| A | B | C | |
|---|---|---|---|
1 | Timestamp | group name | |
2 | 1/25/2012 11:28:11 | So that one can adjust the mechanism or the measured value. | wCjfuUMhUb97 |
3 | 1/25/2012 11:32:07 | In this case, put an amount of weight on the weighing scale, then subtract 0.3 kg from it. | Howl |
4 | 1/25/2012 11:36:36 | idk | |
5 | 1/25/2012 11:37:36 | It is not useful, and to correct it, just subtract(if it is positive) or add(if it is negative), without the negative sign, the zero error value from the value shown. | Howl |
6 | 1/25/2012 11:38:33 | zero error: +0.03kg i would subtract 0.3kg from the reading | jiahui |
7 | 1/25/2012 11:40:19 | the zero error is +0.3kg. subtract 0.3kg from the actual answer | lyyyw |
8 | 1/30/2012 14:51:59 | zero error is when there is nothing on the instrument, there is a reading on it. If the reading is on the negative scale, we should add the integer of the negative number to our reading. If the reading was positive when there is nothing on it, (excluding zero) we should subtract the integer of the reading to our actual reading to get the correct readings. Refer to : http://wiki.answers.com/Q/What_is_a_zero_error_of_vernier_caliper_and_how_can_you_remove_it for more information on zero error | >:) |
9 | 1/30/2012 15:01:29 | The actual weight=measured value-zero error. | Grimmjow |
10 | 1/30/2012 15:03:12 | et | etw |
11 | 1/30/2012 15:20:33 | The zero error occurs when the reading is not zero when nothing is measured. The actual weight for this case is = the reading - 0.3kg | Gu Erchao |
12 | 1/30/2012 15:20:39 | The reading that is recorded when nothing is being measured. In this case I would subtract 0.3kg from all readings obtained from this weighing scale. | Ee Ter |
13 | 1/30/2012 15:22:11 | This is a positive zero error. To get the accurate result, add 0.3kg to the reading you get with that weighing scale. | :) |
14 | 1/30/2012 15:25:42 | invent something that is simpler and not as complicated as the vernier caliper in terms of calculating/reading the measurement. | Derp |
15 | 1/30/2012 15:26:07 | the weighing measurement does not read zero when it is supposed to be. whatever is measured by that measurement, we can deduct 0.3 from the reading | Jenny |
16 | 1/30/2012 15:26:44 | (continued) the idea of zero error is very useful and applicable to other instruments, because the concept of positive and negative errors can be applied to any other measuring devices as well! | :) |
17 | 1/30/2012 15:27:03 | MEANS GOT GHOST! | Awesomeness. |
18 | 1/30/2012 15:28:24 | GOT GHOST )))))): | I love my mom! |
19 | 1/30/2012 15:28:38 | Subtract 0.3 after measuring your weight | thulasie |
20 | 1/30/2012 15:28:47 | Yes i think it is definitely applicable to other tools of measurement because only addition or subtraction of results is required for us to be able to get the accurate answer. | Derp |
21 | 1/30/2012 15:28:49 | Deduct 0.3kg from the weight taken in order to derive the actual weight. | Geok Xing |
22 | 1/30/2012 15:28:50 | It is also very applicable to other tools of measurement. Take the reading and add 0.3kg to get the actual reading. | Bonham Carter |
23 | 1/30/2012 15:29:23 | When other tools of measurement without a zero error are not available, we can still measure physical quantities with the one with a zero error. The accurate measurement is still given by (measured value - zero error). | Gu Erchao |
24 | 1/30/2012 15:29:24 | YES. the zero error can be taken away/ added to the weight measured. | >< |
25 | 1/30/2012 15:30:16 | Zero error is the incorrect reading that you have on the weighing scale in this case, because the weighing scale is showing 0.3kg, when it is supposed to show 0kg when no one is standing on it. To determine the actual weight for this case, you have to minus 0.3kg from the final measurement. For example, if someone is standing on the weighing scale and the weighing scale shows 45.9 kg, the person's actual weight should be 45.6kg. Thanks everybody Thanks!! :D | Bongnino |
26 | 1/30/2012 15:30:43 | The zero error in this case is 0.3kg that is the measurement displayed when there is nothing being measured | Edwin Churchill Thangaraj |
27 | 1/30/2012 15:32:20 | It alerts us that it's time to 'reset' the tool. |