STATISTICS�IN �ECONOMICS
Presentation on
Arithmetic Mean
Prepared By
CHANDIGARH REGION
PGT
PREM JEET KUMAR BHATI
TOPIC �FOR �THE DAY
Arithmetic Mean
Objectives
The student will be able to:
* Find the meaning of arithmetic
mean.
* Find the application of formulas of arithmetic mean in different series.
* Students will able to make easy solutions of numerical practices of Arithmetic Mean.
����What is meant by Arithmetic Mean?��
The Arithmetic Mean is the Numerical Average of the data set
or a Series.
How do we find it ?
The mean is found by adding all the values in the Data Set/Series, then dividing the sum by the Number of values.
It is also known as Arithmetic Average.
Lets find MEAN score?
97
84
73
88
100
63
97
95
86
+
783
783
÷
9
The mean is 87
A trial example for you :-
there are…..
Find the Mean or Average Number of students in this JNV school……..
HINT :-
We need to find ……….
students.
classes.
Solution :-
Arithmetic Mean= Total Number Of Students
No of Classes
Types Of Mean
Simple Arithmetic Mean
Weighted Arithmetic Mean
Simple Arithmetic Mean
*All items of a series
are given equal importance.
Weighted Arithmetic Mean
*Different items of a series are
accorded different weights
in accordance with their
relative importance
Computation of Mean
Individual series
Discrete series
Continuous series
Methods for Computation
Direct Method
Short Cut Method
Step-deviation Method
Abbreviations � used in Computation of Mean
Formulae � Used in Computation of Mean
Types of Series | Direct Method | Shortcut Methods | Step deviation Methods |
Individual Series | | | |
Discrete series | | | |
Continuous Series | | | |
STATISTICS�IN �ECONOMICS
Presentation on
Median
Prepared By
CHANDIGARH REGION
PGT
PREM JEET KUMAR BHATI
TOPIC �FOR �THE DAY
Median
Objectives
The student will be able to:
* Find the meaning of median.
* Find the application of formulas of median in different series.
* Students will able to make easy solutions of numerical practices of Median.
What is the MEDIAN?�
The MEDIAN is the number that is in the middle of a set of data.
Median is what divides the score in the distribution into two equal parts.
50% lies below the median value and 50% lies above the median value.
It is also known as the middle score or the 50th percentile.
Median
Sounds like
MEDIUM
Think middle when you hear median.
Computation of Median
Individual series
Discrete series
Continuous series
Median Of Ungrouped Data
. Arrange the Scores ( From the
lowest to highest or highest
to lowest)
Determine the middle most score in a
distribution if n is an odd number and get
the average of two middle most scores if n is
an even number.
97
84
73
88
100
63
97
95
86
The median is 88.
Half the numbers are
less than the median.
Half the numbers are
greater than the median.
��How do we find the MEDIAN �When two numbers are in the middle of series ?� N is even number.
1. Add the two middle most numbers.
2. Then divide by 2.
97
84
73
88
100
63
97
95
88 + 95 = 183
183
÷
2
The median is
91.5
Median of Grouped Data
Discrete series :-
steps for……
1. Arrange the data in ascending or descending order.
2. Compute Cumulative frequency.
3.Apply the formula and locate the median at the size of items , in whose cumulative frequency the value of (n+1) the item lies.
2 Formula :- m = size of ( n+1)th item
2
Example :-
Calculate median (m) :-
Solution :-
m= size of n+1th item
2 M= 49+1 = 50
2 2
size of 25th item m=61
Income | 58 | 59 | 60 | 61 | 62 | 63 | 64 | 65 | 66 |
frequency | 2 | 3 | 6 | 15 | 10 | 5 | 4 | 3 | 1 |
Income | 58 | 59 | 60 | 61 | 62 | 63 | 64 | 65 | 66 |
frequency | 2 | 3 | 6 | 15 | 10 | 5 | 4 | 3 | 1 |
c. f. | 2 | 5 | 11 | 26 | 36 | 41 | 45 | 48 | 49 |
Median of Grouped Data
Continuous series :-
steps for……
1. Compute Cumulative frequency.
2. Obtain median group by applying formula (n) item.
2
3. Finally apply the formula 2nd formula.
Formula :-
m = l1 + N/2 – c.f. × i
f
Example :-
Calculate median (m) :-
Lets do this.....
