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12P08

Electromagnetic Waves

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12P08-Electromagnetic Waves

Learning Objectives

Displacement current

Electromagnetic waves

Electromagnetic spectrum

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12P08.1

Displacement current

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12P08.1 Displacement current

Learning Objectives

Maxwell’s argument

Maxwell’s experiment

Maxwell’s equation

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12P08.1

CV1

Maxwell’s arguments

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Motion of charge

Effects of motion of a charge

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Motion of charge

Effects of motion of a charge

Stationary

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Motion of charge

Effects of motion of a charge

Stationary

Electric field is generated

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Motion of charge

Effects of motion of a charge

Stationary

Electric field is generated

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Motion of charge

Effects of motion of a charge

Stationary

Moving with uniform motion

Electric field is generated

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Motion of charge

Effects of motion of a charge

Stationary

Moving with uniform motion

Magnetic field is generated

Electric field is generated

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Motion of charge

Effects of motion of a charge

Stationary

Moving with uniform motion

Magnetic field is generated

Electric field is generated

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Motion of charge

Effects of motion of a charge

Stationary

Moving with uniform motion

Accelerated

Magnetic field is generated

Electric field is generated

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Motion of charge

Effects of motion of a charge

EM Waves are generated

Stationary

Moving with uniform motion

Accelerated

Magnetic field is generated

Electric field is generated

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Maxwell’s argument

Current creates magnetic fields.

Hans Oersted

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Maxwell’s argument

Current creates magnetic fields.

Oersted's experiment

Hans Oersted

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Maxwell’s argument

Magnetic field changing with time gives rise to an electric field.

Michael Faraday

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Maxwell’s argument

Magnetic field changing with time gives rise to an electric field.

Faraday’s law

Michael Faraday

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Maxwell’s argument

Is the converse also true?

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Maxwell’s argument

Is the converse also true?

J.C. Maxwell

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Maxwell’s argument

Does the change in electric field create magnetic field?

J.C. Maxwell

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Maxwell’s argument

A time varying electric field can generate magnetic field.

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Maxwell’s argument

A time varying electric field can generate magnetic field.

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Maxwell’s argument

A time varying electric field can generate magnetic field.

Ic

Ic

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Maxwell’s argument

A time varying electric field can generate magnetic field.

Ic

Ic

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Maxwell’s argument

A time varying electric field can generate magnetic field.

Ic

Ic

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Maxwell’s argument

Electric field

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Maxwell’s argument

Electric field

Electric field changing with time gives rise to a magnetic field.

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Maxwell’s argument

Electric field

Magnetic field

Electric field changing with time gives rise to a magnetic field.

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Maxwell’s argument

Electric field

Magnetic field

Electric field changing with time gives rise to a magnetic field.

Magnetic field changing with time gives rise to an electric field.

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12P08.1

CV2

Maxwell’s Experiment

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Maxwell’s experiment (outside the capacitor)

Case 1:

Maxwell’s Experiment

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Maxwell’s experiment (outside the capacitor)

Case 1:

Parallel Plate

Capacitor

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Maxwell’s experiment (outside the capacitor)

Case 1:

Parallel Plate

Capacitor

Compass is outside

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Maxwell’s experiment (outside the capacitor)

Case 1:

Parallel Plate

Capacitor

Compass is outside

Compass gets deflected

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Maxwell’s experiment (outside the capacitor)

Case 1:

Parallel Plate

Capacitor

Compass is outside

Compass gets deflected

Magnetic field is present

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Maxwell’s experiment (outside the capacitor)

Apply Ampere’s law

Closed loop

Parallel Plate

Capacitor

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Maxwell’s experiment (outside the capacitor)

Apply Ampere’s law

Closed loop

Parallel Plate

Capacitor

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Maxwell’s experiment (outside the capacitor)

Apply Ampere’s law

Closed loop

Parallel Plate

Capacitor

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Maxwell’s experiment (outside the capacitor)

Apply Ampere’s law

Closed loop

Parallel Plate

Capacitor

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Maxwell’s experiment (inside the capacitor)

Case 2:

Maxwell’s Experiment

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Maxwell’s experiment (inside the capacitor)

Case 2:

Parallel Plate

Capacitor

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Maxwell’s experiment (inside the capacitor)

Case 2:

Parallel Plate

Capacitor

Compass is inside

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Maxwell’s experiment (inside the capacitor)

Case 2:

Parallel Plate

Capacitor

Compass is inside

Compass gets deflected

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Maxwell’s experiment (inside the capacitor)

Case 2:

Parallel Plate

Capacitor

Compass is inside

Compass gets deflected

Magnetic field is present

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Maxwell’s experiment (inside the capacitor)

Case 2:

Parallel Plate

Capacitor

Compass is inside

Compass gets deflected

Magnetic field is present

Current is present

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Maxwell’s experiment (inside the capacitor)

Apply Ampere’s law

Closed loop

4.31

Parallel Plate

Capacitor

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Maxwell’s experiment (inside the capacitor)

Apply Ampere’s law

Closed loop

4.31

Parallel Plate

Capacitor

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Maxwell’s experiment (inside the capacitor)

Apply Ampere’s law

Closed loop

Parallel Plate

Capacitor

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Maxwell’s experiment (inside the capacitor)

Apply Ampere’s law

Closed loop

Parallel Plate

Capacitor

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Maxwell’s experiment (Conclusion)

Change in electric field produces magnetic field which suggest presence of current that is called displacement current.

Ic

Ic

Parallel plate capacitor

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Maxwell’s experiment (Conclusion)

Change in electric field produces magnetic field which suggest presence of current that is called displacement current.

Ic

Ic

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Maxwell’s experiment (Conclusion)

Change in electric field produces magnetic field which suggest presence of current that is called displacement current.

Ic

Ic

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Maxwell’s experiment (Conclusion)

Change in electric field produces magnetic field which suggest presence of current that is called displacement current.

Id

Ic

Ic

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Displacement current

Using Gauss’s law flux passing through plates

Parallel Plate

Capacitor

Closed loop

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Displacement current

Using Gauss’s law flux passing through plates

Parallel Plate

Capacitor

Closed loop

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Displacement current

Using Gauss’s law flux passing through plates

Parallel Plate

Capacitor

Closed loop

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Displacement current

Using Gauss’s law flux passing through plates

Parallel Plate

Capacitor

Closed loop

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Displacement current

Using Gauss’s law flux passing through plates

Parallel Plate

Capacitor

Closed loop

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Displacement current

Using Gauss’s law flux passing through plates

Parallel Plate

Capacitor

Closed loop

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Displacement current

Parallel Plate

Capacitor

Closed loop

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Displacement current

Parallel Plate

Capacitor

Closed loop

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Displacement current

Parallel Plate

Capacitor

Closed loop

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Displacement current

Parallel Plate

Capacitor

Closed loop

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Displacement current

Parallel Plate

Capacitor

Closed loop

Id

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Displacement current

Total current

Parallel Plate

Capacitor

Closed loop

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Displacement current

Total current

Parallel Plate

Capacitor

Closed loop

Id = 0

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Displacement current

Total current

Parallel Plate

Capacitor

Closed loop

Id = 0

Ic = 0

Id = Ic

Id

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Displacement current

Maxwell Ampere’s law

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Displacement current

Maxwell Ampere’s law

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Displacement current

Maxwell Ampere’s law

Where Ic = Conduction current

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Displacement current

Maxwell Ampere’s law

Where Ic = Conduction current

Id = Displacement current

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Displacement current

Definition

Current flowing between the capacitor plates without motion of charges is called displacement current.

