy2 / B.Fcu ) As2 - ( 0.9 Fy.d ) As + Mu = 0
58
Ascal =0,00cm2a=550,5408
59
b=-704700
60
b)- Asb = B.d ( ( 4550 / 6300 + Fy ).Fcu / Fy
c=0
61
Asb =347,09cm2
Ascal < 0.5 Asb -- ( O.K )
X1=1280,014124
62
X2=0
63
c)- Asmin1 = 9 / Fy ( B.d )
=27,19cm2
64
Asmin2 = 1.33 Ascal.
=0,00cm2
65
Asmin =0,00cm2
66
67
Asfinal=0,00cm2
68
Use212/Rib
69
70
71
7)- CHECK MR FOR RIGHT SIDE :-
72
- MR = Rmax ( Fcu / gc ) b.d2 =
702,50mt/rib
73
- Mact=0,00mt/rib
74
MR > Mact --- Use Min. Solid Part
75
SR =30cma=0,585
76
b=-4,40
77
8)- CHECK MR FOR LEFT SIDE :-
c=-1404,995625
78
- MR = Rmax ( Fcu / gc ) b.d2 =
702,50mt/ribX1=52,91192653
79
- Mact=0,00mt/ribX2=-45,39055901
80
MR > Mact --- Use Min. Solid Part
S=-4539,055901
81
SL =30cmS=-4539
82
a=0,585
83
9)- CHECK SHEAR ON RIBS FROM RIGHT SIDE :-
b=-4,40
84
- qcu = 0.73 Fcu =
11,54Kg/cm2c=-1404,995625
85
- qumax = 2.04 Fcu =
32,26Kg/cm2X1=52,91192653
86
- Quact / Rib = ( QuR - Wu . SR ) / 2 =
2,02tX2=-45,39055901
87
- qu = ( Qu / 0.85 ( b.d + B.ts ) ) =
0,24Kg/cm2S=-4539,055901
88
qu < qcu --- Use Solid Part as calculated above
S=-4539
89
SR =30cm
90
91
10)- CHECK SHEAR ON RIBS FROM LEFT SIDE :-
92
- Quact / Rib = ( QuL - Wu . SL ) / 2 =
2,02t
93
- qu = ( Qu / 0.85 ( b.d + B.ts ) ) =
0,24Kg/cm2
94
qu < qcu --- Use Solid Part as calculated above
95
SL=30cm
96
97
98
99
100