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. | 8/30/2011 21:24:30 | Nicole Price | 5.1 | 8 | The solution for Example 6, Problem (b) | It says that the graph of y= lnx is on the right when it's actually the leftmost graph. | x |

. | 8/31/2011 9:46:17 | Laura Taalman | 5.1 | 12 | Problem 32 | This has a variable so will not be a "value". Change problem to some other fun thing like 2^{1 + 3 \log_2 1} | x |

. | 8/31/2011 21:00:33 | Elizabeth Williams | 5.1 | 7 | Solution to problem (b) in Example 4. | It says log sub 6 3 is the exponent to which we would have to raise 6 to get 2, but it is supposed to be the exponent to which we would have to raise 6 to get 3. | x |

. | 9/1/2011 15:58:02 | Alex Jusell | 5.2 | 16 | In theorem 5.12, a) | at the end of part a) the limit should equal negative infinity, not infinity | x |

. | 9/1/2011 22:53:46 | Irene | 5.1 | 10 | Typo for answer to problem 1 | it just says xxxxxx | x |

. | 9/6/2011 11:06:28 | Allison Welborn | 5.3 | 30 | Example 2, Solution a. | It says to use the product rule in the third step to take the derivative but they use a minus sign instead of a plus sign. | x |

. | 9/6/2011 15:57:23 | Alex Jusell | 5.4 | 41 | In the chart on the top half of the page | The wrong number is used in the "every minute" row and the "times compounded" column. It should be compounded 525,600 times, not 1,314,000 times. | x |

. | 9/6/2011 20:28:27 | Nicole Price | 5.3 | 29 | Solution to Example 1c | The first sentence ends with a parenthesis even though there was no other parenthesis in the sentence. | x |

. | 9/7/2011 13:07:56 | Kate Reiman | 5.4 | 46 | The first question in the Questions section | The question asks "In the potato pile example at the start of this section, does the linear model does not grow by the same percentage...?" It should just be "...does the linear model grow by the same percentage..?" | x |

. | 9/7/2011 23:44:24 | Anne Hurst | 5.5 | 54 | End of the first sentence of page 54. | The end of the sentence says "..... domain restrictions will ensure that this is always be the case." It should say ".... domain restrictions will ensure that this will always be the case." | x |

. | 9/8/2011 23:24:37 | Sarah Brown | 5.4 answer appendix | answer appendix, no page number | below problem 39 until section 5.5 | answer key is provided for even problems 40-66, not odd problems | x |

. | 9/9/2011 9:12:03 | Amanda Wright | 5.3 Answers | 3rd page of answers | bottom right column | there is no answer present for number 93 of section 5.3 in the Answers section | x |

. | 9/9/2011 9:56:25 | Amanda Wright | 5.4 answers | 4th page of answers | towards bottom left hand column | for answers number 39 of 5.4 the exponents in the answer are typed like constants | x |

. | 9/15/2011 9:32:11 | Kate Reiman | 5.5 | 59 | Statement before problems 53-62 | You said it would be less confusing if you changed either the questions or the statement to lim as x->infinity u(x)/v(x) = infinity. | x |

. | 9/15/2011 9:33:55 | Kate Reiman | 5.5 | 59 | Problem 67 | You said if the problem were changed to lim as x->infinity (1/2)^x(x^100) it would be a better problem. | x |

. | 9/16/2011 10:29:24 | Amanda Wright | 6.1 answers | 3rd page of answers | Bottom left column of answers | #47 should be(-sqrt2/2,-sqrt2/2) #73 doesn't have an answer, should be 2pi/3k | x |

. | 9/17/2011 16:42:41 | Dorottya Boisen | Chapter 5 review | No pg#, but would be pg62 | Limits of Exponential and Logarithmic functions | "If k>0, then lim as x approaches negative infinity of e^(-kx)" is written twice. One of the fill-in-the-blanks should be the limit as x approaches negative infinity of e^(kx). | x |

. | 9/17/2011 16:48:39 | Dorottya Boisen | 5.5 Answers | No pg # | Answer to question 57 | Answer says that "the limit as x approaches infinity of (e^x)/(2^x)= infinity" However, the answer should be for the quotient of (2^x)/(e^x). | x |