Displacement current between capacitor plates

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Displacement current

Definition

Current flowing between the capacitor plates without motion of charges is called displacement current.

Current arises due to changing of electric field.

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Displacement current

Definition

Current flowing between the capacitor plates without motion of charges is called displacement current.

Current arises due to changing of electric field.

Displacement current

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Displacement current

Definition

Current flowing between the capacitor plates without motion of charges is called displacement current.

Current arises due to changing of electric field.

Displacement current

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Displacement current

Definition

Current flowing between the capacitor plates without motion of charges is called displacement current.

Current arises due to changing of electric field.

Displacement current

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ConcepTest

Ready for challenge

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Q. The charge on a parallel plate capacitor varies as . The plates are very large and close together (Area = A, Separation = d). Neglecting the edge effect find the displacement current through the capacitor?

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Q. The charge on a parallel plate capacitor varies as . The plates are very large and close together (Area = A, Separation = d). Neglecting the edge effect find the displacement current through the capacitor?

Pause video

(Time duration : 2 minutes)

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Sol.

Parallel plate capacitor

Plate area (A)

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Sol. Displacement current

Plate area (A)

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Sol. Displacement current

Electric field

Plate area (A)

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Sol. Displacement current

Electric field

Plate area (A)

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Sol. Displacement current

Electric field

Plate area (A)

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Sol. Displacement current

Electric field

Plate area (A)

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Sol. Displacement current

Electric field

Plate area (A)

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Sol. Displacement current

Electric field

Plate area (A)

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Sol. Displacement current

Electric field

Plate area (A)

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12P08.1

CV3

Maxwell’s Equation

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Maxwell’s Equation

  1. (Gauss’s Law for electrostatics)

Electric field exists due to charge.

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Maxwell’s Equation

  1. (Gauss’s Law for electrostatics)

Electric field exists due to charge.

2. (Gauss’s Law for magnetism)

Magnetic field lines form closed loop.

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Maxwell’s Equation

3. (Faraday’s Law)

Electric field is generated due to change of magnetic field.

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Maxwell’s Equation

3. (Faraday’s Law)

Electric field is generated due to change of magnetic field.

4. (Maxwell-Ampere’s Law)

Magnetic field generates due to change of electric field.

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Reference Questions

NCERT : Ex 8.1

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12P08.1

PSV 1

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Q. Figure shows a capacitor made of two circular plate each of radius 12 cm , and separated by 5.0 cm . The capacitor is being charged by an external source (not shown in figure). The charging current is constant and equal to 0.15 A .

Parallel plate capacitor

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Q. Figure shows a capacitor made of two circular plate each of radius 12 cm , and separated by 5.0 cm . The capacitor is being charged by an external source (not shown in figure). The charging current is constant and equal to 0.15 A .

  1. Calculate the capacitance and the rate of change of potential difference between the plates.

Parallel plate capacitor

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Q. Figure shows a capacitor made of two circular plate each of radius 12 cm , and separated by 5.0 cm . The capacitor is being charged by an external source (not shown in figure). The charging current is constant and equal to 0.15 A .

  1. Calculate the capacitance and the rate of change of potential difference between the plates.
  2. Obtain the displacement current across the plates.

Parallel plate capacitor

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Q. Figure shows a capacitor made of two circular plate each of radius 12 cm , and separated by 5.0 cm . The capacitor is being charged by an external source (not shown in figure). The charging current is constant and equal to 0.15 A .

  1. Calculate the capacitance and the rate of change of potential difference between the plates.
  2. Obtain the displacement current across the plates.
  3. Is Kirchhoff's first rule valid at each plate of the capacitor ? Explain it.

Parallel plate capacitor

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Sol.

  1. Capacitance of the Parallel plate capacitor

Separation d = 5 cm

Radius of plate r = 12 cm

Parallel plate capacitor

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Sol.

  1. Capacitance of the Parallel plate capacitor

Separation d = 5 cm

Radius of plate r = 12 cm

Parallel plate capacitor

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Sol.

  1. Capacitance of the Parallel plate capacitor

Separation d = 5 cm

Radius of plate r = 12 cm

Parallel plate capacitor

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Sol.

  1. Capacitance of the Parallel plate capacitor

Separation d = 5 cm

Radius of plate r = 12 cm

Parallel plate capacitor

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Sol.

  1. Capacitance of the Parallel plate capacitor

Separation d = 5 cm

Radius of plate r = 12 cm

Parallel plate capacitor

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Rate of change of potential difference = = ?

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Rate of change of potential difference = = ?

Given

I = 0.15 A

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Rate of change of potential difference = = ?

Given

I = 0.15 A

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Rate of change of potential difference = = ?

Given

I

I = 0.15 A

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Rate of change of potential difference = = ?

Given

I

I

I = 0.15 A

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Rate of change of potential difference = = ?

Given

I

I

I

I = 0.15 A

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  1. Displacement current

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  1. Displacement current

Given

I = 0.15 A

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  1. Displacement current

Given

I = 0.15 A

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  1. Displacement current

Given

I = 0.15 A

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  1. Displacement current

Given

I = 0.15 A

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  1. Displacement current

Given

I = 0.15 A

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  1. Displacement current

Given

I

= Id

0.15 A

I = 0.15 A

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  1. Is Kirchhoff's first rule valid at each plate of the capacitor ? Explain it.

Yes, kirchoff’s law is valid at each plate of capacitor.

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  1. Is Kirchhoff's first rule valid at each plate of the capacitor ? Explain it.

Yes, kirchoff’s law is valid at each plate of capacitor.

As we know that kirchoff’s law states that algebraic sum of currents at any junction of circuit must be zero.

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  1. Is Kirchhoff's first rule valid at each plate of the capacitor ? Explain it.

Yes, kirchoff’s law is valid at each plate of capacitor.

As we know that kirchoff’s law states that algebraic sum of currents at any junction of circuit must be zero.

At point A apply kirchoff’s law

Ic

Ic

Id

A

Parallel plate capacitor

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  1. Is Kirchhoff's first rule valid at each plate of the capacitor ? Explain it.

