There are 7 periods or horizontal rows in the periodic table. i) The first period is made up of with only 2 elements namely, hydrogen and helium.
ii) The second period contains 8 elements, starts with lithium and end with noble gas neon.
iii) The third period also contain 8 elements begin with sodium and end with argon.
iv) The fourth period is having 18 elements, begins with alkali metal Potassium and end with krypton.
v) The fifth period like fourth period also contain 18 elements. It begins with rubidium and end with xenon.
vi) The sixth period is a long period having 32 elements. This period includes 8 normal elements, 10 transition elements and 14 rare earth elements.
vii) Seventh period also contain 32 elements.
Definition: The recurrence of similar properties of elements after certain intervals when they are arranged in the order of increasing atomic number is called periodicity.
1) s – Block Elements :
Definition : The elements whose atoms receive the last electron in the s- orbital of their outermost sub- orbital are called s block elements. Or The elements in which the last electron enters in the s- orbital of their outer most energy level are called s- block elements.
Definition : The elements in which the last electron enters in the p- sub shell of their outermost energy level are called p- block elements.
2) Second transition series (4d-series) :
3) Third transition series (5d Series) :
4) Fourth transition series (6d- series) :
4) F-block elements :
Definition : The elements in which the last electron enters in (n-2)d i.e. last but two or anti penultimate sub shell are called f- block elements.
i) Lanthanide series or (4f-series) :
3) General characteristics of d-block elements :
B) Periodic properties:
i) Atomic radius/ Atomic size/ Atomic radii :
Definition: It is defined as the distance from centre of nucleus up to the last orbital in which electron is present. OR
“ The distance from the centre of nucleus to the point where the electron density is effectively zero.”
Explanation : i) An atom is composed of a compact nucleus surrounded by electron cloud
ii) Which does not have a sharply defined boundry because of its diffused nature
iii) The diffused nature of the electron cloud make it difficult for us to give an exact definition of atomic radius
iv) It is not possible to determine the exact radius of atom because
b) Ionic radius :
Definition : “ It is the effective distance from the centre of nucleus of an ion upto which it has its influence on its electron cloud.”
Explanation : i) A cation is always much smaller than the corresponding atom
ii) If further, more number if electrons are removed, smaller will be the size of resulting cation. For. Ex. rFe > rFe+2 > rFe+3
1.26 0.76 0.64
This is due to –
iii) A cation formed by the loss of electron may result in the complete disappearance of the shell. Thus the cation is much smaller than the atom.
For. Ex.
Na Na+
(2 , 8 , 1 ) ( 2, 8 )
iv) As a result the effective nuclear charge is increased and electrons are pulled towards nucleus.
hence, the cation becomes smaller.
v) On the other hand an anion is always larger than the corresponding atom.
For. Ex. Atomic radius of I atom = 1.23
Ionic radius of I- ion = 2.16
vi) The ionic radius is measured with the help of X-ray diffraction method. It is measured in A0 .
C) Covalent radius :
Definition : It is defined as one half of the internuclear distances (i.e. bond distance or bond length) between the centers of two nuclei of two similar atoms bonded together by a single covalent bond.
Explanation : i) According to definition it is assumed that atoms are incompressible spheres touching to each other in normal covalent
bonds formed.
ii) However, atoms are neither fully incompressible nor do they touch each other in a covalent molecule.
iii) Therefore, the covalent radii calculated on the basis
of above definition cannot be regarded as exact.
iv) Covalent radius can be measured by X- ray diffraction or spectroscopic studies.
v) It is measured in the unit A0 .
rA = Bond length /2
For.Ex. 1) If the bond length of hydrogen molecule is 0.74 A then what will be the covalent radius of hydrogen atom.
rH = Bond length/2 = o.74/2 = 0.37
2) Covalent radius can be used for the calculation bond length of hetero atomic molecule by using
Bond length of A.B = rA + rB = dA2 + dB2/ 2
Ex. 2) Covalent radius of C is 0.77 and C-H bond length in CH4 is 1.14. What is the covalent radius of hydrogen.
