MSE, BARIPADA
DEPARTMENT OF CIVIL ENGINEERING
SUBJECT – GEO-TECH. ENGG.
TEACHER – ER. ANKIT JOSHI
PRESENTATION
ON
SOIL CLASSIFICATION
INTRODUCTION
NEED FOR SOIL CLASSIFICATION SYSTEMS
Classification System
“Language”
Engineering Properties
Permeability, shear strength, compressibility,
swell-shrinkage etc.
Engineering Purpose
(Foundation, Dams, Highways, Airfields, etc.)
Role of Soil Classification in Geotechnical Engineering
Classification and index properties
(w, e, γ , s, GSD, LL, PI, etc.)
Why more than one Classification System are in use?
SOIL CLASSIFICATION SYSTEMS
1. Grain-size classification
Limitations:
2. TEXTURALCLASSIFICATION
REMARKS
Example 1
Let it be desired to determine the textural classification of a soil whose grading is as follows:
4%
Gravel
31%
Sand
44%
Silt-size
21%
Clay-size
The two lines intersect within the area labeled LOAM, which is the textural class of this soil.
Notes
We could have used the point of intersection of:
Example 2
The textural classification is CLAY.
10%
Gravel
18%
Sand
27%
Silt-size
45%
Clay-size
Find the modified textural composition:
Let it be desired to determine the textural classification of a soil whose grading is as follows:
Because of the large percentage of gravel, it may be called GRAVELLY CLAY.
Limitations of Textural Classification Systems
3. CLASSIFICATION BY USE
A. AASHTO CLASSIFICATION SYSTEM
Tests Required:
Criteria:
Remarks
Sieve No. 10
Sieve No. 200
18
4.75 mm
2.0 mm
0.425 mm
0.075 mm
(AASHTO)
Gravel
(USCS)
Sand
Sieve No. involved in AASHTO Soil Classification System
3 Groups
6 Subgroups
4 Groups
2 Subgroups
For classification starts apply the test data from left to right, top to bottom. By process of elimination, the first group from the left into which the test data fit is the correct classification.
No. 10
No. 40
No. 200
Note:
Differentiation between A-2’s and other group is based on %passing Sieve No. 200
REMARKS
GROUP INDEX
1. Percentage of the soil passing the No. 200 (0.075 mm) sieve.
2. Liquid limit, LL
3. Plasticity Index, PI
F200= % passing No. 200 sieve.
Rules for Determining Group Index
No. 10
No. 40
No. 200
GI = 0
Partial
Group
Index
Full Group Index
Example 1
The sieve analysis and plasticity data for two soils are given in the table below. Classify soils according to the AASHTO soil classification system.
Soil 2
%finer
Soil 1
%finer
Sieve Size
35
100
NO. 4
20
100
NO. 10
10
99
NO. 40
5
90
NO. 100
2
75
NO. 200
-
110
LL
-
50
PL
No. 10
No. 40
No. 200
Soil 2
%finer
Soil 1
%finer
Sieve Size
35
100
NO. 4
20
100
NO. 10
10
99
NO. 40
5
90
NO. 100
2
75
NO. 200
-
110
LL
-
50
PL
Soil 1:
A-7-5
GI =(75-35)[0.2+.005(110-40)]
+0.01(75-15)[60-10] = 52
The soil is A-7-5(52)
Soil 2:
A-1-a(0)
110
Soil 1:
A-7-5
Because %Passing #200 > 35%
The soil is classified as A-7-5 and not A-2-7.
Example 2
#200 86%
LL 70%
PI 32%
Because %Passing #200 > 35%
The soil is classified as A-7-5 and not A-2-7.
Example 3
The grain size distribution curve, natural water content, liquid limit, and liquidity index are give below. Classify the soil according to the AASHTO Classification System.
PL =21.25%
PI = 18.75%
%finer
Sieve No.
98
NO. 4
86
NO. 10
28
NO. 40
10
NO. 200
40
LL
19
PI
40
Given
Solution
No. 10
No. 40
No. 200
%finer
Sieve No.