Yes, kirchoff’s law is valid at each plate of capacitor.

As we know that kirchoff’s law states that algebraic sum of currents at any junction of circuit must be zero.

At point A apply kirchoff’s law

Ic

Ic

Id

A

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  1. Is Kirchhoff's first rule valid at each plate of the capacitor ? Explain it.

Yes, kirchoff’s law is valid at each plate of capacitor.

As we know that kirchoff’s law states that algebraic sum of currents at any junction of circuit must be zero.

At point A apply kirchoff’s law

Ic

Ic

Id

A

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  1. Is Kirchhoff's first rule valid at each plate of the capacitor ? Explain it.

Yes, kirchoff’s law is valid at each plate of capacitor.

As we know that kirchoff’s law states that algebraic sum of currents at any junction of circuit must be zero.

At point A apply kirchoff’s law

Ic

Ic

Id

A

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Summary

  • Displacement current has same effect as the conduction current.
  • The displacement current may be zero since the electric field does not change with time.
  • In charging capacitor both the displacement and conduction current may be present in different regions of space.
  • Electric field changing with time gives rise to magnetic field and consequently displacement current is the source of magnetic field.
  • Displacement current is given as

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12P08.2

Electromagnetic Waves

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12P08.2 Electromagnetic waves

Learning Objectives

What is EM Waves

Source and Nature of EM Waves

Properties of EM Waves

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12P08.2

CV1

What is EM Waves

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What is EM Waves

What is Wave?

Disturbance that travels through a medium or without medium, transporting energy from one location to another location without transporting medium.

Wave

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What is EM Waves

Types of waves

  1. Longitudinal Waves:- Particle of waves are displaced along the direction of propagation of wave.

130

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What is EM Waves

Types of waves

  1. Longitudinal Waves:- Particle of waves are displaced along the direction of propagation of wave.

Example : Sound waves

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Longitudinal wave

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What is EM Waves

  1. Transverse Waves:- Particles of waves are displaced perpendicular to the direction of propagation.

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What is EM Waves

  1. Transverse Waves:- Particles of waves are displaced perpendicular to the direction of propagation.

Example : Waves of guitar’s string

Transverse wave

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What is EM Waves

Definition of Electromagnetic waves

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What is EM Waves

Definition of Electromagnetic waves

Electric field, magnetic field and direction of propagation of wave are mutually perpendicular.

Propagation direction

Z

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What is EM Waves

Definition of Electromagnetic waves

Electric field, magnetic field and direction of propagation of wave are mutually perpendicular.

Electromagnetic waves are non material waves.

Propagation direction

Z

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What is EM Waves

Definition of Electromagnetic waves

Electric field, magnetic field and direction of propagation of wave are mutually perpendicular.

Electromagnetic waves are non material waves.

Z

Y

X

Z

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What is EM Waves

How EM Waves are produced?

An accelerated or oscillated charge generates EM Waves.

138

ret

Y

X

Z

Z

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What is EM Waves

http://www.mysearch.org.uk/website1/images/animations/472.emwave.gif

Oscillating Charge

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What is EM Waves

http://www.mysearch.org.uk/website1/images/animations/472.emwave.gif

Oscillating Charge

Oscillating Electric Field

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What is EM Waves

http://www.mysearch.org.uk/website1/images/animations/472.emwave.gif

Oscillating Charge

Oscillating Magnetic Field

Oscillating Electric Field

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What is EM Waves

http://www.mysearch.org.uk/website1/images/animations/472.emwave.gif

Oscillating Charge

Oscillating Electric Field

Oscillating Magnetic Field

Oscillating Electric Field

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What is EM Waves

Oscillating Electric Field

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What is EM Waves

Oscillating Magnetic Field

Oscillating Electric Field

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What is EM Waves

Oscillating magnetic field

Oscillating electric field

EM Waves

Oscillating Magnetic Field

Oscillating Electric Field

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ConcepTest

Ready for challenge

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Q. A plane EM Waves travels in vacuum along z - direction. What can you say about the directions of its electric and magnetic field vectors?

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Q. A plane EM Waves travels in vacuum along z - direction. What can you say about the directions of its electric and magnetic field vectors?

Pause video

(Time duration : 2 minutes)

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Q. A plane EM Waves travels in vacuum along z - direction. What can you say about the directions of its electric and magnetic field vectors?

Sol. Electric field and magnetic field are in x-y plane and perpendicular to each other as shown below in figure.

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Q. A plane EM Waves travels in vacuum along z - direction. What can you say about the directions of its electric and magnetic field vectors?

Sol. Electric field and magnetic field are in x-y plane and perpendicular to each other as shown below in figure.

Z

X

Y

Propagation direction

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Q. A plane EM Waves travels in vacuum along z - direction. What can you say about the directions of its electric and magnetic field vectors?

Sol. Electric field and magnetic field are in x-y plane and perpendicular to each other as shown below in figure.

E or B

B or E

Velocity of wave

Z

X

Y

X

Y

Z

Propagation direction

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12P08.2

CV2

Source and Nature of EM Waves

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Source and Nature of EM Waves

Source of Electromagnetic waves:

Source of electromagnetic wave is a vibrating or accelerating charge or oscillating charge.

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Source and Nature of EM Waves

Source of Electromagnetic waves:

Source of electromagnetic wave is a vibrating or accelerating charge or oscillating charge.

Change in Electric Field

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Source and Nature of EM Waves

Source of Electromagnetic waves:

Source of electromagnetic wave is a vibrating or accelerating charge or oscillating charge.

Change in Electric Field

Change in Magnetic Field

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Source and Nature of EM Waves

Source of Electromagnetic waves:

Source of electromagnetic wave is a vibrating or accelerating charge or oscillating charge.

Change in Electric Field

Change in Magnetic Field

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Source and Nature of EM Waves

Nature of EM Waves

EM Waves are transverse and non material waves .

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Source and Nature of EM Waves

Equation of electromagnetic waves

Representation of EMW

Z

Propagation direction

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Source and Nature of EM Waves

Equation of electromagnetic waves

Z

Propagation direction

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Source and Nature of EM Waves

Equation of electromagnetic waves

Z

Propagation direction

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Source and Nature of EM Waves

Equation of electromagnetic waves

Here ⍵ = angular frequency(rad/sec)

Z

Propagation direction

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Source and Nature of EM Waves

Equation of electromagnetic waves

Here ⍵ = angular frequency(rad/sec)

k = magnitude of wave vector

Z

Propagation direction

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Source and Nature of EM Waves

Equation of electromagnetic waves

Here ⍵ = angular frequency(rad/sec)

k = magnitude of wave vector

λ = wavelength of EMWs

Z

Propagation direction

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Source and Nature of EM Waves

Equation of electromagnetic waves

Here ⍵ = angular frequency(rad/sec)

k = magnitude of wave vector

λ = wavelength of EMWs

z = propagation direction

Z

Propagation direction

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Source and Nature of EM Waves

Equation of electromagnetic waves

Here ⍵ = angular frequency(rad/sec)

k = magnitude of wave vector

λ = wavelength of EMWs

z = propagation direction

t = specific time

Z

Propagation direction

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Source and Nature of EM Waves

c = speed of electromagnetic wave = speed of light = 3 × 108 m/sec

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Source and Nature of EM Waves

Magnitude of wave propagation vector

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Source and Nature of EM Waves

Relationship between permittivity ( 𝟄0 ) of free space and magnetic permeability of free space ( 𝝻0 )

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Source and Nature of EM Waves

For any other material the velocity of EM Waves

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Source and Nature of EM Waves

For any other material the velocity of EM Waves

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Source and Nature of EM Waves

For any other material the velocity of EM Waves

Where 𝟄 and 𝝻 are permittivity and permeability of material respectively.

