1 of 3

B

20

45º

D

Bottom of

tower

Top of

tower

60º

?

Height of the observer is neglected

A

C

line of sight

line of sight

Transmission

Tower

Q. From a point on the ground, the angles of elevation

of the bottom and the top of a transmission tower

fixed at the top of a 20m high building are 45º and

60º respectively. Find the height of tower.

2 of 3

(20 + x) m

Sol.

D

A

B

60º

C

20

45º

x

  1. From a point on the ground, the angles

of elevation of the bottom and the top

of a transmission tower fixed at the top

of a 20m high building are 45º and 60º

respectively. Find the height of tower.

AB = 20m

AB represents the height of the building

BC represents the height of the

transmission tower.

Let BC be x m

In right angled ΔBAD,

tan 45º =

AB

AD

1

=

20

AD

AD = 20 m

BC is part of AC

BC = AC – AB

To find AC, first we need to find AD

Opposite

side

Adjacent side

Observe ∠D

For ∠BDA

Opposite side →

Adjacent side →

tan 45o =

?

1

AB

AD

Ratio of opposite side and Adjacent side reminds us of _________

‘tan’

20m

?

Now, Consider ΔBAD

AC = AB + BC

AC =

20

+ x

AC =

Let us find AC

3 of 3

20m

In right angled ΔCAD,

tan 60º =

AC

AD

 

=

20 + x

20

 

20 + x

=

x

 

=

– 20

x

20

=

– 1)

x

20

=

– 1)

AC =

(20 + x) m

Height of the transmission tower is 14.6 m

x

20

=

× 0.73

x

14.6

=

 

(1.73

 

Sol.

  1. From a point on the ground, the angles

of elevation of the bottom and the top

of a transmission tower fixed at the top

of a 20m high building are 45º and 60º

respectively. Find the height of tower.

D

A

B

60º

C

20

45º

x

For ∠CDA

Opposite side →

Adjacent side →

AC

AD

Observe ∠D

Ratio of opposite side and Adjacent side reminds us of _________

‘tan’

tan 60o =

?

 

Adjacent side

(x +20)m

Opposite

side