1.14 = rH + 0.77
rH = 1.14 - 0.77
= 0.37A0
3) However, if atoms forming the covalent bond are hetero atoms i.e. one is more electronegative than other then the covalent radius is determined by the following equation.
A – B = rA + rB - 0.09 ( XA - XB)
where, XA and XB are electronegativities of the atoms A and B.
For Ex.
D) Van der waal’s radius :
Definition : It is defined as- “One half of the distance between the nuclei of two identical atoms belonging to two neighbouring molecules of an element in the solid state”.
Explanation:
adjacent molecules of an element in solid state
approach each other without overlapping their
electron clouds to form a bond between them.
ii ) They cannot come closer than a minimum
distance without forming a bond.
iii) This minimum distance is called van der wall’s
distance and half of this distance is called van
der wall’s radius.
iv) The name van der waal’s radius is used because the forces existing between the molecules are the van der wall’s forces of attractoin.
v) These forces are maximum in solid states and absent in gaseous condition while in liquid state is very small.
vi) Therefore, van der wall’s radius is determined only in solid state
vi) The van der wall’s radii is also known as non-bonded radii
vii) The van der wall’s radius is determined by X- ray diffraction studies
viii) van der wall’s radius is always greater than the covalent radius
xi) The noble gases do not form covalent bonds. Thus for noble in solid state have van der wall’s radii
a) Variation along the Periods: Atomic size/radius decreases on moving from left to right in a period.
b) Variation down the groups: Atomic size/radius increases from top to bottom within a group of periodic table.
b) Ionization energy/ Ionization potential :
Definition: Ionization energy of an element is defined as- “ The amount of energy required to remove the most loosely bound electron from isolated neutral gaseous atom in its ground state to produce a cation”.
Exlpanation : Lets consider the general reaction-
M(g) + Energy M+(g) + e-
Isolated gaseous
atom
1 eV/atom = 96.4705 KJ/mole = 23.06 Kcal/mole
1 Kcal/mole = 4.185 KJ/mole
M(g) + Energy M+(g) + e- (IE1)
M+ + Energy M2+ + e- (IE2)
M2+ + Energy M3+ + e- (IE3)
a) Atomic size :
i) Greater the size of an atom, the smaller is ionization energy. This is because as the size of atom is increases, the outer shell electron far away from the nucleus.
ii) Thus the size of atom increases, the force of attraction on the electron decreases.
iii) Hence, less is the energy needed to remove the electron. Therefore IE decreases with increase in atomic size/ atomic radius.
b) Effective Nuclear Charge :
i) The force of attraction between the nucleus and the outermost electron increases with increase in nuclear charge.
ii) Thus, greater the nuclear charge, the greater is the energy needed to pull out an electron from the atom.
iii) Hence, IE increases with increase in nuclear charge.
C) Screening/ shielding effect :
i) The electrons present in valence shell of am atom are attracted by the nucleus due to nuclear charge
ii) The force of attraction also depends on the distance between the nucleus and valence shell electron and also on the inner shell electrons.
iii) These inner shell electrons exert a force of repulsion on valence shell electrons.
iv) Thus inner shell electrons acts as a screen / shield between nucleus and valence shell electrons.
v) Hence, these outer electrons feel lesser nuclear charge is denoted with Zeff.
vi) Thus, if screening effect increases, Zeff decreases, force of attraction on valence shell electron decreases.
vii) Thus, IE decrease with with an increase in number of inner electrons i.e. screening effect.
d) Half filled and completely filled orbitals :
i) According to Hund’s rule, half-filled (ns1, np3 , nd5) and full-filled(ns2,np6,nd10) orbital’s are comparatively more stable.
ii) Hence, more energy is needed to remove an electron from such orbitals.
iii) This maens that the IE of an atom having half-filled or completely -filled orbitals in its electronic configuration is relatively higher than that expected normally from its position in the periodic table.