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ConcepTest

Ready for challenge

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Q. The source of EM Waves can be a charge

  1. Moving with a constant velocity
  2. Moving in a circular orbit
  3. At rest
  4. Falling in an electric field

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Q. The source of EM Waves can be a charge

  1. Moving with a constant velocity
  2. Moving in a circular orbit
  3. At rest
  4. Falling in an electric field

Pause video

(Time duration : 2 minutes)

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Q. The source of EM Waves can be a charge

  1. Moving with a constant velocity
  2. Moving in a circular orbit
  3. At rest
  4. Falling in an electric field

Sol.

(b) Moving in a circular orbital ( In circular motion a particle is having centripetal acceleration so it can be a source of EM Waves )

(d) Falling in an electric field (In electric field a charge particle is experienced force so that it gets accelerated, so it can be a source EM Waves)

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ConcepTest

Ready for challenge

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Q. Which physical quantity is same for X- rays of wavelength 10 -10 m , red light of wavelength 6800 Å and radio waves of wavelength 500 m ?

  1. Velocity
  2. Frequency
  3. Amplitude
  4. acceleration

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Q. Which physical quantity is same for X- rays of wavelength 10 -10 m , red light of wavelength 6800 Å and radio waves of wavelength 500 m ?

  1. Velocity
  2. Frequency
  3. Amplitude
  4. acceleration

Pause video

(Time duration : 2 minutes)

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Q. Which physical quantity is same for X- rays of wavelength 10 -10 m , red light of wavelength 6800 Å and radio waves of wavelength 500 m ?

Sol.

  1. Velocity

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ConcepTest

Ready for challenge

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Q. A radio can tune in to any station in the 7.5 MHz to 12 MHz band. What is the corresponding wavelength band?

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Q. A radio can tune in to any station in the 7.5 MHz to 12 MHz band. What is the corresponding wavelength band?

Pause video

(Time duration : 2 minutes)

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Q. A radio can tune in to any station in the 7.5 MHz to 12 MHz band. What is the corresponding wavelength band?

Sol. We know that

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Q. A radio can tune in to any station in the 7.5 MHz to 12 MHz band. What is the corresponding wavelength band?

Sol. We know that

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Q. A radio can tune in to any station in the 7.5 MHz to 12 MHz band. What is the corresponding wavelength band?

Sol. We know that

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Q. A radio can tune in to any station in the 7.5 MHz to 12 MHz band. What is the corresponding wavelength band?

Sol. We know that

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Q. A radio can tune in to any station in the 7.5 MHz to 12 MHz band. What is the corresponding wavelength band?

Sol. We know that

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Q. A radio can tune in to any station in the 7.5 MHz to 12 MHz band. What is the corresponding wavelength band?

Sol. We know that

So that corresponding wavelength band 40 m to 25 m.

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ConcepTest

Ready for challenge

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Q. A charged particle oscillates about its mean equilibrium position with a frequency of 109 Hz. what is the frequency of the electromagnetic waves produced by the oscillator?

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Q. A charged particle oscillates about its mean equilibrium position with a frequency of 109 Hz. what is the frequency of the electromagnetic waves produced by the oscillator?

Pause video

(Time duration : 2 minutes)

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Q. A charged particle oscillates about its mean equilibrium position with a frequency of 109 Hz. what is the frequency of the electromagnetic waves produced by the oscillator?

Sol. Frequency of Electromagnetic wave must be equal to the frequency of oscillation of charged particle.

So frequency of EM Waves is 10 9 Hz.

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12P08.2

CV3

Properties of EM Waves

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Properties of EM Waves

Electromagnetic waves are transverse in nature.Properties of EMWs

Transverse wave

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Properties of EM Waves

Speed of EM Waves is equal to the speed of light.

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Properties of EM Waves

Speed of EM Waves is equal to the speed of light.

c = speed of wave in vacuum = 3 × 10 8 m/s

Characteristics of EMW

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Properties of EM Waves

Speed of EM Waves is equal to the speed of light.

c = speed of wave in vacuum = 3 × 10 8 m/s

λ = wavelength of EM Waves

Characteristics of EMW

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Properties of EM Waves

Speed of EM Waves is equal to the speed of light.

c = speed of wave in vacuum = 3 × 10 8 m/s

λ = wavelength of EM Waves

A = amplitude of wave

Characteristics of EMW

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Properties of EM Waves

Speed of EM Waves is equal to the speed of light.

c = speed of wave in vacuum = 3 × 10 8 m/s

λ = wavelength of EM Waves

A = amplitude of wave

𝝂 = frequency of wavelength

Characteristics of EMW

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Properties of EM Waves

Velocity of EM Waves

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Properties of EM Waves

Relationship between magnitude of electric field and magnetic field

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Properties of EM Waves

Relationship between magnitude of electric field and magnetic field

Where E0 = Maximum value of electric field

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Properties of EM Waves

Relationship between magnitude of electric field and magnetic field

Where E0 = Maximum value of electric field

B0 = Maximum value of magnetic field

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Properties of EM Waves

Poynting vector:- The rate of flow of energy in an electromagnetic wave per unit area per unit second is called poynting vector.

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Properties of EM Waves

Poynting vector:- The rate of flow of energy in an electromagnetic wave per unit area per unit second is called poynting vector.

Representation of poynting vector

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Properties of EM Waves

Poynting vector:- The rate of flow of energy in an electromagnetic wave per unit area per unit second is called poynting vector.

Representation of poynting vector in circuit

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Properties of EM Waves

Poynting vector:- The rate of flow of energy in an electromagnetic wave per unit area per unit second is called poynting vector.

Representation of poynting vector in circuit

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Properties of EM Waves

Poynting vector:- The rate of flow of energy in an electromagnetic wave per unit area per unit second is called poynting vector.

SI Unit of S is watt / m2.

Representation of poynting vector in circuit

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Properties of EM Waves

The electric vector is responsible for optical effect of electromagnetic waves.

