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Seeking a formula for how vapor retarders affect mold risk, I ended up converting a printed spreadsheet into a functioning spreadsheet - almost.
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The source calculates vapor pressure and condensation through a wall.
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How were the highlighted-yellow parts calculated? .... The blue font parts (+two formulae images on line 13) were added by me. Black is identical to the source. Italics means now calculated (vs just printed).
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(If you want the source, it's "Vapour Pressure and Condensation", in Canadian Building Digest.)
https://nrc-publications.canada.ca/eng/view/ft/?id=897fca5e-67e2-46e0-9e83-c2c456faadf1
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"Consider a wall of 4-inch reinforced concrete with an inside finish of winch plaster over 1 inch of foamed plastic insulation that separates
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an internal environment of 73°F and 35 per cent RH from an outside environment of 0°F and 80 per cent RH.
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The actual vapour pressures are, respectively, 0.818 x 0.35 = 0.286 in. Hg and 0.038 x 0.80 = 0.030 in. Hg, and the total pressure difference is 0.256 in. Hg."
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Interior Temp73°F22.8°C
Exterior Temp
0°F-17.8°C
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Interior RH35%
Exterior RH
80%
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Saturation Vapor Pressure0.818in.Hg2.7743
kPa, by Buck Approximation
Saturation Vapor Pressure
0.038in.Hg0.1275kPa
by Huang, sub-zero version
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0.8193
by converting kPa to in.Hg (inches of mercury)
0.038
by converting kPa to in.Hg
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Buck Approximation
Huang Approximation
0.1517kPa
by Buck, not right for sub-zero
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sub-zero-°C version
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The pressure difference must be apportioned among the various components of the envelope in proportion to their resistance to vapour flow.
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Table I. Tabulated Vapour and Temperature Calculations
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InteriorAir FilmPlaster
Insulation
Concrete
Air FilmExteriorTotal
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Thickness n-0.7514
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Permeance M-15---
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Permeability µ--1.63.2-
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Vapour Resistance 1/M , n/µ0.070.631.251.94
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% of drop0%3.43%32.19%64.38%0%100%
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Vapour Pressure Drop for Continuity (in.Hg)
00.0090.0820.16500.256
(row calculated by either (1) measuring the interior and exterior actual vapor pressures, then multiplying the difference by the % of resistance at that layer, or (2) as some unit conversion from line 22 (dividing line 22 by 7.58 matched the printed #s in line 24)
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Vapour Pressure for Continuity ("pc") (in.Hg)
0.2860.2860.2780.1950.0300.030
Vapour permeability can be expressed in several ways:
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- vapour resistivity of a material, measured in GNs/kgm (giga Newton seconds per kilogram metre) or MNs/gm (mega Newton seconds per gram metre)
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Thermal Conductance C1.466.66--6
- vapour resistance for a given thickness of material, in GNs/kg or MNs/g
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Thermal Conductivity k--0.2512-
- vapour resistance factor, also known as th µ-value, which is the resistivity of a material relative to that of still air. It is a factor, and has no units.
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Thermal Resistance 1/C , n/k0.680.154.000.330.175.34
- "perms", short for permeability, used commonly in North America, measured in grains/(ft2 ·h·inHg)
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Temperature Drop °F92555273
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Temperature °F736462720
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Temperature °C22.817.616.4-14.0-16.5-17.8
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Saturation Vapor Pressure 2.7743kPa2.01001.86970.18160.14360.1275
* intermediary calculation in kPa to get to source's unit (inches of mercury, in.Hg)
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Saturation Vapour Pressure ("ps")0.819in.Hg0.5940.5520.0540.0420.038
(calculated matches printed)
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Actual Vapour Pressure ("pa") 0.287in.Hg0.2860.2640.0540.030.030
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Actual Vapor Pressure (calc'd: SVP x calculated-RH)
0.287in.Hg0.20774779140.1932395120.018764485310.014845003920.01318083873
How did they calculate mid-assembly RH? My calc's in this row don't match the printed data (the row above) because I can't properly calculate mid-assembly RH.
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Actual Vapor Pressure (calc'd: SVP x given-RH )
0.287
(RH not given)
(RH not given)
(RH not given)
(RH not given)
0.030
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Vapour Flow = Vapour Pressure Difference / Vapour Flow Resistance
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The vapour flow to point A is
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(0.286 - 0.054) /
(0.07 + 0.62)
0.2860.0540.2320.34grain / sq ft / hr
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0.070.630.69
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and that from point A
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(0.054 - 0.030) /
1.25
0.0540.0300.0240.02grain / sq ft / hr
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1.251.25
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giving a condensation rate of
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0.34 - 0.02 = 0.32 grain/sq ft/hr.
Condensation Rate:
0.32
grain / sq ft / hr
1 perm = 1 grain/(hr ft2 inHg)
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Does knowing the condensation rate enable us to factor vapor pressure into calculations of relative humidity?
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* How did they calculate "Actual Vapor Pressure"?
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The paper only includes RH inside and outside - it does not include RH (or dewpoint) mid-assembly.
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Actual Vapor Pressure can be calculated from RH and Temperature. RH can be calculated from Dewpoint and Temperature, but Dewpoint is calc'd from RH and Temp, so: circular reasoning.
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Temperature °C22.817.616.4-14.-16.5-17.8
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Dewpoint6.51.90.9-26.2-28.4-29.6
formula source: https://bmcnoldy.rsmas.miami.edu/Humidity.html
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r.h.35.0%35.0%35.0%35.0%35.0%35.0%
formula source: https://bmcnoldy.rsmas.miami.edu/Humidity.html
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Dewpoint (by sub-zero version of formula)
8.53.82.8-25.-27.3-28.4
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r.h. (by sub-zero version of formula)35.0%35.0%35.0%35.0%35.0%35.0%
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r.h. (given)35.0%80.0%
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Why are the r.h. calculations all 35% at every point of the assembly? Circular reasoning / calculating.
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I used the same indoor RH for the Dewpoint calculations at every point of the assembly. Was there a now-forgotten good reason for that?
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About the formula for "Saturation Vapor Pressure":
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Psat in kPa and T in °C. Where A, B, and C are the coefficients of the August-Roche-Magnus approximation.
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For above-zero temperatures, A = 6.112, B= 17.625 and C= 243.04.
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For sub-zero temperatures, A = 6.112, B=22.46 and C=272.62.
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Psat2008 EVAL [ 6.112 * EXP(17.62*Temperature/(243.12+Temperature)) ]
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PsatSub0 EVAL [ 6.112 * EXP(22.46*Temperature/(272.62+Temperature)) ]
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-- https://cumuluswiki.org/a/Charts_Definition_Language_(CDL)
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Where A = 6.1094, B= 17.625 and C= 243.04 are the coefficients of the August-Roche-Magnus equation as found here. Psat in hPa and T in °C
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