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Mathematics -Class XII

Unit III -Calculus

Chapter VII -Integrals

Topic -Definite Integrals

Sub Topic -Definite Integral as

the Limit of a Sum –

Definition and proof

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Outline:

  • Definition
  • Integral as the Limit of a sum –proof
  • Example with solutions
  • Assignment I
  • Assignment II

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DEFINITE INTEGRAL

AS THE LIMIT OF SUM

(PART-I)

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DEFINITION

Let f be a continuous function defined on the closed interval [a, b],

  • Let a = x0 < x1 < x2 , … < xn – 1 < xn = b .

  • Divide [a,b] into n parts with width h=(b-a)/n.

As n ∞

is called definite integral of f from a to b.

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The definite integral

is the area bounded by the curve

y= f(x)., the ordinates x=a , x=b and the x-axis

To evaluate this area , consider the region PRSQP between the curve, x-axis and the ordinates at x=a and x=b.

Y

0

X

Q

P

R

S

x=a

x=b

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Divide the interval [a,b] into n equal subintervals denoted by

Y

0

X

Xn=b

X0=a

X1

X2

X3

xr-1

xr

Q

P

R

S

A

B

L

D

M

C

[x0,x1],[x1,x2],….[xn-1,xn] , where x0=a, x1=a+h, x2=a+2h…, xr=a+rh , r=1,2,3,…n

and xn=b=a+nh, or h= (b-a)/n. Also as

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The region PRSQP under consideration is the sum of n sub regions where each sub region is defined on the subintervals [xr-1,xr], r=1,2,3,…n. hence from fig.

Area of the rectangle (ABLC)<area of the region (ABDCA)< area of rectangle(ABDM )

Y

0

X

A

B

L

C

M

D

xr-1

xr

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As xr-xr-1 0,i.e ,h 0 the three areas are nearly equal .

Here sn & Sn are sum of the areas of all lower rectangles and higher rectangles over subintervals [xr-1,xr], r=1,2,3,…n.

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Therefore sn<area of the region PRSPQ<Sn

or

As , all the three areas are equal

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Applications

  • Evaluate: as limit of a sum?

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Ans.

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SOLUTION BY SECOND FORMULA

Here a=0, b=2 , h=2/n

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Solution contd…

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