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Properties of EM Waves

The electric vector is responsible for optical effect of electromagnetic waves.

Because moving particle oscillates primarily due to the electric field.

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Properties of EM Waves

The energy in an electromagnetic wave is equally divided in electric vector and magnetic vector.

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Properties of EM Waves

The energy in an electromagnetic wave is equally divided in electric vector and magnetic vector.

Energy distribution in EMWs

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Properties of EM Waves

The Average energy density of electric field

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Properties of EM Waves

The Average energy density of magnetic field

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Properties of EM Waves

Intensity of EM Waves is defined as the energy crossing per unit area per unit time perpendicular to the propagation of electromagnetic wave.

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Properties of EM Waves

Intensity of EMWs is defined as the energy crossing per unit area per unit time perpendicular to the propagation of electromagnetic wave.

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Properties of EM Waves

The existence of EM Waves was confirmed by Hertz in 1888.

Heinrich hertz

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Properties of EM Waves

Total momentum delivered to surface by EM Waves

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Properties of EM Waves

Total momentum delivered to surface by EM Waves

p = Total momentum delivered

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Properties of EM Waves

Total momentum delivered to surface by EM Waves

p = Total momentum delivered

U = Total energy of EM Waves

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Properties of EM Waves

Total momentum delivered to surface by EM Waves

p = Total momentum delivered

U = Total energy of EM Waves

c = Speed of light

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ConcepTest

Ready for challenge

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Q. The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is 510 nT. What is the amplitude of the electric field part of the wave?

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Q. The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is 510 nT. What is the amplitude of the electric field part of the wave?

Pause video

(Time duration : 2 minutes)

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Q. The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is 510 nT. What is the amplitude of the electric field part of the wave?

Sol. Given

B0 = 510 nT

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Q. The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is 510 nT. What is the amplitude of the electric field part of the wave?

Sol. Given

B0 = 510 nT

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Q. The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is 510 nT. What is the amplitude of the electric field part of the wave?

Sol. Given

B0 = 510 nT

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Q. The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is 510 nT. What is the amplitude of the electric field part of the wave?

Sol. Given

B0 = 510 nT

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Q. The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is 510 nT. What is the amplitude of the electric field part of the wave?

Sol. Given

B0 = 510 nT

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Reference Questions

NCERT : Example 8.2, 8.3, 8.4, 8.5

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12P08.2

PSV 2

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Q. Suppose that the electric field amplitude of an electromagnetic wave is E0 = 120 N/C and that its frequency is f = 50 MHz.

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Q. Suppose that the electric field amplitude of an electromagnetic wave is E0 = 120 N/C and that its frequency is f = 50 MHz.

  1. Determine B0, 𝟂, k and λ.

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Q. Suppose that the electric field amplitude of an electromagnetic wave is E0 = 120 N/C and that its frequency is f = 50 MHz.

  1. Determine B0, 𝟂, k and λ.
  2. Find expression for E and B.

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Q. Suppose that the electric field amplitude of an electromagnetic wave is E0 = 120 N/C and that its frequency is f = 50 MHz.

  1. Determine B0, 𝟂, k and λ.
  2. Find expression for E and B.

Pause video

(Time duration : 2 minutes)

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Sol.

  1. Magnitude of magnetic field vector

Given

E0 = 120 N/C

f = 50 MHz

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Sol.

  1. Magnitude of magnetic field vector

Given

E0 = 120 N/C

f = 50 MHz

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Sol.

  1. Magnitude of magnetic field vector

Given

E0 = 120 N/C

f = 50 MHz

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Sol.

  1. Magnitude of magnetic field vector

Given

E0 = 120 N/C

f = 50 MHz

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Sol.

  1. Magnitude of magnetic field vector

Given

E0 = 120 N/C

f = 50 MHz

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Sol.

Angular frequency

Given

E0 = 120 N/C

f = 50 MHz

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Sol.

Angular frequency

Given

E0 = 120 N/C

f = 50 MHz

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Sol.

Angular frequency

Given

E0 = 120 N/C

f = 50 MHz

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Sol.

Angular frequency

Given

E0 = 120 N/C

f = 50 MHz

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Sol. Wavelength

Given

E0 = 120 N/C

f = 50 MHz

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Sol. Wavelength

Given

E0 = 120 N/C

f = 50 MHz

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Sol. Wavelength

Given

E0 = 120 N/C

f = 50 MHz

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Sol. Wavelength

Given

E0 = 120 N/C

f = 50 MHz

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Sol. Magnitude of propagation vector

Given

E0 = 120 N/C

f = 50 MHz

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Sol. Magnitude of propagation vector

Given

E0 = 120 N/C

f = 50 MHz

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Sol. Magnitude of propagation vector

Given

E0 = 120 N/C

f = 50 MHz

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Sol. Magnitude of propagation vector

Given

E0 = 120 N/C

f = 50 MHz

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E0 = 120 N/C

f = 50 MHz

Sol.

(b) Expression of electric field

Given

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Sol.

(b) Expression of electric field

Given

E0 = 120 N/C

f = 50 MHz

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Sol.

(b) Expression of electric field

Given

E0 = 120 N/C

f = 50 MHz

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Sol.

Expression of magnetic field

Given

E0 = 120 N/C

f = 50 MHz

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Sol.

Expression of magnetic field

Given

E0 = 120 N/C

f = 50 MHz

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Sol.

Expression of magnetic field

Given

E0 = 120 N/C

f = 50 MHz

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12P08.2

PSV 3

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Q. A parallel plate capacitor made of circular plates each of radius R = 6 cm has a capacitance C = 100 pF. The capacitor is connected to a 230 V AC supply with an angular frequency of 300 rad / sec .

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Q. A parallel plate capacitor made of circular plates each of radius R = 6 cm has a capacitance C = 100 pF. The capacitor is connected to a 230 V AC supply with an angular frequency of 300 rad / sec .

  1. What is the rms value of the conduction current?

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Q. A parallel plate capacitor made of circular plates each of radius R = 6 cm has a capacitance C = 100 pF. The capacitor is connected to a 230 V AC supply with an angular frequency of 300 rad / sec .

  1. What is the rms value of the conduction current?
  2. Is the conduction equal to the displacement current?

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Sol. Given

radius R = 6 cm

C = 100 pF

𝞈 = 300 rad / sec

Vrms= 230 V

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Sol. Given

We know that for an LC circuit

radius R = 6 cm

C = 100 pF

𝞈 = 300 rad / sec

Vrms= 230 V

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Sol. Given

We know that for an LC circuit

radius R = 6 cm

C = 100 pF

𝞈 = 300 rad / sec

Vrms= 230 V

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Sol. Given

We know that for an LC circuit

radius R = 6 cm

C = 100 pF

𝞈 = 300 rad / sec

Vrms= 230 V

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Sol. Given

We know that for an LC circuit

radius R = 6 cm

C = 100 pF

𝞈 = 300 rad / sec

Vrms= 230 V

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Sol. Given

We know that for an LC circuit

radius R = 6 cm

C = 100 pF

𝞈 = 300 rad / sec

Vrms= 230 V

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(b) Is the conduction equal to the displacement current?