Income | 100-120 | 120-140 | 140-160 | 160-180 | 180-200 |
frequency | 10 | 20 | 30 | 15 | 5 |
Computation of c.f.
MARKS | frequency | C.F. |
100-120 | 10 | 10 |
120-140 | 20 | 30 |
140-160 | 30 | 60 |
160-180 | 15 | 75 |
180-200 | 5 | 80 |
Applying formula
M = size of (N/2) item [ N= 80 ]
M = 80/2 = 40th item
40th item is located in class interval of 140-160
Now,
l1 = 140 , n/2 = 40 , c.f. =30, i = 20 , f = 30
M = 140+ 80/2 - 30 × 20
3 0 m = 140+6.67=146.67
M = 146.67
Properties of Median
Merits and Demerits of Median
Merits
Demerits
That is all in the part of Median
Thank you
STATISTICS�IN �ECONOMICS
Presentation on
Mode
Prepared By:
CHANDIGARH REGION
PGT
PREM JEET KUMAR BHATI
TOPIC FOR THE DAY
MODE
Hello Friends. I want to order shoes for my class students. But I don’t know what size?
Shall I order same size shoes for all students?
Can statistics help me in This?
Yes! Definitely, The Mode can help you in this decision.
Moooode?
What is Mode?
Mode is defined as the size of the variable or score which occurs most frequently..
Oooh!
I understood. First I will take all my students’ shoe No.
Here is the measurement.
5
5.5
6.5
6
5
6
6
7
6
5
5
6.5
7
5.5
5
Five is Most repeated shoe No. so Mode is 5.
Variable | 10 | 20 | 30 | 40 | 50 |
Frequency | 4 | 10 | 6 | 15 | 20 |
Example: Find the mode from the frequency distribution.
Calculating mode from the frequency distribution (Discrete Series)
In the above frequency distribution table, 50 occur maximum times with highest frequency 20. So the Mode will be 50.
Calculating mode from the frequency distribution (Continuous Series)
Formula:
Where, L = Lower limit of modal class
= Frequency of the group preceding the modal class
= Frequency of the modal class
= Frequency of the group succeeding the modal class� I = Magnitude or class interval of the modal class
Example: Gives the details different age group workers in a company. Compute the value of mode.
Class Interval | Frequency |
0-10 | 4 |
10-20 | 10 |
20-30 | 20 |
30-40 | 35 |
40-50 | 15 |
50-60 | 6 |
In above example the highest frequency is 35 so model class is 30-40. So:
L = lower limit of modal class = 30
f1 = frequency of modal class = 35
fo = frequency of class preceding the modal class. = 20
f2 = frequency of class higher than modal class = 15
I = size or width of class interval. = 10
OR 30 + 4.3 Or 34.43
So Mode = 34.43
By putting the values in the formula
Calculating mode from the frequency distribution (Continuous Series) Using Grouping Method: This method is used when highest frequencies are given more than once.
Grouping Process:
These frequency columns contain the following:
Column 1: It contains all the frequency values.
Column 2: We add frequencies in group of two values starting from first value of column 1.
Column 3: We add frequencies in group of two values starting from second value of column 1.
Column 4: We add frequencies in group of three values starting from first value of column 1.
Column 5: We add frequencies in group of three values starting from second value of column 1.
Column 6: We add frequencies in group of three values starting from third value of column 1.
Note: Highest value in all the columns are encircled or underlined, so the mode seems to change.
Example: Compute the value of mode from the following data using Grouping Method.
