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LocationOriginalReplacementCreditDatePrinting
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viDedications, viVan Damvan Damvan Dam
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xliiPreface, xliiSomasegurSomasegarvan Dam
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3Introduction, Section 1.1, page 3, last paragraphkeep a copy of Haines, Möller, and Hoffman’s book on real-time rendering [AMHH08] next to youkeep a copy of Akenine-Möller, Haines, and Hoffman's book on real-time rendering [AMHH08] next to youHaines7/19/20131
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12Page 12, start of section 1.5a nanometer is 10 x 10^-9 ma nanometer is 1.0 x 10^-9 mHughes7/19/20131
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12Page 12, start of section 1.5hair has a diameter of about 10 x 10^-4mhair has a diameter of about 1.0 x 10^-4mHughes7/15/20131
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13Page 13, topabout 6. 6 x 10^{18} visibleabout 6.6 x 10^{18} visibleHughes7/27/20131
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29p 29"pupil, and reaches the cornea.""pupil, and reaches the retina."Kiyoshi Kiyokawa, @ Osaka U.7/27/20131
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56Chapter 2, section 2.5.1, page 56: 3rd code fragment, line 2... ScaleY="0.6"... ScaleY="0.7"Sklar7/27/20131
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72p 72, Inline Exercise 3.5is (0,0), similarly .. transforms to (1, 1)is (0,1), similarly .. transforms to (1, 0)Hughes7/19/20131
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123Page 125, Figure 6.5, lower-left-vertex of triangle(250, 0, 50)(-50, 0, 50)Jesper Kristiansen1/30/20141
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165p 165, Formula 7.71-14Davide Cavignino8/8/20131
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166p 166, Figure 7.13gamma(0) and gamma(1) should be exchanged, as should eta(0) and eta(1)gamma(0) and gamma(1) should be exchanged, as should eta(0) and eta(1)Davide Cavignino, Naor Hadar9/27/20131
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167p 167, Inline Ex. 7.10 and previous linePTDavide Cavignino9/27/20131
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169p 169, formulas 7.101 and 7.102[alpha beta gamma][alpha beta gamma]^T Davide Cavignino11/10/20131
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171p 171, Figure 7.15labels in lower part of graphchange "t" to "varying t" and "s" to "varying s"Davide Cavignino1/30/20141
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171p 171, figure 7.15 caption +stC +sCDavide Cavignino12/25/20151
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179p 179, eq 7.127 and 7.128A_{xy} [in each equation] A_{yz}Hughes11/13/20131
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179p 171, eqn 7.127, 7.128, and two sentences below eqn 7.128A_xyA_yzDavide Cavignino11/25/20131
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180p 180, eq 7,130sa(T)= Azx = 1/2(azbx - axbz) + (bzcx - czbx) + (czax - azcx).sa(T)= Azx = 1/2(azbx - axbz) + (bzcx - czbx) + (czax - azcx). {i.e., add parentheses so that all three terms are multiplied by 1/2, not just the first one}Daniel Shelepov
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181p 181, line 7TT'Davide Cavignino1/27/20141
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181p 181, eqn 7.132A'_{xy} = ...A'_{xy} = \frac{1}{2} ( ... ) {i.e., insert a 1/2, and put parens around the three terms on the right hand side}Daniel Shelepov
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181p 181, eqn 7.135{entire formula}A'_{xy} = \frac{1}{2} \left( (a_x (-\tan (\theta) b_z - (\tan(\theta) a_z) b_x + (b_x(-\tan (\theta)) c_z - c_x(-\tan(\theta)b_z) + (c_x(-\tan(\theta) a_z - a_x (-\tan(\theta) c_z) \right)Daniel Shelepov
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181p 181, eqn 7.136 = - \tan (\theta) A_{zx} = \tan (\theta) A_{zx} {remove negative-sign}Daniel Shelepov
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181p 181, eqn 7.139 ... \tan^2(\theta) ... ... \tan^2 (\theta)) ... {add an extra right-paren}Daniel Shelepov
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181p 181, line -14Thus, the area of T' is |cos theta| times that of T.Thus, the area of T is |cos theta| times that of T'.Davide Cavignino11/25/20131
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185p 185, eq. 7.1431 / 3 [entry in matrix]1 / 9Hughes9/23/20131
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194p 194, line 18(3, 1); (3, 1)(3, 1); (1, 3)Davide Cavignino9/23/20131
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196p 196, line 19V-E+FV-E+TDavide Cavignino9/23/20131
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197p 197, line, 5only a single byteonly four bytesDavide Cavignino9/23/20131
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197p 197, line 6to totoDavide Cavignino9/23/20131
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197p 197, line 6be increased to roughly \lceil \log_2(\frac{3T}{2}) \rceilbe increased in proportion to lceil \log_2(\frac{3T}{2}) \rceilDavide Cavignino11/25/20131
