Application of De Moivre’s Theorem (Complex Numbers)
Shemar, Alisa, Mohamed, Cooper
What is De Moivre’s Theorem?
The equation is:
Guided Problem
Using De Moivre’s Theorem, simplify the following expression:
First, convert to trigonometric form.
Next, apply De Moivre’s Theorem by raising the modulus to the sixth power and multiplying the argument by six.
Lesson 7
Finding the nth root of a complex number
With Z being the complex number and n being the power it is raised to
The fourth roots of -1
First find the modulus, r = 1 and then the argument, arg = 𝜋. This gives us -1 in polar form, 1 cis(𝜋)
Next plug the values into the formula, where r = 1, 𝛳 = 𝜋, n = 4, and k = n-1
Find the fifth roots of -9-9i√2
First convert to polar form by finding the modulus, r=√((-9)2+(-9)2)=√(243) = 9√3
Then find the argument, arg = tan-1 (y/x) = tan-1((-9√2)/(-9)) = tan-1(√2) ≈ 0.9553
However, since the angle is in the third quadrant you add 𝜋 to that so the argument would be ≈ 4.0969
Polar Form: 9√3 cis(4.0969) or 9√3 (cos(4.0969)+ i sin(4.0969))
Then use this equation to find the roots by plugging in values for k given that k = n-1