Class Interval | Frequency |
10-15 | 6 |
15-20 | 14 |
20-25 | 32 |
25-30 | 24 |
30-35 | 18 |
35-40 | 10 |
40-45 | 6 |
Solution: Calculation of mode with grouping table:
Class | Frequency (Column) | |||||
(1) | (2) | (3) | (4) | (5) | (6) | |
10-15 | 6 | ]20 | | ]52 | | |
15-20 | 14 | ]46 | ]70 | | ||
20-25 | 32 | ]56 | ]74 | |||
25-30 | 24 | ]42 | ]52 | |||
30-35 | 18 | ]28 | ]34 | |||
35-40 | 10 | ]16 | | |||
40-45 | 6 | | | | ||
Analysis Table
Column No. | 10-15 | 15-20 | 20-25 | 25-30 | 30-35 | 35-40 | 40-45 |
1 | - | - | 1 | - | - | - | - |
2 | - | - | 1 | 1 | - | - | - |
3 | - | 1 | 1 | - | - | - | - |
4 | 1 | 1 | 1 | 1 | 1 | 1 | - |
5 | - | 1 | 1 | 1 | - | - | - |
6 | - | - | 1 | 1 | 1 | - | - |
Total | 1 | 3 | 6 | 4 | 2 | 1 | 0 |
Solution:
Analysis table shows that the class interval 20-25 has been repeated all the six times ,so the mode lies in the class 20-25. Applying the formula we get:
In above example the highest frequency is 35 so model class is 30-40. So:
L = lower limit of modal class = 30
f1 = frequency of modal class = 35
fo = frequency of class preceding the modal class. = 20
f2 = frequency of class higher than modal class = 15
I = size or width of class interval. = 10
OR 20 + 3.46 Or 23.46
So Mode = 23.46
STATISTICS�IN �ECONOMICS
Presentation on
Partition values
Prepared By
CHANDIGARH REGION
PGT
PREM JEET KUMAR BHATI
TOPIC �FOR �THE DAY
Partition Values
Objectives
The student will be able to:
* Find the meaning of Partition
values.
* Find the application of formulas of
partition values in different series.
* Students will able to make easy solutions of numerical practices of Partition Values.
Partition Values
Partition values are
the values of a series
which divide the
data into a number
of equal points.
Some Partition Values are
Median :-
Median is a location value .
It also act as a partition
value, for it divides the
total frequency
into two equal parts
Quartile :-
75% of the items have values less than Q3.
Quartiles
25% | 25% | 25% | 25% |
Q1
Q2
Q3
Deciles :-
Percentile :-
Computation of Partition Values
Individual series
Discrete series
Continuous series
FORMULA FOR PARTITION VALUES
4
10
100
FORMULA FOR PARTITION VALUES
And so on...
4
10
100
lets take an Example....
In Discrete series :-
Find out 1st (Q1) and 3rd (Q3) quartile , 4th Deciles (D4) and 80th Percentile (P80)
Come ...lets solve it...
MARKS | 2 | 3 | 4 | 5 | 6 | 7 |
FREQUENCY | 2 | 3 | 9 | 21 | 11 | 5 |
Solution:-�Compute c.f. first.......
MARKS | FREQUENCY | C.F. |
2 | 2 | 2 |
3 | 3 | 5 |
4 | 9 | 14 |
5 | 21 | 35 |
6 | 11 | 46 |
7 | 5 | 51 |
Q1 = size of (N+1)item => 51+1
4
4
=
Size of 13th item
Size of 13th item lies in the c.f. 14,whose variable is 4
Thus , Q1 = 4
Q3= size of 3(N+1) item
4
3 (51+1)
4
= 39TH Item
=>
Size of 39th item lies in the c.f. 46,whose variable is 6
Thus , Q3 = 6
D4= size of 4(N+1) item
10
=>
4 (51+1)
10
= 20.8TH Item
Size of 20.8th item lies in the c.f. 35,whose variable is 5
Thus , D4 = 5
P80= size of 80 (N+1) item
100
=>
80 (51+1)
100
= 41.6TH Item
Size of 41.6th item lies in the c.f. 46,whose variable is 6
Thus , P80 = 6
Hence......you found
Partition values :-
Q1 = 4
Q3 = 6
D4 = 5
P80 = 6
Same Way........
With the same way you can find out Partition
Values in individual
series as well
as continuous
series easily...
That is all in the part of Partition Values
Thank you
THANKS