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QUADRATIC EQUATIONS

  • SDT sum based on Bicycle

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A man riding on a bicycle covers a distance of 60 km in a direction of wind and comes back to his original position in 8 hours. If the speed of the wind is 10 km/hr. Find the speed of the bicycle.

Sol.

SPEED

Let the speed of bicycle be x km/hr

SPEED

DISTANCE

TIME

= DISTANCE

SPEED

In the direction

of wind

Against the direction

of wind

60 km

(x + 10) km/hr

60

60 km

(x – 10) km/hr

60

x km/hr

10 km/hr

x km/hr

What we have to find in this sum ?

x + 10

x – 10

60 km

Speed in the direction of wind = (x + 10) km/hr

Speed against the direction of wind = (x – 10) km/hr

Total time taken = 8 hours

 

+

 

= 8

As per the given condition

homework

3 of 3

 

+

 

= 8

= 8

=

 

=

 

Dividing throughout by 2 we get,

 

=

 

 

=

 

 

=

 

 

=

 

 

=

 

 

=

 

 

=

 

 

 

=

 

 

 

 

 

 

 

The speed of the bicycle is 20 km/hr

1

‘-’ sign means subtracting

Find two factors of 100 in such a way that by subtracting factors we get middle number.

100 × 1 = 100

Since last sign is ‘-’ Give middle sign to the bigger factor & opposite sign to smaller factor.

20

5

100

-

+

 

60

 

 

 

 

 

 

 

 

 

 

2

15

 

 

 

 

 

 

 

A man riding on a bicycle cover a distance of 60 km in a direction of wind and comes back to his original position in 8 hours. If the speed of the wind is 10 km/hr. Find the speed of the bicycle.

Sol.

Let the speed of bicycle be x km/hr

As per the given condition