Sol.

  1. Yes, because from the formula of displacement current, we can get conduction current without changing the dimension.

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12P08.2

PSV 4

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Q. In a plane electromagnetic wave, the electric field oscillates sinusoidally at a frequency of 2.0 × 10 10 Hz and amplitude 48 V/m.

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Q. In a plane electromagnetic wave, the electric field oscillates sinusoidally at a frequency of 2.0 × 10 10 Hz and amplitude 48 V/m.

  1. What is the wavelength of the wave?

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Q. In a plane electromagnetic wave, the electric field oscillates sinusoidally at a frequency of 2.0 × 10 10 Hz and amplitude 48 V/m.

  1. What is the wavelength of the wave?
  2. What is the amplitude of the oscillating magnetic field?

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Q. In a plane electromagnetic wave, the electric field oscillates sinusoidally at a frequency of 2.0 × 10 10 Hz and amplitude 48 V/m.

  1. What is the wavelength of the wave?
  2. What is the amplitude of the oscillating magnetic field?
  3. Show that the average energy density of the E field equals the average energy density of the B field. [c = 3 × 10 8 m s-1 ]

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Sol.

  1. Wavelength

Given

𝜈 = 2.0 × 10 10

E0 = 48 V/m

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Sol.

  1. Wavelength

Given

𝜈 = 2.0 × 10 10

E0 = 48 V/m

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Sol.

  1. Wavelength

Given

𝜈 = 2.0 × 10 10

E0 = 48 V/m

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Sol.

  1. Wavelength

Given

𝜈 = 2.0 × 10 10

E0 = 48 V/m

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Sol.

  1. Amplitude of magnetic field vector

Given

𝜈 = 2.0 × 10 10

E0 = 48 V/m

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Sol.

  1. Amplitude of magnetic field vector

Given

𝜈 = 2.0 × 10 10

E0 = 48 V/m

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Sol.

  1. Amplitude of magnetic field vector

Given

𝜈 = 2.0 × 10 10

E0 = 48 V/m

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Sol.

  1. Amplitude of magnetic field vector

Given

𝜈 = 2.0 × 10 10

E0 = 48 V/m

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Sol.

  1. Amplitude of magnetic field vector

Given

𝜈 = 2.0 × 10 10

E0 = 48 V/m

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Sol. (c) Energy density in electric field

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Sol. (c) Energy density in electric field

Energy density

in magnetic field

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Sol. (c) Energy density in electric field

Energy density

in magnetic field

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Sol. (c) Energy density in electric field

Energy density

in magnetic field

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Sol. (c) Energy density in electric field

Energy density

in magnetic field

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Sol. (c) Energy density in electric field

Energy density

in magnetic field

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Sol. (c) Energy density in electric field

Energy density

in magnetic field

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Sol. (c) Energy density in electric field

Energy density

in magnetic field

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Sol. (c) Energy density in electric field

Energy density

in magnetic field

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Summary

  • EM Waves are non material waves and transverse in nature.
  • EM Waves travel at the speed of light.
  • EM Waves are in sinusoidal form.
  • EM Waves are produced due to vibrating or accelerating or oscillating charges.
  • Expression of electric field
  • Expression of magnetic field
  • Speed of EM Waves

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12P08.3

Electromagnetic Spectrum

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12P08.3 Electromagnetic Spectrum

Learning objectives

What is EM Spectrum?

Classification of EM Waves

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12P08.3

CV1

What is EM Spectrum

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What is EM spectrum

The arrange array of electromagnetic radiation in the sequence of their wavelength or frequency is called Electromagnetic spectrum.

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What is EM spectrum

The arrange array of electromagnetic radiation in the sequence of their wavelength or frequency is called Electromagnetic spectrum.

This consists electromagnetic energy ranging from Gamma Rays to Radio waves.

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What is EM spectrum

Electromagnetic spectrum

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What is EM spectrum

Radio Waves

Microwave Waves

Infrared Waves

Visible Rays

UV Rays

X-Rays

Gamma Rays

Relationship between Energy, Wavelength and Frequency for Electromagnetic spectrum

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What is EM spectrum

Radio Waves

Microwave Waves

Infrared Waves

Visible Rays

UV Rays

X-Rays

Gamma Rays

Wavelength (λ)

Relationship between Energy, Wavelength and Frequency for Electromagnetic spectrum

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What is EM spectrum

Radio Waves

Microwave Waves

Infrared Waves

Visible Rays

UV Rays

X-Rays

Gamma Rays

Wavelength (λ)

Energy (E)

Relationship between Energy, Wavelength and Frequency for Electromagnetic spectrum

Wavelength (λ)

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What is EM spectrum

Radio Waves

Microwave Waves

Infrared Waves

Visible Rays

UV Rays

X-Rays

Gamma Rays

Wavelength (λ)

Energy (E)

Frequency (f)

Relationship between Energy, Wavelength and Frequency for Electromagnetic spectrum

Wavelength (λ)

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Memory based question

Ready for challenge

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Q. Which electromagnetic wave has the shortest wavelength and highest frequency ?

  1. Gamma rays
  2. Radio waves
  3. X-rays
  4. Ultraviolet rays

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Q. Which electromagnetic wave has the shortest wavelength and highest frequency ?

  1. Gamma rays
  2. Radio waves
  3. X-rays
  4. Ultraviolet rays

Pause video

(Time duration : 2 minutes)

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Q. Which electromagnetic wave has the shortest wavelength and highest frequency ?

  1. Gamma rays
  2. Radio waves
  3. X-rays
  4. Ultraviolet rays

Sol.

  1. Gamma rays

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Memory based question

Ready for challenge

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Q. Electromagnetic waves that you can see are called

  1. Infrared rays
  2. Microwaves
  3. X-rays
  4. Visible light

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Q. Electromagnetic waves that you can see are called

  1. Infrared rays
  2. Microwaves
  3. X-rays
  4. Visible light

Pause video

(Time duration : 2 minutes)

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Q. Electromagnetic waves that you can see are called

  1. Infrared rays
  2. Microwaves
  3. X-rays
  4. Visible light

Sol.

  1. Visible light

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Memory based question

Ready for challenge

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Q. Longest wavelength of spectrum

  1. Radio waves
  2. Ultraviolet rays
  3. Visible light
  4. Microwaves

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Q. Longest wavelength of spectrum

  1. Radio waves
  2. Ultraviolet rays
  3. Visible light
  4. Microwaves

Pause video

(Time duration : 2 minutes)

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Q. Longest wavelength of spectrum

  1. Radio waves
  2. Ultraviolet rays
  3. Visible light
  4. Microwaves

Sol.

