For the half wave rectifier shown, where vI = 120 Vrms, and R = 50 Ω.
Assume Vγ = 0.6 V.
Answers:�i) Peak output voltage is 41.83 V�ii) 35 W
A half-wave rectifier is used to supply a 5 V peak output voltage to a resistive load of 800 Ω.
The diode has a turn on voltage of Vγ = 0.7 V and a resistance, rf of 25 Ω.
Answers:�i) vs = 5.86 sin ωt�ii) 46.2 %
iii) 5.86 V
For a half-wave rectifier circuit, the output voltage across a 2 kΩ load resistor is 30.72 V. The diode has a turn on voltage of Vγ = 0.7 V.
Answers:�i) 10:1
ii) 31.42 V
A full-wave center tapped rectifier uses two diodes, the internal resistance of each diode may be assumed to be constant at 20 Ω with Vγ = 0.65 V . The transformer’s rms secondary voltage is 50 V and load resistance is 980 Ω.
Answers:�i) 70 mA�ii) 99.4 %
A full-wave rectifier circuit uses diodes, with Vγ = 0.65 V . The transformer’s rms primary voltage is 220 V and turns ratio, N1:N2 = 20:1.
Answers:�i) 9.94 mA�ii) 30.46 V
In the bridge rectifier circuit shown above, the diodes are assumed have a turn on voltage of Vγ = 0.7 V. The primary to secondary turns ratio is given as 4:1. Find
(rms)
Answers:�i) Vopeak = 80 V�ii) 80.6 V
A bridge rectifier circuit with a filter capacitor has RL = 0.1 kΩ. The secondary transformer delivers an input voltage, vs of 15 V (rms) and has a frequency of 60 Hz. Assume that the diodes have turn-on voltage of 0.7 V each.
AC Line
Voltage
Answers:�i) 198.13 mA�ii) 3.3 mF
Answer:�15.5 ≈ 16:1
A full-wave bridge rectifier circuit with a capacitor filter is designed to meet the following specifications
If the transformer input AC voltage, vp is 120 V (rms) at 60 Hz
Assume that the diodes has the turn on voltage of 0.7 V and rf = 10 Ω
N1: N2
+
VO
-
+
vP
-
+
vs
-
Answers:�i) 13:1
ii) 11.74 V�iii) 23.48 kΩ and C = 20.83 μF
Answers:�i) IZ = 0.088 A, IL = 0 A, VL = VZ = 5.6 V�ii) IZ = 0.1656 A, IL = 0.0224 A, VL = VZ = 5.6 V
Consider the circuit shown below. The Zener diode voltage is VZ = 3.9 V
Determine IZ , IL , and the power dissipated in the diode
Answers:�IZ = 0.367 mA, IL = 0.975 mA,
PZ = 1.43 mW
A 5.0 V stabilized output voltage, VL is required to be produced across a 0.2 kΩ load from a 12 V DC power supply input source. The maximum power rating PZ of the Zener diode is 2 W. Using the voltage regulator circuit, if the Zener diode is dissipating the maximum power calculate:
Answers:�i) IZ = 0.4 A�ii) Ri = 16.47 ohm
A voltage regulator circuit is shown below where a 10 V Zener diode is connected across a 1 kΩ load. The input voltage source VPS = 18 V and a series resistor Ri is connected to limit the Zener diode current.
Determine the value of Ri required to make the current IZ = 20 mA.
Answer: Ri = 266.67 ohm
Design the voltage regulator circuit illustrated below using the specifications given
Answer: Ri = 1.3 k-ohm
Assume IZ (min) = 0.1 IZ (max).
Answers:
Ri = 8.08 Ω
PZ = 11.9 W