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197p 197, figure 8.14 captionvertex a to vertex b vertex v_a to vertex v_bDavide Cavignino12/14/20131
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199p 199 Exercise 8.3<Replace entire exercise>Explain why, in a manifold surface mesh, each vertex must have at least three adjacent triangles. Hughes12/14/20131
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206p 206, line 6 of first listingmeshinterp2meshinterpDavide Cavignino9/10/20131
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215p 215, formula 9.20phi = phi = ...phi = ... Davide Cavignino9/10/20131
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216Eq. 9.24 "P = \alpha A + \beta B + \gamma B""P = \alpha A + \beta B + \gamma C"Martin Magnusson7/25/20131
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217p 217, Exercise 9.3Think about a meshThink about a manifold meshHughes7/25/20131
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220p 220, exercise 9.9(c) Explain why S S^t must be invertible.(c) Explain why S^t S must be invertible.Hughes11/26/20131
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220p 220, exercise 9.9all of parts d and e(d) Show that if $\wvec$ is a suitable vector for Equation~\ref{eq:grad-find1}, then so is $\wvec + \al \nvec$ for any $\al$, where $\nvec = \vvec_1 \cross \vvec_2$ is the triangle normal. We can therefore assume that we're looking for a vector $\wvec$ in the plane of the triangle, i.e., one that can be written as a linear combination $\wvec = \Smat \uvec$ of the vectors $\vvec_1$ and $\vvec_2$.
(e) Write $\wvec = \Smat \uvec$, substitute in the result of part b, and conclude that $\wvec = \Smat (\Smat\tr \Smat\)\inv \vect{f_1 - f_0 \\ f_2 - f_0}$. . 		Hughes11/27/20131
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235p 235, line -9columnrowDavide Cavignino12/4/20131
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244p 244, Fig 10.18, middle matrix in right-hand column1, -1, 1 entries -1, -1, 1Davide Cavignino12/4/20131
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251p 251, formula 10.101R^2 \to R^2R^2 \to RDavide Cavignino1/27/20141
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252p 252, line -13vector vvector uDavide Cavignino12/4/20131
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252p 252, near the top(AB)^T = A^TB^T(AB)^T = B^TA^TBob Zasio1 + 2
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254p 254, line -5planelineDavide Cavignino12/6/20131
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255p 255, formula 10.118S(T_M(v)S(T_M(v)) [i.e., add a close-parenthesis]Davide Cavignino12/9/20131
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255p 255, line -15radial projectionprojection from the originDavide Cavignino12/9/20131
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255p 255, line -14z = 0x = 0Davide Cavignino12/18/20131
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258p 258, formula 1.33DT(P)v = [vector]DT(p)v {delete the = sign and the vertical vector}Davide Cavignino12/18/20131
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258p 258, formula 1.342x+12x-1Davide Cavignino12/18/20131
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258p 258, formula 1.35-1 [in upper left of matrix]1Davide Cavignino12/18/20131
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258p 258, formula 1.35-s/x^2s/x^2 {in rightmost column vector, top entry}Davide Cavignino9/4/20131
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268p 268, line -16m_{21}m_{12}Davide Cavignino9/4/20131
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271p 271, line -1z = -s[1, 1]; z = s[1, 0];Davide Cavignino9/4/20131
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272p 272, lines 8, 9, 10middle, lastlast, middle (replace both occurrences)Davide Cavignino12/15/20131
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272p 272, line 10in M \approx I + sin theta J_\omegaI should be boldface, upright {i.e., identity matrix}Davide Cavignino12/15/20131
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272p 272, line 12n \times 33 \times nDavide Cavignino2/4/20141
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298p 298, Exercise 12.6a transformationa projective transformationHughes1/20/20141
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318p 318, ex 13.3 $\arctan(\frac{1}{f}}$ $2 \arctan(\frac{1}{f})$. Hughes2/15/20171
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338p 338Page 338: last paragraph “a true edge that is not on the boundary of the edge...” did you mean “boundary of the mesh”?7/30/2018
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351Equation 14.13Should be c' = f + (c - f) *e^(-dk). The book's formula has it backwards and shades nearby pixels as the fog color, blending out to no fog in the distance. I would mention that gl clamps the e^(-dk) term to [0, 1] before applying it to the formula7/30/2018
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395p 395 listing 15.4 line 8class Radiance3 Color3;typedef Radiance3 Color3;Alessandro Gentilini2/15/20171
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395p 395 listing 15.4 line 9class Power3 Color3;typedef Power3 Color3;Alessandro Gentilini2/18/20131
