B. Sc. S. Y. ELECTROCHEMISTRY
Dr. S. M. Reddy
Associate Prof.
Physical Chemistry
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Conductivity cell
Cell constant and its determination
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The exact value of the cell constant (l/A) can be determined by measuring the distance between the electrodes (l) and their area of cross-section (A).
Actual measurement of these dimensions is very difficult.
Therefore an indirect method is employed to determine the value of cell constant. We know that
To determine cell constant, a standard solution of KCl whose specific conductance at a given temperature is known is used.
Then a solution of KCl of the same strength is prepared and its conductance determined experimentally at the same temperature.
Substituting the two values in the above expression the cell constant can be calculated.
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Arrhenius theory of electrolytic dissociation
According to Arrhenius the conductance of solution was due to the presence of ions.
In 1884, he put forward the theory of ionisation.
AB → A+ + B‾ (Old view)
In its modern form, the theory assumes that the ions are already present in the solid electrolyte and these are held together by electrostatic force.
When electrolytes are placed in water, these neutral molecules dissociate to form separate anions and cations.
A+B‾ → A+ + B‾ (Modern view)
Therefore, this theory is also called as theory of electrolytic dissociation.
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Applying the law of mass action
K – is called as dissociation constant
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Limitations of Arrhenius theory of electrolytic dissociation
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Debye-Huckel theory of strong electrolytes
In case of weak electrolytes, the increase in the equivalent conductance with dilution can be explained on the basis of Arrhenius theory which suggests that the conductance increases because the dissociation of weak electrolyte increases with dilution.
However, in case of strong electrolytes, as they are almost completely dissociated even at moderate concentration, the increase in equivalent conductance with dilution must be due to some additional factors.
Debye-Huckel theory explains the increase in the equivalent conductance of strong electrolytes with dilution is based on following factors.
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Relaxation effect or asymmetric effect
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As it is moving out of the ionic atmosphere, it has to rebuild an ionic atmosphere of apposite charge around it and the old ionic atmosphere is destroyed. However, the destruction of old ionic atmosphere and the formation of new ionic atmosphere do not take place at the same time. There is some time lag called as time of relaxation between the destruction of old ionic atmosphere and the formation of new ionic atmosphere.
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During this time, the old ionic atmosphere pulls the moving ion backward and hence retards its motion (Fig. b). Hence this effect is known as relaxation effect. Alternatively, it may be argued that as the central ion moves, the symmetry of the atmosphere is lost, more ions of the ionic atmosphere are left behind than are present in the front (Fig. b). The excess ions of the ionic atmosphere present behind the moving ion drag the ion backward and retard its motion. Thus the effect arises because of the asymmetry of the ionic atmosphere of the moving ions and hence is also known as asymmetric affect.
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Electrophoretic effect
Fig. c
When EMF is applied, the central ion moves in one direction and the oppositely charged ionic atmosphere moves in the opposite direction. As this ionic atmosphere moves, the solvent molecules associated with it also moves. Thus the flow of the ionic atmosphere and that of the solvent molecules attached to it takes place in a direction opposite to that of the movement of the central ion. In other words, the central ion is moving against the stream. Thus motion of the ions is retarded. This effect is called as electrophoretic effect (Fig. c).
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Debye- Huckel Onsager’s equation and its verification
Besides these two effects, the third retarding force is the normal frictional resistance offered by the medium which depends on the viscosity of the medium, its dielectric constant etc.
Bases upon the above facts, Debye and Huckel (1923) derived a mathematical expression for the variation of equivalent conductance with concentration. This equation was further improved by Onsagar (1926-27). Therefore this equation is known as Debye-Huckel –Onsagar equation or simply Onsagar equation. For uni-univalent electrolyte, it is written in the form :
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Where, Λc – is equivalent conductance at concentration c
Λo – is equivalent conductance at infinite dilution
D – Dielectric constant of the medium
η – Viscosity of medium
T – Temperature of the solution in degrees absolute
C – concentration of the solution in moles/lit
As D and η are constants for a particular solvent, therefore at constant temperature, the above equation can be written as :
Where, A and B are constants for a particular solvent at a particular temperature.
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Verification of Onsager’s equation
Validity of the Onsagar equation is established by the following two observations:
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Migration of ions
AgNO3 → Ag+ + NO3–
CuSO4 → Cu++ + SO4– –
H2SO4 → 2H+ + SO4– –
The electrolytes dissociate in solution to form positive ions (cations) and negative ions (anions). As the current is passed between the electrodes of the electrolytes, the cations will move towards cathode and anion will move towards anode. Usually the different ions move with different rates.