  1. Radio waves

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Memory based question

Ready for challenge

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Q. Which colour has the shortest wavelength in visible light?

  1. Red
  2. Violet
  3. Blue
  4. Green

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Q. Which colour has the shortest wavelength in visible light?

  1. Red
  2. Violet
  3. Blue
  4. Green

Pause video

(Time duration : 2 minutes)

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Q. Which colour has the shortest wavelength in visible light?

  1. Red
  2. Violet
  3. Blue
  4. Green

Sol.

  1. Violet

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12P08.3

CV2

Classification of EM Spectrum

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Classification of EM Waves

  1. Radio waves

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Classification of EM Waves

  1. Radio waves

Production - Due to accelerated charge in wire or antena

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Classification of EM Waves

  1. Radio waves

Production - Due to accelerated charge in wire or antena

Wavelength range - Greater than 0.1 m

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Classification of EM Waves

  1. Radio waves

Production - Due to accelerated charge in wire or antena

Wavelength range - Greater than 0.1 m

Detection- Receiver’s Aerial

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Classification of EM Waves

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Classification of EM Waves

Application of Radio waves

Radio waves are used in radio and television communication systems.

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Classification of EM Waves

Application of Radio waves

Radio waves are used in radio and television communication systems.

Radio waves are used in Cellular phones to transmit voice communication in the ultrahigh frequency band.

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Classification of EM Waves

2. Microwaves

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Classification of EM Waves

2. Microwaves

Production - Klystron valve or magnetron valve

Microwave oven

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Classification of EM Waves

2. Microwaves

Production - Klystron valve or magnetron valve

Wavelength range - 0.1 m to 1 mm

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Classification of EM Waves

2. Microwaves

Production - Klystron valve or magnetron valve

Wavelength range - 0.1 m to 1 mm

Detection - Point contact diodes

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Classification of EM Waves

Application of microwaves

They are suitable for the radar systems used in aircraft navigation.

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Classification of EM Waves

Application of microwaves

They are suitable for the radar systems used in aircraft navigation.

Microwave oven is an interesting domestic application of these waves.

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Classification of EM Waves

3. Infrared rays

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Classification of EM Waves

3. Infrared rays

Production - Vibration of atoms and molecules

Infrared wireless communication

Infrared rays generation

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Classification of EM Waves

3. Infrared rays

Production - Vibration of atoms and molecules

Wavelength range - 1 mm to 700 nm

Infrared wireless communication

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Classification of EM Waves

3. Infrared rays

Production - Vibration of atoms and molecules

Wavelength range - 1 mm to 700 nm

Detection - Infrared photographic film

Infrared wireless communication

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Classification of EM Waves

Application of Infrared rays

Infrared lamps are used in physical therapy.

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Classification of EM Waves

Application of Infrared rays

Infrared lamps are used in physical therapy.

Infrared rays maintain the earth’s temperature.

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Classification of EM Waves

Application of Infrared rays

Infrared lamps are used in physical therapy.

Infrared rays maintain the earth’s temperature.

Infrared detectors are used in earth satellites, both for military purpose and to observe the growth of crops.

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Classification of EM Waves

Application of Infrared rays

Infrared lamps are used in physical therapy.

Infrared rays maintain the earth’s temperature.

Infrared detectors are used in earth satellites, both for military purpose and to observe the growth of crops.

Electronic devices also emit infrared rays and widely used in the remote switches of household electronic systems such as TV sets, video recorders, and wi-fi systems.

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Classification of EM Waves

4. Visible light

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Classification of EM Waves

4. Visible light

Production - Electrons in atoms emit light when they move from higher energy level to lower energy level.

Spectrum of visible light

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Classification of EM Waves

4. Visible light

Production - Electrons in atoms emit light when they move from higher energy level to lower energy level.

Wavelength range- 400 nm to 700 nm

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Classification of EM Waves

4. Visible light

Production - Electrons in atoms emit light when they move from higher energy level to lower energy level.

Wavelength range- 400 nm to 700 nm

Detection - Eye photocells, photographic film

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Classification of EM Waves

Colour

Wavelength (nm)

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Classification of EM Waves

Colour

Wavelength (nm)

Violet

400 - 450

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Classification of EM Waves

Colour

Wavelength (nm)

Violet

400 - 450

Blue

450 - 500

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Classification of EM Waves

Colour

Wavelength (nm)

Violet

400 - 450

Blue

450 - 500

Green

500 - 550

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Classification of EM Waves

Colour

Wavelength (nm)

Violet

400 - 450

Blue

450 - 500

Green

500 - 550

Yellow

550 - 600

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Classification of EM Waves

Colour

Wavelength (nm)

Violet

400 - 450

Blue

450 - 500

Green

500 - 550

Yellow

550 - 600

Orange

600 - 650

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Classification of EM Waves

Colour

Wavelength (nm)

Violet

400 - 450

Blue

450 - 500

Green

500 - 550

Yellow

550 - 600

Orange

600 - 650

Red

650 - 700

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Classification of EM Waves

Application of visible light

Visible light emitted or reflected from objects around us provides us information about the world.

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Classification of EM Waves

5. Ultraviolet rays

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Classification of EM Waves

5. Ultraviolet rays

Production -The sun is an important source of UV Rays.

Inner shell electrons in atoms moving from one energy level to lower energy level.

UV rays generation

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Classification of EM Waves

5. Ultraviolet rays

Production -The sun is an important source of UV Rays.

Inner shell electrons in atoms moving from one energy level to lower energy level.

Wavelength range- 400 nm to 1 nm

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Classification of EM Waves

5. Ultraviolet rays

Production -The sun is an important source of UV Rays.

Inner shell electrons in atoms moving from one energy level to lower energy level.

Wavelength range- 400 nm to 1 nm

Detection - Photocells, photographic films

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Classification of EM Waves

Application of Ultraviolet rays

UV lamps are used to kill germs in water purifiers.

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Classification of EM Waves

Application of Ultraviolet rays

UV radiations can be focused into very narrow beams for high precision applications such as LASIK eye surgery.

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Classification of EM Waves

Application of Ultraviolet rays

Ozone layer in the atmosphere absorbs UV rays coming from sun.

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Classification of EM Waves

6. X-rays

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Classification of EM Waves

6. X-rays

Production- X-rays tube or inner shell electrons

X-rays generation

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Classification of EM Waves

6. X-rays

Production- X-rays tube or inner shell electrons

Wavelength range - 1 nm to 10 -3 nm

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Classification of EM Waves

6. X-rays

Production- X-rays tube or inner shell electrons

Wavelength range - 1 nm to 10 -3 nm

Detection - photographic film, Geiger tubes, Ionisation chamber

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Classification of EM Waves

Application of X-rays

X-rays are used as a diagnostic tool in medicine.