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413p 413 listing 15.17 line 19T.bsdf(n).evaluateFiniteScatteringDensity(w_i, w_o) *T.bsdf().evaluateFiniteScatteringDensity(w_i, w_o) *Alessandro Gentilini2/28/20141
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450p 450 exercise 15.17acupb$a \cup b$Alessandro Gentilini12/18/20131
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450p 450 exercise 15.17$A \cap B$$A \cup B$Alessandro Gentilini12/18/20131
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450p 450 exercise 15.17\textit{npt}\textit{not}Alessandro Gentilini1/2/20141
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543p 543, eqn 19.16matrixall three diagonal entries of matrix should be 9 + 8rHughes1/2/20141
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557p 557, Inline Exercise 20.3Figure 20.12Figure 20.11, top.Hughes6/9/20151
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557p 557, Inline Exercise 20.3"The answer is not ...map!"<delete>Hughes12/25/20151
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603p 603, eqn 22.22t(t - j)T(t-j)Hughes
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603p 603, equation 22.20G_B = [P_j; P_{j+1}; P_{j+2}; P_{j+3}]G_B = [P_{j}; P_{j-1}; P_{j-2}; P_{j-3}]Hughes5/3/20151
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610p 610, Figure 23.3 labeling.e_5 e_nFoley5/3/20151
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610p 610, Figure 23.4 caption.adjacent faces.adjacent faces (illustrated for case n = 5). Foley5/3/20151
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630p 630, inline exercise 24.2(1/2, 1, 1)(2, 1, 1)Hughes5/3/20151
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640p 640, inline exercise 25.5, part b25.425.3Hughes5/3/20151
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685p 685, Inline Exercise 26.90 <= x <= 10 <= x <= 1/2Hughes5/3/20151
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685p 685, Inline Exercise 26.91 < x <= 21/2 < x <= 2Hughes5/3/20151
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688p 688, Equation 26.22(x/sqrt{x^2 + z^2}, y, z/\sqrt{x^2 + z^2})(x sqrt{1-y^2}, y, z \sqrt{1-y^2})Eric Jang5/3/20151
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707p 707, eq. 26.86sin phi".sin phi.Hughes5/3/20151
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708p 708, ex 26.3 (b) Hcapital phiHughes5/3/20151
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709p 709, ex 26.10 (d)4s5sHughes5/3/20151
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709p 709, ex 26.10 (d)1%5%Hughes5/3/20151
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719p 719, first paragraph of 27.5.2, last sentence...usually write L(P, omega_o) ...... usually write f_s(P, omega_i, omega_o) ...Hughes5/3/20151
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724p 724, 3rd sentencevectors omega_ksubscript "k" should be italicHughes5/3/20151
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724p 724, 4th sentencesaying that omega_k = ...subscript "k" should be italicHughes5/3/20151
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728p 728, FIgure 27.12Label F_R on y-axisshould be R_FHughes5/3/20151
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731p 731, equation 27.36\pi(n \cdot \omega_i) (n \cdot \omega_o)(n \cdot \omega_i) (n \cdot \omega_o) {i.e., delete the \pi in the denominator of the second fraction}Martin Magnusson5/3/20151
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732p 732, line 3\alpha = \cos^{-1}(n \cdot \omega_i)\alpha = \cos^{-1}(n \cdot h) {replace omega_i with a bold h)Martin Magnusson5/3/20151
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734p 734, top{add to end of first sentence}and E_0 is the irradiance.Martin Magnusson5/3/20151
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739p 739, line 1anisotropicisotropicMartin Magnusson5/3/20151
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739p 739, 5 lines after eqn 27.45anisotropicisotropicMartin Magnusson5/3/20151
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758p 758, Section 28.6.1, first sentence"red, green, and blue are primary colors""red, yellow, and blue are primary paint colors"Rosemary Simpson5/3/20151
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758p 758, Section 28.6.1, second sentenceAnyone who has tried to make orange from red, green, and blue paint knows this is false.Anyone who has tried to make saturated green from red, yellow, and blue paint knows this is false.Rosemary Simpson5/3/20151
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758p 758, Section 28.6.1, first paragraph<add sentence at end>Similar claims hold for red, green, and blue "primary" light colors. Rosemary Simpson5/3/20151
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780p 780, Exercise 28.1YIQ <appears twice>XYZ <both times>Hughes5/3/20151
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780p 780, Exercise 28.1"is more naturally related to the human eye""is more fundamental"Hughes5/3/20151
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815p 815, Listing 30.3, line 1"point3 = randhemi()""Point3 cosRandHemi()"Hughes5/3/20151
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823p 823, Exercise 30.10b - a < 1/Mb - a <= 1/MHughes5/3/20151