A
C
E
B
F
D
Given : DE || AC
DF || AE
Prove that :
BF BE
FE EC
=
Proof :
In ΔABC,
DE || AC
... [given]
........(i)
BE
EC
=
BD
DA
... [by basic proportionality theorem]
In ΔABE,
DF || AE
... [given]
........(ii)
... [by basic proportionality theorem.]
... from (i) and (ii)
=
BF
FE
=
BD
DA
BF
FE
BE
EC
Ex 6.2 - 4