. | 9/19/2011 17:58:34 | Dorottya Boisen | 6.2 | 82 | Proof of Theorem 6.6 | Unit circle shows angle theta and -theta. The x and y co-ordinates for angle -theta should both be negative. Currently it is (x, -y), but the lower left quadrant has negative values for both x and y, so it should be (-x,-y). | x |

. | 9/21/2011 17:18:41 | Anne Hurst | 6.3 | 92 | third paragraph, third sentence. | it says " Now by applying the Squeeze Theorem the the double inequality...." there should only be one "the." | x |

. | 9/22/2011 10:29:08 | Mason Moomaw | 6.2 | 85 | Last sentence in the answer to example 2. | The solution shows that the answer is -f(x), making it an odd function. But in the next sentence it says "since f(-x)=f(x) for all values of x in its domain, we can say that f(x) is odd." It should say, "Since f(-x)= -f(x) for all values of x in its domain, we can say that f(x) is odd. | x |

. | 9/22/2011 18:12:21 | Alex Smyth | 6.2 # 61 and 63 Answers | p. 89 | second column half way down the page | The Answer for # 61 and 63 is blank | x |

. | 9/22/2011 19:57:10 | Maile Wood | 5.4 | 41 | In the table of compounding interest | shouldn't the last column be titled "balance after 5 years"? t seems to be 5 in each example as in every other example given up to that point. | x |

. | 9/22/2011 21:15:54 | Alex Smyth | 6.2 | 85 | fourth line. | The book shows that sin(pi/4)cos(pi/6)-sin(pi/6)cos(pi/4) = (sqrt2/2)(sqrt3/2)-(1/2)(1/sqrt2) I believe the (1/sqrt2) should be sqrt2/2 because cos(pi/4)=sqrt2/2 | x |

. | 9/22/2011 22:11:01 | Alex Smyth | 6.2 | 85 | Solution for example 2 | The last line says that Since f(-x) = f(x) then f(x) is odd. The negative sign is missing from the f(x) | x |

. | 9/28/2011 15:09:12 | SaraKate Rohloff | Answers of 7.1 | Back of the book | Answer to number 33, the second line. | two addition signs "0.18166+ +0.18439" | x |

. | 9/29/2011 22:19:43 | Marjorie Riddle | 6.4 | 109 | Example 4, problem b | The problem says to differentiate xcos-1(3x+1) but the explanation differentiates xsin-1(3x+1) | x |

. | 10/3/2011 1:32:23 | Varqa Tavangar | 7.2 | 139 | second sentence of the Technical Point part. | "...recall that the terms in a Riemann sum must of the form..." There is a 'be' missing between 'must' and 'of'. | x |

. | 10/4/2011 16:28:18 | Anne Hurst | 7.3 | 150 | second paragraph under theorem 7.10 | It says, " .....of the definite integral, but instead we present instead a..." It should say " of the definite integral, but instead we present a" | x |

. | 10/9/2011 21:00:44 | Anne Hurst | 7.4 | 161 | the last sentence of the first paragraph. | It says "In such cases will have to split up the interval....." It should say "In such cases we will have to split up the interval...." | x |

. | 10/9/2011 21:30:40 | Anne Hurst | 7.4 | 163 | second paragraph, second sentence. | It says " ..... The cross-section of a wave of water, as if are looking at water sloshing....." It should say " .....The cross-section of a wave of water, as if we are looking at water sloshing...." | x |

. | 10/10/2011 9:53:35 | Isabelle Masters | 7.4 | 159 | last sentence of the second paragraph | One of the numbers in the Left Sum equation is missing a decimal point. It says "01875" but it should be "0.1875". | x |

. | 10/13/2011 20:46:33 | Evan Bryant | 7.4 | 167 | Problem number 5, fourth and fifth line | The error is "Will the unsigned are will be positive or negative, and why? Will the signed area will be positive or negative, and why?" and it should read, "Will the signed/unsigned area be positive or negative, and why?" | x |

