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CIRCLE

  • Sum based on Theorem – The lengths

of two tangents drawn from

an external point to a circle are equal.

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Q. Prove : Parallelogram circumscribing a circle is a rhombus.

D

A

B

C

P

Q

R

S

To prove : ABCD is a rhombus.

Hint : prove : AB = BC

Proof :

AR

BR

CP

PD

=

=

=

=

AS

BQ

CQ

DS

…(i)

…(ii)

…(iii)

…(iv)

.

[Length of the tangents drawn from an external point to a circle are equal]

Adding (i), (ii), (iii) & (iv)

AB

+

CD

=

AD

+

BC

(AR + BR)

+ (CP + PD)

=

+ (BQ + CQ)

(AS + SD)

To prove parallelogram a rhombus, adjacent sides should be equal

AB is made up of two segments

AR and

BR

We know, tangent segments drawn from external point are equal

CD is made up of two segments

CP and

DP

We know, tangents drawn from external point are equal

…(v)

[A-R-B, B-Q-C, C-P-D, A-S-D]

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AB

+

CD

=

AD

+

BC

Q. Prove : Parallelogram circumscribing a circle is a rhombus.

D

A

B

C

P

Q

R

S

To prove : ABCD is a rhombus.

Hint : prove : AB = BC

Proof :

…(v)

But,

AB

=

CD

…(vi)

AD

=

BC

…(vii)

[Opposite sides of a

parallelogram are equal]

2AB

=

2BC

AB

=

BC

ABCD is a rhombus.

AB

+

AB

=

BC

+

BC

In a parallelogram opposite sides are equal

A pair of adjacent sides in a parallelogram is equal

(A parallelogram is a rhombus if a pair of adjacent

sides is equal)