1 of 2

Class interval

Frequency

50 – 70

18

70 – 90

12

90 – 110

13

110 – 130

27

130 – 150

8

150 – 170

22

(4 marks)

Find the mean of each of the following frequency distributions (5 – 14)

6

Sol.

Class interval

Class

Mark (xi)

di =

fiui

60

Total

--

--

Σ fiui =

61

Class width(h)

= 20

– 20

0

20

40

– 40

– 1

0

1

2

– 2

60 + 20

100

120

140

80 + 20

100 + 20

120 + 20

= xi

100

100

Assumed Mean (A) =

100

60 - 100

80 - 100

100 – 100

120 - 100

140 - 100

80

No. of workers (fi)

Σ fi =

100

--

ui=

di

g

=

di

20

×

×

×

×

×

+

+

+

+

+

+

+

+

12

13

27

8

18

0

50 - 70

70 - 90

90 - 110

110 - 130

130 - 150

A

50 + 70

2

40

20

20

20

0

20

20

– 40

–20

– 48

109

– 36

– 12

27

16

20

xi

– A

 

Mean

 

=

Σ fi

 

Σ fiui

60

3

160

140 + 20

160 - 100

+

+

22

150 - 170

66

60

20

×

g is the G.C.D. of all values of di

2 of 2

Class interval

Frequency

50 – 70

18

70 – 90

12

90 – 110

13

110 – 130

27

130 – 150

8

150 – 170

22

(4 marks)

Find the mean of each of the following frequency distributions (5 – 14)

6

Sol.

u

=

Σ fiui

Σ fi

=

61

100

=

u

Σ fiui =

61

Σ fi =

100

0.61

 

=

A

+

u

×

g

=

100

+

20

=

100

=

112.2

+

12.2

(0.61)

 

Assumed Mean (A) =

100

G.C.D of all di (g)

= 20