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COORDINATE GEOMETRY

  • Sum based on Distance formula

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…(ii)

Q. Name the type of quadrilateral formed, if any, by the

following points, and give reasons for your Answer.

(i)

Let A (–1, –2),

B (1, 0) ,

C (–1, 2),

D (–3, 0)

AB =

[1

(–1)

2

+

[0

2

AB =

(2)

2

+

(2)

AB =

4

AB =

8

(–2)

2

]

]

+

4

AB =

2

2

BC =

(–1

1)

2

+

(2

2

0)

BC =

(–2)

2

+

(2)

2

BC =

4

BC =

8

+

4

BC =

2

2

CD =

[–3

(–1)

2

+

(0

2

CD =

(–2)

2

+

(–2)

CD =

4

CD =

8

2)

2

]

+

4

CD =

2

2

Sol.

(–1, –2) , (1, 0) , (–1, 2) , (–3, 0)

x1 = 1,

y1 = 0,

x2 = -1,

y2 = 2

x2 = –3,

x1 = -1,

y2 = 0

y1 = 2,

Let us find AB

Let us find BC

Let us find CD

Let the coordinates of C be (x1, y1).

Let the coordinates of D be (x2, y2).

What is the formula to find distance between two points ?

+

(

)

(

)

x2

x1

y2

y1

2

2

What is the formula to find distance between two points ?

+

(

)

(

)

x2

x1

y2

y1

2

2

x1 = -1,

x2 = 1,

y2 = 0

y1 = –2,

A quadrilateral has four sides

So, we need to find all four sides of quadrilateral

What is the formula to find distance between two points ?

+

(

)

(

)

x2

x1

y2

y1

2

2

…(i)

…(iii)

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AB =

2

2

…(i)

BC =

2

2

…(ii)

AC =

2

2

…(iii)

Q. Name the type of quadrilateral formed, if any, by the

following points, and give reasons for your Answer.

AD =

(–3

+

1)

2

+

(0

2

+

2)

AD =

[–3

(–1)]

2

+

[0

2

AD =

(–2)

2

+

(2)

AD =

4

AD =

8

(–2)]

2

+

4

AD =

2

2

A (–1, –2),

B (1, 0) ,

C (–1, 2),

D (–3, 0)

Sol.

x2 = –3,

x1 = –1,

y2 = 0

y1 = –2

Let the coordinates of A be (x1, y1).

Let the coordinates of D be (x2, y2)

Let us find AD

What is the formula to find distance between two points ?

+

(

)

(

)

x2

x1

y2

y1

2

2

…(iv)

AB

=

BC

[From (i), (ii), (iii) and (iv)]

=

AC

=

AD

ABCD is a Rhombus.

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Q. Name the type of quadrilateral formed, if any, by the

following points, and give reasons for your Answer.

Diag AC =

[–1

(–1)]

2

+

[2

2

AC =

0

+

(4)

AC =

16

(–2)

2

AC =

4

]

Diag BD =

(–3

1)

2

+

(0

2

BD =

(–4)

+

0

BD =

16

0)

BD =

4

2

In ABCD,

AB

=

BC

=

CD

=

AD

and

Diagonal AC

=

Diagonal BD

Hence, ABCD is a square

A (–1, –2),

B (1, 0) ,

C (–1, 2),

D (–3, 0)

Sol.

x2 = –1,

y2 = 2

x1 = –1,

y1 = -2

x2 = –3,

y2 = 0

x1 = 1,

y1 = 0

Let the coordinates of B be (x1, y1).

Let the coordinates of D be (x2, y2).

Let us find diag. BD

Let us find AC

AC =

(–1

+

1)

2

+

(2

2

+

2)

ABCD is a Rhombus.

AB

=

BC

=

AC

=

AD

Let the coordinates of C be (x2, y2).

Let the coordinates of A be (x1, y1).

What is the formula to find distance between two points ?

+

(

)

(

)

x2

x1

y2

y1

2

2

What is the formula to find distance between two points ?

+

(

)

(

)

x2

x1

y2

y1

2

2