Migration of ions through electrolytic solution to opposite electrodes
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The apparatus used consists of a U tube having long horizontal portion. It is fitted with side limbs. The horizontal portion is filled with a jelly of agar – agar treated with a trace of alkali. This is then made red by adding few drops of phenolphthalein.
When jelly is set, dil H2SO4 is added in the anodic limb of the tube. Sodium sulphate solution is added in the cathodic limb. On passing the current H+ ions in the left limb solution eventually move into the agar – agar jelly. Their passage is marked by the gradually discharge of the red colour due to the neutralization of the alkali by H+ ions. The movement of the red boundary through the agar – agar jelly shows that H+ ions migrates to the cathodic limb.
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The lower part of the U – tube is filled with a 5 % water solution of agar – agar with a small amount of copper dichromate (CuSO4 + K2Cr2O7). The surface of the green solution in the two limbs of the U – tube is marked by a small amount of charcoal. In both the limbs, a layer of solution of potassium nitrate and agar – agar is placed. This is allowed to set. Over this second layer of potassium nitrate solution in this water is placed and two electrodes are inserted in it.
As the current is turned on, the blue colour of Cu++ ions rises into the jelly under the cathode and reddish yellow dichromate ions (Cr2 O7– – ) move up under the anode. After some times the two types of ions are seen rising with well defined boundaries. The use of jelly is to prevent the mixing of the solutions by diffusion.
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Transport number
During electrolysis the anions and cations carry current.
The fraction of the total current carried by the cation or the anion is called as transport number. It is also known as Hittorf number.
Let, v+ - be the speed of migration of cation.
v_ be the speed of migration of anion.
t+ and t_ are the transport numbers of cations and anions respectively.
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r – r t+ = t+
r = t+ + r t+
r = t+ ( 1 + r)
t _ = 1 – t+
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Kohlrausch law
In 1875, Kohlrausch studied the equivalent conductance of different electrolytes at infinite dilution ( λ∞) and he observed that each ion contributes to the conductance of the solution. He stated the general equation known as Kohlrausch law. It states that:
The equivalent conductance of an electrolyte at infinite dilution is equal to the sum of the equivalent conductance of the component ions. Mathematically, it states as :
λ∞ = λa + λc
where, λa is equivalent conductance of anion
λc is equivalent conductance of cation
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Applications of Kohlrausch’s law:
Each ion has the same constant ionic conductance at a fixed temperature, no matter of which electrolyte it forms a part. It is expressed in ohm-1 cm2 and is directly proportional to the speeds of the ions.
λa α v_ or λa = k x v_
λc α v+ or λc = k x v+
where k is constant of proportionality
also
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Dividing eq 1 by 2
From the equation 3 we can determine the ionic conductance from the experimental values of the transport number of the ions.
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Weak electrolytes do not ionize to a sufficient extent in solution and are far from being completely ionized even at very great dilution. The practical determination of ( λ∞) in such cases is, therefore, not possible. However, it can be calculated with the help of Kohlrausch’s law.
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Thus the ionic conductance of an ion is obtained by multiplying the equivalent conductance at infinite dilution of any strong electrolyte containing that ion by its transport number.
In this manner, the ionic mobilities of the two ions present in the weak electrolyte can be calculated. Thus we can get the equivalent conductance of the electrolyte at infinite dilution by adding up these two values.
The apparent degree of dissociation (α ) of an electrolyte at infinite dilution V is given by α = λv/λ∞, where λv is the equivalent conductance of the electrolyte at the dilution V and λ∞ is its equivalent conductance at infinite dilution. This according to Kohlrausch’s law and is equal to the sum of λa and λc .
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Substances like AgCl or PbSO4 which are ordinarily called as insoluble do possess a definite value of solubility in water. This can be determined from conductance measurements of their saturated solutions. Since a very small amount of solute is present it must be completely dissociated into ions even in a saturated solution so that the equivalent conductance k V is equal to equivalent conductance at infinite dilution. This according to Kohlrausch law is the sum of the ionic mobilities.
k V = λ∞ = λa + λc
Knowing k and λ∞ , V can be calculated which is the volume in ml containing 1 gm-eqvt of the electrolyte.
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The absolute ionic mobility of an ion is defined as the velocity of an ion in centimeters per second under a potential gradient of one volt per centimeter. It is expressed in cm/s.
Potential gradient = Applied EMF / Distance between the electrodes.
For example, let the velocity of the ion at infinite dilution be U cm per sec. when the distance between the electrodes is 20 cm and the voltage 100 V. then the potential difference is 100/20 ie volts per cm and the ionic mobility is U/5 cm/sec.