X-rays of body

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Classification of EM Waves

Application of X-rays

X-rays are also used in treatment of certain form of cancer. X-rays damage or destroy living tissues and organism.

Destroying living tissues by using X rays

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Classification of EM Waves

Application of X-rays

X-rays are used in luggage scanner at airport, railway station etc.

Luggage scanner

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Classification of EM Waves

7. Gamma rays

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Classification of EM Waves

7. Gamma rays

Production - Radioactive decay of nucleus

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Classification of EM Waves

7. Gamma rays

Production - Radioactive decay of nucleus

Wavelength range - less than 10 -3 nm

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Classification of EM Waves

7. Gamma rays

Production - Radioactive decay of nucleus

Wavelength range - less than 10 -3 nm

Detection - detected by observing

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Classification of EM Waves

Application of Gamma rays

They are used in medicine to destroy cancer cells.

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Classification of EM Waves

Application of Gamma rays

They are used in medicine to destroy cancer cells.

They are used to treat malignant tumours in radiotherapy.

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Memory based question

Ready for challenge

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Q. What type of waves are used to transmit cellular telephone messages?

  1. Gamma rays
  2. Microwaves
  3. Radio waves
  4. Visible light

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Q. What type of waves are used to transmit cellular telephone messages?

  1. Gamma rays
  2. Microwaves
  3. Radio waves
  4. Visible light

Pause video

(Time duration : 2 minutes)

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Q. What type of waves are used to transmit cellular telephone messages?

  1. Gamma rays
  2. Microwaves
  3. Radio waves
  4. Visible light

Sol.

  1. Radio waves

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Memory based question

Ready for challenge

379 of 398

Q. Which of the following is correct in order of lowest to highest frequency?

  1. X-rays, visible light, microwaves
  2. Ultraviolet rays, visible light, gamma rays
  3. Microwaves,visible light, gamma rays
  4. Gamma rays, visible light, x rays

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Q. Which of the following is correct in order of lowest to highest frequency?

  1. X-rays, visible light, microwaves
  2. Ultraviolet rays, visible light, gamma rays
  3. Microwaves,visible light, gamma rays
  4. Gamma rays, visible light, x rays

Pause video

(Time duration : 2 minutes)

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Q. Which of the following is correct in order of lowest to highest frequency?

  1. X-rays, visible light, microwaves
  2. Ultraviolet rays, visible light, gamma rays
  3. Microwaves,visible light, gamma rays
  4. Gamma rays, visible light, x rays

Sol.

  1. Microwaves, visible light, gamma rays

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Memory based question

Ready for challenge

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Q. Why are radio waves used extensively for communication?

  1. Short wavelength
  2. High frequency
  3. High energy
  4. Long wavelength

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Q. Why are radio waves used extensively for communication?

  1. Short wavelength
  2. High frequency
  3. High energy
  4. Long wavelength

Pause video

(Time duration : 2 minutes)

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Q. Why are radio waves used extensively for communication?

  1. Short wavelength
  2. High frequency
  3. High energy
  4. Long wavelength

Sol.

  1. Long wavelength

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Memory based question

Ready for challenge

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Q. The energy of the EM Waves is of the order of 15 kev. Which part of the spectrum does it belong

  1. X-rays
  2. Infrared rays
  3. Ultraviolet rays
  4. Gamma rays

388 of 398

Q. The energy of the EM Waves is of the order of 15 kev. Which part of the spectrum does it belong

  1. X-rays
  2. Infrared rays
  3. Ultraviolet rays
  4. Gamma rays

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(Time duration : 2 minutes)

389 of 398

Q. The energy of the EM Waves is of the order of 15 kev. Which part of the spectrum does it belong

  1. X-rays
  2. Infrared rays
  3. Ultraviolet rays
  4. Gamma rays

Sol.

  1. X-rays

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Memory based question

Ready for challenge

391 of 398

Q. The condition under which a microwave oven heats up food containing water molecules most efficiently is

  1. The frequency of the microwave must match the resonant frequency of water molecules
  2. The frequency of the microwave has no relation with natural frequency of water molecules
  3. Microwaves are heat waves , so always produce heat
  4. Infrared waves produce heating in a microwave oven

392 of 398

Q. The condition under which a microwave oven heats up food containing water molecules most efficiently is

  1. The frequency of the microwave must match the resonant frequency of water molecules
  2. The frequency of the microwave has no relation with natural frequency of water molecules
  3. Microwaves are heat waves , so always produce heat
  4. Infrared waves produce heating in a microwave oven

Pause video

(Time duration : 2 minutes)

393 of 398

Q. The condition under which a microwave oven heats up food containing water molecules most efficiently is

  1. The frequency of the microwave must match the resonant frequency of water molecules
  2. The frequency of the microwave has no relation with natural frequency of water molecules
  3. Microwaves are heat waves , so always produce heat
  4. Infrared waves produce heating in a microwave oven

Sol.

  1. The frequency of the microwave must match the resonant frequency of water molecules

394 of 398

Memory based question

Ready for challenge

395 of 398

Q. The decreasing order of wavelength of infrared, microwave, ultraviolet rays and Gamma rays is

  1. Gamma rays, Ultraviolet rays, Infrared rays, Microwaves
  2. Microwaves, Gamma rays, Ultraviolet rays, Infrared rays
  3. Infrared rays, Microwaves, Gamma rays, Ultraviolet rays
  4. Microwaves, Infrared rays, Ultraviolet rays, Gamma rays

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Q. The decreasing order of wavelength of infrared, microwave, ultraviolet rays and Gamma rays is

  1. Gamma rays, Ultraviolet rays, Infrared rays, Microwaves
  2. Microwaves, Gamma rays, Ultraviolet rays, Infrared rays
  3. Infrared rays, Microwaves, Gamma rays, Ultraviolet rays
  4. Microwaves, Infrared rays, Ultraviolet rays, Gamma rays

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(Time duration : 2 minutes)

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Q. The decreasing order of wavelength of infrared, microwave, ultraviolet rays and Gamma rays is

  1. Gamma rays, Ultraviolet rays, Infrared rays, Microwaves
  2. Microwaves, Gamma rays, Ultraviolet rays, Infrared rays
  3. Infrared rays, Microwaves, Gamma rays, Ultraviolet rays
  4. Microwaves, Infrared rays, Ultraviolet rays, Gamma rays

Sol.

(d) Microwaves, Infrared rays, Ultraviolet rays, Gamma rays

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Summary

  • Wavelength is inversely proportional to the frequency.
  • Frequency of Gamma rays is maximum and wavelength is minimum.
  • Wavelength of radio waves is maximum and frequency is minimum.
  • Wavelength of red colour is maximum in visible light.
  • EM spectrum is the arrangement of EM Waves in increasing order of frequency or decreasing order of wavelength.