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Questions Link to Answers Want to talk about it in class?
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Ch 3 QUESTIONS
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3.2 #9 Link to my work for these Questions
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3.2 #21 - just confused on finding c value
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3.2 #61
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3.2 #37 part c
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3.3 #33 - taking derivative of absolute value
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3.3 #39
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3.3 #48
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3.3 #36 Link for these two questions
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3.4 #25
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3.4 # 9 Link for these questions
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3.4 #15
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3.4 #37 (why you can't use second derivative)
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3.6 #43 (answer key is using decimals and strange forms)
When you set the 2nd derivative equal to zero, there's no way to solve it algebraically, so we have to turn to desmos to see where the zeros are...
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3.6 #25 (steps for 2nd derivative)Link to find 2nd derivative for #25
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3.6 #43 (isnt the 1st derivative tan x + x(sec x)^2
Yes it is! I'm not sure what they were thinking - they made it way more difficult than it is!
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3.6 #25 (is there a slant asymptote?)
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Ch 4 QUESTIONS
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4.1 #41 and #43 Link to 4.1 - #41 and #43
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4.1 #35, #59 Link to 4.1 - #35 and #59
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4.3 #21 -- does dy and g(y) mean a given y interval rather than a given x interval? ------------------->
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4.5 #21, #30 Link to 4.5 - #21 - #75
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4.5 #47, #59, #75
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4.4 #45: Calcchat explanation doesnt make sense
Sketch this to find your interval over which the function intersects the x-axis.
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Ch 5 QUESTIONS
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5.1 #55
Quotient rule, then factor out t on top, then the t ^4 in the denominator becomes t ^3 when you simplify.
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5.2 #31 Why is (u+3) squared? since root2 = u+3, shouldn't it be u+3?
 Link to 5.2 #31
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5.2 #27 Link to 5.2 #27
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5.2 #33 -- why is there a 3 pulled out?
u= sin (x/3), so du= 1/3(cos x/3) We then have to get rid of the 1/3, so it ends up as 3 on the du side.
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5.2 #55 and #57 Link to 5,2 #55 and #57
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5.3 #63 & #67 Link to 5.3 #63 and #67
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5.3 #15
Link to 5.3 #15, #65, and #63 (addressing monotonic part)
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5.3 #65
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5.3 #63, when I set the derivative of f(x) equal to 0 I get a value, so how is the function monotonic?
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5.4 #53 & 103 & 109 Link to 5.4 - #53, #103 and #109
#31 - I think it's because inverse secant's range is -pi/2 to pi/2. yet x (as the hypotenuse of our triangle) has to always be positive.
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5.5 #59 and 73 Link to 5.5 #59 and #73
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5.7 #12, why is it 5pi/6 instead of -pi/6? , #31 where did the absolute value come from?
#12 - Inverse cotan has the range of 0 to pi (just like cos).
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* NOTE: #12 and #31 required you to remember what the graphs of cot and sec look like. If you have questions about any trig grpahs, let me know and we'll review in class.
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Ch 6 QUESTIONS
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6.3 #53 Link to 6.3 #53
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6.3 # 57 Link to 6.3 #57
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6.3 # 61 Link to 6.3 #61
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6.3 #65 Link to 6.3 #65
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6.3 #66 Link to 6.3 #66
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6.1 # 81 (how do we find exact for dy/dx=y+cosx Just do the EULER'S part of this.
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6.3 # 61 part d (Euler's) Link to 6.3 # 61 Part D
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#9 on reveiw why is the negavtive on a particular side? putting it on the other side yeilds a different answer (C=-1) because e to any power is always positive. How do we know which side? Or when simplifying can we say ln|-y|=ln(y) before exponentiating?
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Ch 8 QUESTIONS
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8.1 #39 Link to #39 and #43
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8.1 #43
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8.1 #45 Link to UPDATED #45
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8.1 #41 Link to #41
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8.1 #33 Link to #33 and #35
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8.1 #35
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