98
NO. 4
86
NO. 10
28
NO. 40
10
NO. 200
40
LL
19
PI
From the AASHTO Table the soil is classified as: A-2-6 (0)
Because %Passing #200 < 35%
The soil is classified as A-2-6 and not A-6.
%finer
Sieve No.
98
NO. 4
86
NO. 10
28
NO. 40
10
NO. 200
40
LL
19
PI
Note: If the location comes along the border line, we need to consult the table and the grain size will tell the classification of the given soil.
Remarks About AASHTO System
PI <= LL- 30 ------🡪A-7-5
PI > LL- 30--------🡪 A-7-6
So it was easer to put A-3 before A-2 in order to facilitate left to right and top to bottom procedures applied in this system.
Or instead we use the chart
B. UNIFIED SOIL CLASSIFICATION SYSTEM (USCS)
Definition
Suffix
Definition
Prefix
Well graded
W
Gravel
G
Poorly Graded
P
Sand
S
Silty
M
Silt
M
Clayey
C
Clay
C
High Plasticity
H
Organic
O
Low Plasticity
L
Peat
Pt
Use Plasticity Chart
Gravels
Sands
High
Plasticity
Low
Plasticity
Sands
Gravels
AASHTO
USCS
To determine if well graded (W) or poorly graded (P), calculate Cu and Cc
Coefficient of uniformity
Coefficient of gradation
B-Line
MH
CH
ML
CL-ML
CL
A-Line
U-Line
OH
or
OH
or
OH
or
OH
or
OL or OH based on the value of a
Organic Soils
Coarse-grained soils (Gravel (G) or Sand (S))
Fine-grained soils (Silt (M) or Clay (C))
% Passing sieve No. 200 (0.075 mm)
> 50%
< = 50%
% Coarse soil (Co) = 100 - % Passing # 200
% Gravel (G) = 100 - % Passing # 4
G > 1/2 Co
G < 1/2 Co
Gravel (G)
Sand (S)
% Passing sieve No. 200
< 5%
5% -12 %
> 12%
GW, GP, SW or SP
Use 🡪 Cu, Cc
W : well graded P: poorly graded
GW-GM, GW-GC, GP-GM, GP-GC, SW-SM, SW-SC, SP-SM, SP-SC
GM, GC, SM, SC
Use 🡪 plasticity charts
B-Line
MH
CH
ML
CL-ML
CL
A-Line
OH
or
OH
or
OL
or
OL
or
OL or OH based on the value of α
Example 1
The sieve analysis and plasticity data for two soils are given in the table below. Classify the soils according to the USCS soil classification system.
Soil 2
%finer
Soil 1
%finer
Sieve Size
100
100
NO. 4
100
93
NO. 10
100
52
NO. 40
92
25
NO.100
85
16
NO. 200
89
38
LL
49
23
PL
Soil 1:
Soil 2:
SC
MH
Example 2
Classify the following soils Using USCS
47
SC
CH
SM
SC
CH
SM
Example 2 (Cont.)
Example 2 (Cont.)
49
50
Example 3
51
Soil A is then classified as SP-SM
(Poorly graded sand with silt and gravel)
Example 4
#4 = 95%
#200 = 11%
Coarse fraction =100-11 = 89%,
Gravel = 100 -95 = 5% (5/89 = 5.6% < 50%) -🡪 Sand
From Atterberg Tests
LL = 32, PL = 26
Example 4 (cont.)
D10 = 0.06 mm, D30 = 0.25 mm, D60 = 0.75 mm
Cu = 0.75/0.06 = 12.5 Cc = 0.25X0.25/(0.75X 0.06) = 1.39
∴ Well graded
From Atterberg Tests
LL = 32, PL = 26
PI = 32-26 = 6
The soil is classified as SW-SM (Well-graded sand with silt)
The fine part is silt
Remarks
Comparison of the USCS and AASHTO Classification Systems
In USCS if 50% passes No. 200 🡺 fined-grained