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TOPIC : motion in a straight line

CLASS : XI

SUBJECT : PHYSICS

PREPARED BY:

M.G.ADHAU,

PGT-PHYSICS.

J.N.V.NANDED (M.S.)

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To locate the position of object we require a reference point (origin) and a set of axes.

Describing motion

The coordinates (x,y,z) describe the position of object.

The coordinate system along with the clock is known as the frame of reference.

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The actual path length travelled by the object is known as distance.

Distance:

It is Scalar quantity.

Displacement:

The change in position is known as displacement.

Displacement = Final position –Initial position

Δx = x2 – x1

x2 > x1, Δx– is positive

x2 < x1, Δx– is negative

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The motion of the object can be represented by position –time graph.

Position –time Graph:(x-t graph)

t (S)

x (m)

0

10

20

30

40

10

20

30

40

t (S)

X (m)

0

1

2

3

4

2

4

6

8

Object is at rest

Object in uniform motion

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Time (S)

Position(m)

0

1

2

3

4

2

4

6

8

Object in non-uniform motion

i.e. accelerated motion

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Average velocity is defined as displacement (Δx) divided by time interval (Δt)

Average velocity:

It is measured in ms-1

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Average Speed:

Average speed is defined as the total path length travelled by the object divided by time interval.

It is measured in ms-1

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t (S)

X (m)

0

Q

A

B

P

X-t graph for two children A and B returning from their school O to their houses P and Q resp.

Choose the correct entries in the bracket

1.(A/B) lives closer to the school than(B/A)

2.(A/B) stars from the school earlier than(B/A)

3.(A/B) walks faster than(B/A)

4. A and B reach home at the (same/different) time.

5.(A/B) overtakes(B/A) on the road (once/twice)

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Instantaneous Velocity:

The velocity at an instant is defined as the limit of average velocity as the time interval becomes infinitesimally small(Δt tends to zero)

The instantaneous velocity is also defined as the rate of change of position at that instant.

The instantaneous velocity is the time derivative of position.

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Instantaneous Speed:

The magnitude of an instantaneous velocity is called as instantaneous speed.

Speed associated with both the velocities will 25 ms-1

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Average acceleration is defined as change in velocity (Δv) divided by time interval (Δt)

Average Acceleration:

It is measured in ms-2

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Instantaneous acceleration:

The acceleration at an instant is defined as the limit of average acceleration as the time interval becomes infinitesimally small (Δt tends to zero)

The instantaneous acceleration is also defined as the rate of change of velocity at that instant.

The instantaneous acceleration is the time derivative of velocity.

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x

x

t

t

x

t

O

O

O

The Position –time graph

Positive

Acceleration

Zero Acceleration

Negative

Acceleration

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t

O

The velocity time graph

Object is moving in positive direction with positive acceleration

v0

v

t

O

v0

v

Object is moving in positive direction with negative acceleration

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t

O

Object is moving in negative direction with negative acceleration

-v0

-v

Object is moving with negative acceleration through out. Between 0 to t1 it moves + x-direction and between t1 to t2 it moves in opposite direction.

t2

O

v0

-v

t1

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Time (h)

Velocity(km)/h

0

1

2

3

4

10

20

30

40

o

B

c

A

Area under Velocity-time Graph.

Velocity -Time Graph for object moving with constant velocity.

Area under

Velocity-Time graph

=

Area of Rectangle OABC

v

t

= OA x OC

= v x t

Product of velocity and time is equal to displacement.

Area under Velocity –Time graph is always equal to the distance travelled by an object.

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t

0

E

B

C

t

v-v0

v0

v

D

A

Kinematic equations of uniformly accelerated motion

If the object is moving with constant acceleration then inst,acceleration is equal to av.acceleration

This is velocity-time relation

1.velocity-time relation

v = v0 +at

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t

0

E

B

C

t

v-v0

v0

v

D

A

2. Position -time relation

Area under v-t graph.

A = Ar.of Rec.OACD +Ar of Tri. ACB

A = (AO x OD)+ ½ (Ac x BC)

A = (v0 x t)+ ½ (v-v0) x t

A = v0t + ½ (v0 +at-v0) x t

A = v0t + ½ a t2

x = v0t + ½ a t2

x –x0= v0t + ½ a t2

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t

0

E

B

C

t

v-v0

v0

v

D

A

3. Position –velocity relation

Area under v-t graph.

Area of trapezium OABD

A = ½ x OD (OA +BD)

A = ½ x t (v0 +v)

A = ½ x (v-v0)/a x (v0 +v)

A = (v-v0)x (v + v0)/2a

A = (v2-v02)/2a

x = (v2-v02)/2a

x-x0 = (v2-v02)/2a

2a(x-x0 )= v2-v02

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Home work

  • 1.A ball thrown vertically upwards with a speed of 19.6 m/s from the top of the tower returns to the earth in 6 seconds. Find the height of the tower.
  • 2.A car moving along the straight highway with a speed of 126 km/h ,is brought to a stop within a distance of 200 m. What is the retardation of the car and how long does it take for the car to stop?

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Equations of motion by Calculus method

1. velocity-time relation.

Acceleration

Integrating on both sides

This is velocity-time relation.

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velocity

2. Position-time relation.

Integrating on both sides

This is Position-time relation.

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3.Velocity-Position relation.

Integrating on both sides

This is velocity-Position relation.

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Consider two objects A and B moving

uniformly with average velocities vA and vB along x-axis. If xA (0) and xB (0) are positions of objects A and B,respectively at time t = 0, their positions xA (t) and xB (t) at time t are given by:

xA (t ) = xA (0) + vA t --------1

xB (t) = xB (0) + vB t --------2

displacement of object B w.r.t. object A is

xBA(t) = xB (t) – xA (t)

xBA(t) = [ xB (0) – xA (0) ] + (vB – vA) t. ----3

Object B has a velocity vB – vA w.r.t. A

Relative velocity

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The velocity of object B relative to object A is vB – vA

vBA = vB – vA

The velocity of object A relative to object B is vA – vB

vAB = vA – vB

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O

20

40

60

80

100

120

140

X(m)

t(s)

O

20

40

60

80

100

120

140

t(s)

X(m)

1

2

3

4

5

6

1

2

3

4

5

6

A

B

A

B

vA = vB

vA – vB = 0

vB - vA = 0

The two objects stay at a constant distance

vA > vB

vB - vA is negative

Objects meet at a

common point

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O

20

40

60

80

100

120

140

t(s)

X(m)

1

2

3

4

5

6

A

B

vA and vB are of opposite signs.

In this case, the magnitude of vBA or vAB is

greater than the magnitude of velocity of A or

that of B