Bell Ringer – February 2nd
r ≥ 10
p ≤ 5
x < 2
Domain 3 Test
Lesson 27
Finding the Area of Triangles and Quadrilaterals
Bell Ringer – February 3rd
15 + n
20 – n
10 ÷ n
3n
4(n + 5)
Vocabulary
Area
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4 units
6 units
Area = 24 square units
Area of a Parallelogram
A = bh
3 cm
5 cm
4 in
7 in
15 cm2
28 in2
Area of a Triangle
A = ½ bh
4 in
3 in
5 cm
4 cm
A = ½ (4)(3)
A = 2(3)
A = 6 in2
A = ½ (4)(5)
A = 2(5)
A = 10 cm2
Homework
Bell Ringer – February 4th
a. b.
7 cm
5 cm
6 cm
4 in
8 in
5 in
A = ½ (5)(6)
A = ½ (30)
A = 15 cm2
A = (4)(8)
A = 32 in2
Find the area of the trapezoid
4 yd
5 yd
8 yd
6 yd
Area1 = ½ (4)(5)
Area1 = 10 yd2
Area2 = (8)(5)
Area2 = 40 yd2
Area3 = ½ (6)(5)
Area3 = 15 yd2
Total Area = 10 + 15 + 40
Total Area = 65 yd2
1
2
3
Find the total area of the garden below
14 ft
12 ft
10 ft
Area of parallelogram
A = bh
A = (14)(12)
A = 168 ft2
Area of triangle
A = ½ bh
A = ½ (14)(10)
A = 70 ft2
Total Area = 168 + 70
Total Area = 238 ft2
Homework