ELEMENTARY �GAS LAWS: BOYLES’, GAY-LUSSAC’S, AND CHARLE’S LAWS
BARKING DOG, �KEITH HARING, 1990
IN THIS PRESENTATION…
BOYLE’S LAW: PRESSURE VS. VOLUME RELATIONSHIP
Given what we looked at in the past, are pressure and volume directly or inversely related?
BOYLE’S LAW: PRESSURE VS. VOLUME RELATIONSHIP
They are inversely related! As the bag of air was taken underwater, the pressure increased which decreased the volume of the bag of air.
BOYLE’S LAW: PRESSURE VS. VOLUME RELATIONSHIP
As one variable increases, the other one decreases.
BOYLE’S LAW: PRESSURE VS. VOLUME RELATIONSHIP
BOYLE’S LAW: PRESSURE VS. VOLUME RELATIONSHIP
If we rearrange the equation, we get
PV = k
This equation is true for any point on the line, so:
P1V1 = k
and
P2V2 = k
1
2
BOYLE’S LAW: PRESSURE VS. VOLUME RELATIONSHIP
1
2
Since both of the previous equations equal k, then the two equations equal each other:
P1V1 = P2V2
EXAMPLE 1
A weather balloon has a volume of 7589 L on the ground where the pressure is 0.98 atm. When the balloon is released, what will its volume be at 30,000 ft where the pressure is 0.29 atm?
To solve this, we will use the “GUESS” method of organization.
G: write down your Givens in the problem
U: write down your Unknown in the problem
E: write down the Equation you will use to solve the problem
S: Substitute the numbers in for the variables in the equation
S: Solve the problem for the unknown variable
EXAMPLE 1
A weather balloon has a volume of 7589 L on the ground where the pressure is 0.98 atm. When the balloon is released, what will its volume be at 30,000 ft where the pressure is 0.29 atm?
Givens: V1 = 7589 L; P1 = 0.98 atm; P2 = 0.29 atm
Unknown: V2
Equation: P1V1 = P2V2
Substitute: 0.98 atm x 7589 L = 0.29 atm x V2
Solve: V2 = 26,000 L (notice lower P, higher V)
The GUESS method is a useful organizational tool and you will use it to solve these gas law problems. It will save you from making many mistakes!
GAY-LUSSAC’S LAW: PRESSURE VS. TEMPERATURE RELATIONSHIP
Given what we looked at in the past, are pressure and temperature directly or inversely related?
GAY-LUSSAC’S LAW: PRESSURE VS. TEMPERATURE RELATIONSHIP
GAY-LUSSAC’S LAW: PRESSURE VS. TEMPERATURE RELATIONSHIP
GAY-LUSSAC’S LAW: PRESSURE VS. TEMPERATURE RELATIONSHIP
y = mx + b
Substituting the variables for y and x:
P = mT + b
At 0 temp (no kinetic energy) there is 0 pressure, so b = 0 and changing “m” to “k”, the symbol for a constant in science, we get:
P = kT
GAY-LUSSAC’S LAW: PRESSURE VS. TEMPERATURE RELATIONSHIP
1
2
GAY-LUSSAC’S LAW: PRESSURE VS. TEMPERATURE RELATIONSHIP
1
2
EXAMPLE 2
If a sample of a gas at 25oC has a pressure of 19.4 psi, what pressure will the gas have if the temperature is decreased to -5.0oC?
EXAMPLE 2
CHARLES’S LAW: VOLUME VS. TEMPERATURE RELATIONSHIP
Given what we looked at in the past, are volume and temperature directly or inversely related?
CHARLES’S LAW: VOLUME VS. TEMPERATURE RELATIONSHIP
They are directly related! When the crushed ping pong ball was heated, the gas inside expanded and pushed the dent out of the ping pong ball.
CHARLES’S LAW: VOLUME VS. TEMPERATURE RELATIONSHIP
Since the relationship is direct, the equation for Charles’s Law can be derived in the same manner as Gay-Lussac’s Law and will have a very similar form.
The useful equation of Charles’s Law is:
EXAMPLE 3
EXAMPLE 4: WHICH LAW TO USE?
Steam (gaseous water) in a pressure cooker initially has a pressure of 304 kPa at a temperature of 100.oC. If the steam is heated to 150oC in the pressure cooker, what will the new pressure be?
Givens: P1 = 304 kPa; T1 = 100.oC (373 K); T2 = 150oC (424 K)
Unknown: P2
Equation: How do we know what equation to use?
Look at the givens and unknown and decide which�equation includes all of those variables. In this case, it is�Gay-Lussac’s Law.
EXAMPLE 4: WHICH LAW TO USE?
NOW IT’S YOUR TURN!