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It has been found that the ionic conductance is directly proportional to the ionic mobility ie
λa α U a and λc α Uc
λa = k U a and λc = k Uc
Where, k is the proportionality constant. Its value is equal to the charge on one gram-equivalent of the ion under the potential gradient of 1 volt per cm ie k = 96500 coulomb (1 Faraday). Therefore, the ionic mobility is obtained by dividing the ionic conductance by96500 coulombs.
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The observed specific conductance of the purest water at 25 °C is 5.54 x 10-8 mhos. The conductance of one litre of water containing 1 gm eqvt of it would be:
λH2O = 5.54 x 10-8 x 1000 = 5.54 x 10-5 mhos
At the temperature the conductance of H+ ions and OHˉ ions are :
λH+ = 349.8 mhos and λOH- = 198.5 mhos
according to Kohlrausch law
λH2O = λH+ + λOH-
= 349.8 + 198.5
= 548.3 mhos
One molecule of water gives one H+ ion and one OHˉ
H2O = H+ + OHˉ
Assuming that ionic concentration is proportional to conductance, we have
Kw = [H+] [OHˉ] = 1.02 x 10-14 at 25 °C
For most purposes, the value of Kw is taken to be 10-14
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Conductometric titrations:
Conductometric methods help us to reach accurate end points in titrations. The basic principle in conductometric titration is that when one solution from the burette is added to the other solution in the titration flask, conductance value changes. This helps us to arrive at the end point.
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Suppose a solution of HCl is to be titrated against NaOH solution. The acid solution is taken in a beaker in which conductivity cell is deepened and the NaOH solution in the burette. The conductivity of the acid solution is noted initially as well as after successive addition of small amount of NaOH solution. Evidently, the conductance of the acid solution in the beginning is very high as it contains highly mobile H+ ions ( HCl → H+ + Cl ˉ ). On adding NaOH solution to the HCl solution, the H+ ions are replaced by slow moving Na+ ions and hence the conductance of the solution keeps on falling till the end point is reached (ie. all the H+ are replaced by Na+ ions).
H+ + Cl ˉ + Na+ OH ˉ → Na+ + Cl ˉ + H2O
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Beyond the end point, further addition of NaOH solution brings in fast moving OH ˉ ions and hence the conductance of the solution again starts increasing. If conductance values are plotted against the volume of the alkali added, a curve of the type ABC is obtained as shown in fig a. Point of intersection B corresponds to the end point.
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Consider a titration of strong acid such as HCl against weak base NH4OH solution. The conductance of HCl solution is initially high because of the presence of fast moving H+ ions. As NOH4OH solution is added, the fast moving H+ ions are replaced by the slower NH4+ ions and hence the conductance falls along the line AB.
H+ + Cl ˉ + NH4OH → NH+ + Cl ˉ + H2O
When the end point is reached, further addition of NH4OH does not cause much change in the conductance because NH4OH is weakly ionized substance. Therefore the line BC is almost horizontal.
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Consider a titration of weak acid such as CH3COOH against strong base NaOH solution. The conductance of the acid initially is very low because of low ionization of the acid. However on adding NaOH solution to the acid solution, the salt produced CH3COONa is highly ionized and hence the conductance keeps on increasing along the line AB as shown in fig .When the whole of acetic acid is neutralized, further addition of NaOH solution causes the conductance to increase sharply along the line BC because the NaOH added introduces the fast moving OH‾ ion. Intersection of the two lines AB abd BC at the point B gives the equivalent point.
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Consider the titration of weak acid acetic acid against weak base NH4OH. Initially the conductance of the solution is low due poor dissociation of acetic acid. As the base is added to it, the conductance starts picking up due to the formation of ionizable ammonium acetate. After the neutralization point, conductance remains almost constant, because the free base NH4OH is a weak electrolyte. The end point is quite sharp as shown in the fig.
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Consider the titration of silver nitrate solution against KCl solution. AgNO3 solution has some definite value of conductance in the beginning. As KCl solution is added to the AgNO3 solution, the following reaction takes place.
Ag+ + NO3ˉ + K+ + Cl ˉ → K+ + NO3ˉ + AgCl
Thus the net result is the replacement of the Ag+ ions of AgNO3 solution by K+ ions. Since both these ions have nearly equal ionic mobility, the conductance remains almost constant till the end point is reached as shown in fig. After the end point, further addition of KCl brings in K+ and Cl ‾ ions. Thus the conductance begins to increase along the line BC. Point of intersection B corresponds to the equivalence point.
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Advantages of conductometric titrations.
Conductometric titrations have number of advantages over ordinary titrations:
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Thank you