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PROJECT
150123 Portsea North ApartmentsSECTION1LRFD
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TITLE
Floor support beamsDATE4/5/2026CODE SPECS.
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FILE
150123 LRFD_composite_beam_design.xlsTIME11:09 PM
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SIMPLY SUPPORTED I SECTION COMPOSITE BEAM DESIGN
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DESCRIPTION
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-Check design shear and flexure strength of a simply supported I section composite beam to AISC LRFD 3rd Ed.
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-Note that for "unshored" construction, total deflection is sum of deflection of the steel beam under its own load, and deflection of the composite beam
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under dead and live loads. For "shored" construction, total deflection is sum of deflection under dead and live loads for the composite section only.
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-Based on methods used in "Steel Structures Design and Behaviour" by: Salmon & Johnson (see pages 1010-1061)
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-Transformed Section method has been used to calculate elastic section properties
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-It is assumed that all shear will be transferred through Headed Studs and that concrete and steel sections form a fully composite section
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-Steel Material assumed to conform to ASTM A922
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-See AISC LRFD Specifications Chapter I
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INPUT PARAMETERS
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Structure
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-Beam Span Lb=800017,41[ft]5306[mm]
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-Specified Uniformly Distributed Live LoadLL=0,18667
[kip/ft]
3[kN/m]
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-Specified Uniformly Distributed Dead LoadDL=0,88
[kip/ft]
13[kN/m]
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-Live Load FactorLf=1,6[]2[]
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-Dead Load FactorDf=1,2[]1[]
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-Factored Maximum MomentMu=(Lf*LL+Df*DL)*Lb^2/8=51
[kip-ft]
68[kN-m]
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-Factored Maximum ShearVu=(Lf*LL+Df*DL)*Lb*0.5=12[kip]52[kN]
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-Shear Stud DiameterSd=0,75[in]19[mm]
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Section Dimensions
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-Effective Widthbe=110[in]2794[mm]
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-Slab Thicknessts=8[in]203,2[mm]
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-Steel SectionDes=ST10X37.5[]
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Material Properties
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-Steel Yield StrengthFy==36[ksi]248[MPa]
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-Shear Stud Ultimate StrengthFu=58[ksi]400[MPa]
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-Concrete Compressive Strengthfc==3500[psi]24138[MPa]
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-Steel Elastic ModulusEs==29000[ksi]200000[MPa]
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-Steel Elastic ModulusEc=Es/index(C_Table,Match(fc,Comp,0),2)=3412[ksi]23529[MPa]
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-Table Rowrow=Match(Des,section,0)=795
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CALCULATIONS
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Section Properties
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-Area of SteelAs=index(table,row,4)=11,00[in^2]7096,8[mm^2]
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-Height to web thickness ratiohc=index(table,row,25)=13,6[]13,60[]
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-Moment of Inertia about x-xIx=index(table,row,31)=109,0[in^4]45369225[mm^4]
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-Beam DepthBD=index(table,row,5)=10,00[in]254[mm]
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-Flange Widthbf=index(table,row,8)=6,39[in]162,306[mm]
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-Flange Thicknesstf=index(table,row,12)=0,795[in]20,193[mm]
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-Steel to Concrete E rationn=index(C_Table,Match(fc,Comp,0),2)=8,5[]9[]
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-Check whether we use Plastic or Elastic Stress Distr.Chk1=if(hc<=3.76*sqrt(Es/Fy),"Plastic","Elastic")=PlasticLRFD I3.2
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Elastic Section Properties
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-Concrete Transformed widthbet=be/nn=12,9[in]328,7058824[mm]
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-Location of Composite Elastic Neutral Axis yd=(((As*BD/2)+(bet*ts*(BD+ts/2)))/(As+ts*bet))=13,14[in]334[mm]
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-Moment of Inertia of Composite section about x-xItr=Ix+(As*(yd-BD/2)^2)+(1/12*ts^3*bet)+(ts*bet)*(yd-BD-ts/2)^2=1466,58[in^4]610436930[mm^4]
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-Extreme fiber tension section modulusStr=Itr/yd=111,65[in^3]1829605,2[mm^3]
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-Extreme fiber compression section modulusSconc=Itr/(BD+ts-yd)=301,5[in^3]4940571,6[mm^3]
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Flexural Strength Calculations
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-Flexural Strength Based on Elastic StressMn1=if(Chk1="Elastic", min(0.9*0.85*Sconc*fc,0.9*Str*Fy)/12,"See Below")=See Below
[kip-ft]
#VALUE![kN-m]LRFD I3.2
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Case-1 Plastic Neutral Axis (PNA) in Slab
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-Uniform Compression stress depthad=(As*Fy)/(0.85*fc*be/1000)=1,210[in]31[mm](16.7.3)
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-Compressive force in case 1C1=0.85*fc/1000*ad*be=396,0[kip]1760[kN](16.7.1)
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-Tensile force in case 1T1=As*Fy=396,0[kip]1760[kN](16.7.2)
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-Factored Nominal Flexural Strength based on Case 1Mn2=if(ts>ad,0.85*As*Fy*(BD/2+ts-ad/2)/12,"N/A")=348
[kip-ft]
464[kN-m](16.7.5)
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Case-2 Plastic Neutral Axis (PNA) in Steel Beam
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-Compressive force in concreteCc=0.85*fc*be*ts/1000=2618[kip]11636[kN](16.7.6)
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-Tension force in steelCs=((As*Fy)-Cc)/2=-1111[kip]-4938[kN](16.7.9)
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-Thickness of flange in compressiondf=Cs/(bf*Fy)=-4,830[in]-123[mm]
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-Check if PNA within flangeChk2=if(df<0,"N/A",if(tf<bf,"PNA in Flange","PNA in Web"))=N/A
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-Distance to the centroid of tension portion of steel beam
yct=if(Cs<0,"N/A",((As*BD/2)-(df*bf*(BD-df)))/(As-bf*df))=N/A[in]N/A[mm]
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-Factored Nominal Flexural Strength based on Case 2Mn3=if(Cs<0,"N/A",0.85*(Cc*(BD+ts/2-yct)+Cs*(BD-yct-df/2))/12)=N/A
[kip-ft]
N/A[kN-m](16.7.10)
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Shear Strength Calculations
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-Required stud shear strengthVnh=min(0.85*fc*be*ts/1000,As*Fy)=396,0[kip]1760[kN]
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-Nominal stud shear strengthQn=0.5*pi()*Sd^2/4*sqrt(fc*Ec/1000)=24,14[kip]107[kN]
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-Number of required StudsNs=round(Vnh/Qn,0)=16[]16[]
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-Maximum Stud Spacingps=min(8*ts,Lb*12/Ns)=13[in]332[mm]
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Deflections
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-Dead Load DeflectionDDL=5*DL*(Lb*12)^4/(384*Es*Ix)=6,90[in]175,2[mm]
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-Live Load DeflectionDLL=5*LL*(Lb*12)^4/(384*Es*Itr)=0,11[in]2,8[mm]