Stoichiometry – Limiting & Excess Reagents
Limiting Reagent =
Ex:
Excess Reagent =
How many bikes can you make from the following supplies?
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Limiting Reagent
=
Excess Reagent
=
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Calculating Limiting Reagents
1)
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2)
- NEED > HAVE =
Ex:
- NEED < HAVE =
Ex:
3)
4)
Ex: 2 Na + Cl2 2 NaCl
A) Limiting reagent?
B) Amount of NaCl produced? (58.44 g/mol)
C) Amount of excess reagent left over?
| Reactant | Reactant | Reactant | 🡪 | Product | Product | Product |
Reaction Equation |
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154.1 g of sodium (22.99 g/mol) reacts with 227.2 g of chlorine (70.90 g/mol):
| Reactant | Reactant | Reactant | 🡪 | Product | Product | Product |
Reaction Equation |
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Ex: 2 Na + Cl2 2 NaCl
154.1 g of sodium (22.99 g/mol) reacts with 227.2 g of chlorine (70.90 g/mol):
A) Limiting reagent?
-
-
-
= -
-
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-
= -
-
-
-
-
=
-
&
Ex: 2 Na + Cl2 2 NaCl
154.1 g of sodium (22.99 g/mol) reacts with 227.2 g of chlorine (70.90 g/mol):
| Reactant | Reactant | Reactant | 🡪 | Product | Product | Product |
Reaction Equation |
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A) Limiting reagent?
=
-
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= -
-
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&
Excess reagent
Ex: 2 Na + Cl2 2 NaCl
154.1 g of sodium (22.99 g/mol) reacts with 227.2 g of chlorine (70.90 g/mol):
-
-
B) Amount of NaCl produced?
-
= -
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Entered in BCA Table
Ex: 2 Na + Cl2 2 NaCl
154.1 g of sodium (22.99 g/mol) reacts with 227.2 g of chlorine (70.90 g/mol):
| Reactant | Reactant | Reactant | 🡪 | Product | Product | Product |
Reaction Equation |
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A) Limiting reagent?
= -
-
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= -
-
-!!!
&
Excess reagent
-
-
Ex: 2 Na + Cl2 2 NaCl
154.1 g of sodium (22.99 g/mol) reacts with 227.2 g of chlorine (70.90 g/mol):
-
-
B) Amount of NaCl produced?
-
= -
-
-
=
*Always Start with Limiting Reagent!!!*
Entered in BCA Table
Ex: 2 Na + Cl2 2 NaCl
154.1 g of sodium (22.99 g/mol) reacts with 227.2 g of chlorine (70.90 g/mol):
C) Amount of excess reagent left over?
| Reactant | Reactant | Reactant | 🡪 | Product | Product | Product |
Reaction Equation |
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Ex: 2 Na + Cl2 2 NaCl
154.1 g of sodium (22.99 g/mol) reacts with 227.2 g of chlorine (70.90 g/mol):
A) Limiting reagent?
B) Amount of Cu2S produced? (159.17 g/mol)
C) Amount of excess reagent left over?
| Reactant | Reactant | Reactant | 🡪 | Product | Product | Product |
Reaction Equation |
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Ex: 2 Cu + S Cu2S
80.0 g of copper (63.55 g/mol) reacts with 25.0 g of sulfur (32.07 g/mol):
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= -
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Ex: 2 Cu + S Cu2S
| Reactant | Reactant | Reactant | 🡪 | Product | Product | Product |
Reaction Equation |
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80.0 g of copper (63.55 g/mol) reacts with 25.0 g of sulfur (32.07 g/mol):
A) Limiting reagent?
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= -
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= -
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=
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&
Ex: 2 Cu + S Cu2S
80.0 g of copper (63.55 g/mol) reacts with 25.0 g of sulfur (32.07 g/mol):
A) Limiting reagent?
=
=-
-
-!!!
&
Excess reagent
| Reactant | Reactant | Reactant | 🡪 | Product | Product | Product |
Reaction Equation |
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2 Cu
S
Cu2S
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Ex: 2 Cu + S Cu2S
80.0 g of copper (63.55 g/mol) reacts with 25.0 g of sulfur (32.07 g/mol):
-
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B) Amount of Cu2S produced?
-
= -
-
Entered in BCA Table
Ex: 2 Cu + S Cu2S
80.0 g of copper (63.55 g/mol) reacts with 25.0 g of sulfur (32.07 g/mol):
A) Limiting reagent?
=
=-
-
-!!!
&
Excess reagent
| Reactant | Reactant | Reactant | 🡪 | Product | Product | Product |
Reaction Equation |
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2 Cu
S
Cu2S
0 mols
1.26 mols
.780 mols
- 1.26 mols
0 mols
- .630 mols
.150 mols
Ex: 2 Cu + S Cu2S
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80.0 g of copper (63.55 g/mol) reacts with 25.0 g of sulfur (32.07 g/mol):
-
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B) Amount of Cu2S produced?
-
= -
*Always Start with Limiting Reagent!!!*
Entered in BCA Table
Ex: 2 Cu + S Cu2S
-
-
=
80.0 g of copper (63.55 g/mol) reacts with 25.0 g of sulfur (32.07 g/mol):
C) Amount of excess reagent left over?
-
-
-
=
Ex: 2 Cu + S Cu2S
| Reactant | Reactant | Reactant | 🡪 | Product | Product | Product |
Reaction Equation |
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Change |
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After |
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80.0 g of copper (63.55 g/mol) reacts with 25.0 g of sulfur (32.07 g/mol):