For.Ex. Be4 = 1s2 2s2 has extra stability due to completely filled 2s sub-shell
i) We well know that, the s- orbital electrons are closer to the nucleus than the p ,d or f electrons.
ii) Thus, the s orbital electrons experience more attraction towards nucleus than the p, d or f orbital electrons.
iii) Therefore, the energy required for pulling out an s orbital electron is maximum and it decreases in pulling out p, d and f orbital electrons.
iv) Thus, the probability of finding/penetrating electrons near the nucleus follows the following order.
s > p > d > f
i) increase in nuclear charge
ii) There is a gradual decrease in atomic size and
iii) Increase in screening effect due to number of inner electrons
i) Successive increase in nuclear charge
ii) Decrease in atomic size
1) Nature of elements : Elements having lower IE are metallic in character and of higher IE are non-metallic in nature.
2) Reactivity : Elements with lower IE are more reactive where as higher
IE are less reactive.
3) Reducing Power : Lower the value of IP of an element, greater is its
reducing power.
4) Basic character of the element : Lower the value of IP of an element,
the grater will be basic character.
C) Electron Affinity/ Electron Gain Enthalpy (EA / egH)
Definition : “ The amount of energy released in adding an extra electron from outside to an isolated gaseous atom in its in its ground state to convert it into a gaseous anion is known as electron affinity.”
Explanation : Thus electron affinity of an atom M(g) can be defined by the following process :
M(g) + e- M-(g) + Energy released = - EA1
isolated gaseous atom gaseous anion
change involved are known as – successive EA.
For Ex.
O(g) + e- O-(g) = EA1 = - 141 KJ/mole
O-(g) + e- O2-(g) = EA2 = + 780 KJ/mole
EA depends on the following factors
1) Atomic size : If the size of atom is small, the distance between the nucleus
and the incoming electron will also be small
2) Nuclear charge :
3) Electronic configuration :
The effect of E.C. on the magnitude of EA can be explained with the help of following examples.
i) EA values of IIA group elements :
ii) EA values of N and P :
The valence shell E.C. of N and P are :
N 2s2 2p3 ; P 3s23p3
iii) EA values of halogens :
iv) EA of noble gases :
and have no tendency to accept electron from outside.
a) Along the periods :
b) Down the groups :
1) Tendency to form anions :
2) Reducing and oxidizing power of elements :
Reducing agent
( lower Valency stast = 0) ( higher v. s.=+1)
M(g) + e- M-(g)
Oxidizing agent (LVS = -1)
(HVS = 0)
3) Metallic and non-metallic characters of elements :
M - e- M+
M + e- M-
d) Elecronegativity :
Definition : The tendency/ability/power of a bonded atom in a molecule to attract the shared pair of electrons towards itself is termed as its electronegativity.
Explanation :
The important factors which affects the magnitude of electronegativity of elements are as follows :
1) Size of atom :
2) Charge on ion :
For e.g. M2+ > M+ > M
4) Number of inner shells :
5) Type of hybridization :
ronegetivity Increasing
a) Along the period : On going from left to right in a period the electronegativity values increases because.
i) On moving from left to right in a period, there is decrease in size of atoms. Smaller atoms have greater tendency to attract the electrons towards itself.
i.e. smaller atoms have high value of electronegativity.
ii) On moving from left to right there is increase in IE and EA of the elements. Thus, the electronegativity increases.
b) Down the group : When we go down the group the electronegativity value decreases due to following facts :
i) As we move down a group, there is an increase in size of atoms. Thus as size of atom increases, then their electronegativity decreases.
ii) Down the group, the IE and EA decreases, with the decrease of IE and EA the electronegetivity value also decrease.
B of a molecule
A-B = EA-B - under root EA.A × EB.B
XA – XB ∞ Amount of ionic character in A-B bond.
Now put the values of A-B, then we get
XA - XB = K [ EA - A – under root EA -A × EB-B]1/2
XA-XB = 0.208 [EA-B - under root EA-A × EB-B ]1/2