. | 10/13/2011 20:49:59 | Varqa Tavangar | 5.1 | 8 | Solution to Example 6(a) | in the third line, y-axis should be x-axis. | x |

. | 10/14/2011 10:16:13 | Amanda Wright | 7.4 | 170 | first problem on page, number 58 | There is no question to be answered | x |

. | 10/26/2011 13:58:57 | SaraKate Rohloff | 8.3 | 222 | Directions and problems 35-48 | I met with you during office hours and the directions were unclear with respect to what was written for the problems. the beginning problems (35-42 and 46-48) should have d/dx and #43-45 should be double derivatives. | x |

. | 11/2/2011 21:44:27 | Dorottya Boisen | 9.3 | 256 | Example under Theorem 9.13 about completing the square | Text says that quadratic function x^2 + 6x + 10 has b=4, but b=6. | x |

. | 11/2/2011 21:49:19 | Dorottya Boisen | 9.1 | 233 | Theorem 9.5 | Evaluation notation has a mix up- it says [G(u)] from u(b) to u(a). It should be the other way around. | x |

. | 11/2/2011 21:57:55 | Dorottya Boisen | 7.4 Answers | no page number | Question 43 Answer | Delta x is said to be 1/8, and it should be 1/4. The answer to the problem is about 0.990978, and it should be around 2.0173-ish. | x |

. | 11/7/2011 10:03:36 | Maile Wood | 9.4 | 268 | In the table of rewritten forms and u substitutions | In the first example under the choose category: it says "u = cos x, du = sin x dx" but it should say "du = -sin x dx" | x |

. | 11/7/2011 10:10:00 | Maile Wood | 9.4 | 268 | In the table of rewritten forms and u substitutions | In the second and third examples under the choose category: "dx" is missing at the end of the du. | x |

. | 11/9/2011 20:45:22 | Dorottya Boisen | Answers to 9.4 | no page number | answer to question 41 | answer should be 1/4x - 1/8x - 1/96 sin 12x + C | x |

. | 11/9/2011 21:02:49 | Dorottya Boisen | 9.4 Answers | no page number | Answer to question 35- suggestion | Book says to use parts with u= csc^2 x and dv= csc^2 x dx, the use u substitution later. It is much simpler (and more intuitive) to split the integrand into (csc^2 x) (csc^2 x), then re-write as (csc^2 x) (1+ cot^2 x), then use u substitution where u= cotx and du= -csc^2 x dx. | x |

. | 11/13/2011 15:21:57 | Dorottya Boisen | 9.6 | 293 | Definition 9.18, (c) | If f is continuous on (neg inf, inf), split it up into two at any real number c: Integral from (-inf) to (inf) of f(x) dx = Integral from (-inf) to (c) of f(x) dx + Integral from (-inf) to (c) of f(x) dx Last integral in definition should be Integral from (c) to (inf) of f(x) dx | x |

. | 11/28/2011 8:25:04 | Dorottya Boisen | 10.1 | 312 | Paragraph under figures, 4th sentence | "The heights of rectangles in the the middle figure..." 'the' is written twice | x |

. | 11/28/2011 8:32:55 | Dorottya Boisen | 7.4 | n/a | n/a | You mentioned in class that you think the words 'signed' and 'unsigned' are confusing, and said to make note of it on the errata list. | x |

. | 12/1/2011 23:56:10 | Ethan Blackwell | 10.1 | 314 | Definition 10.2 second sentence. | Just a typo, it says "given by a continuous funtion r=r(x) on [a,b]" the correction is just to put the c in function. | x |

. | 12/8/2011 18:41:35 | Varqa Tavangar | 5.3 | 30 | Solution (a) it says "so we begin APPLING the quotient rule". | it should say APPLYING the quotient rule. | x |

. | 12/9/2011 11:08:49 | Mason Moomaw | 5.4 | 44 | The first big paragraph in the answer to example 2. The one starting with "The equivalent continuous growth rate..." | In the second sentence of the paragraph it says, "...we can always convert form exponential functions in the form..." It should say "...we can always convert from exponential functions in the form..." | x |