Estimating fF - Iterative procedure

	A	B	D	E	F	G	H
1	Estimation of the friction factor fF
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3	Here, the Colebrook equation is to be solved iteratively
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8	This process requires to rewrite Colebrook's equation as follows
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16	Data		Iterative calculations
17			Iteration #	fF guess	fF new	% error
18	Kinematic viscosity, m2/s	0.56	1	0.005	0.06061541634	91.75127335
19	Pipe inside diameter, m	0.1	2	0.06061541634	0.045732418	32.54365065
20	Fluid velocity, m/s	30000	3	0.045732418	0.04678342787	2.246543098
21	Pipe roughness, m	0.001	4	0.04678342787	0.04669415954	0.1911766542
22	Reynolds number	5357.142857	5	0.04669415954	0.04670163191	0.01600023368
23			6	0.04670163191	0.04670100565	0.001340991734
24	Result		7	0.04670100565	0.04670105813	0.0001123763486
25	Friction factor	0.04670105407	8	0.04670105813	0.04670105373	0.000009417334625
26	% error	0	9	0.04670105373	0.0467010541	0.0000007891884583
27			10	0.0467010541	0.04670105407	0.00000006613531896
28			11	0.04670105407	0.04670105407	0.000000005542238404
29			12	0.04670105407	0.04670105407	0.000000000464449655
30			13	0.04670105407	0.04670105407	0
31			14	0.04670105407	0.04670105407	0
32			15	0.04670105407	0.04670105407	0
33			16	0.04670105407	0.04670105407	0
34			17	0.04670105407	0.04670105407	0
35			18	0.04670105407	0.04670105407	0
36			19	0.04670105407	0.04670105407	0
37			20	0.04670105407	0.04670105407	0
38			21	0.04670105407	0.04670105407	0
39			22	0.04670105407	0.04670105407	0
40			23	0.04670105407	0.04670105407	0
41			24	0.04670105407	0.04670105407	0
42			25	0.04670105407	0.04670105407	0
43			26	0.04670105407	0.04670105407	0
44			27	0.04670105407	0.04670105407	0
45			28	0.04670105407	0.04670105407	0
46			29	0.04670105407	0.04670105407	0
47			30	0.04670105407	0.04670105407	0	<< RESULT
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