WORK ENERGY AND POWER
P. H. GAJBHIYE
PGT PHYSICS JNV GONDIA
WORK
W = F·d
WORK AS SCALAR PRODUCT
Work as a dot product of force F and displacement d
�Positive, Negative, and Zero Work
�Graphical Representation of the Work Done �by a Constant Force
Work done by variable force
�Work Done by a Non-Constant Force
�Work Done by a Continuously Varying Force
Work done by system of forces
Conservative Non-conservative forces
ENERGY
ENERGY & ITS UNIT
FORMS OF ENERGY
MECHANICAL ENERGY
KINETIC ENERGY
POTENTIAL ENERGY
Kinetic Energy
K.E. = ½mv2
UCSD: Physics 8; 2005
16
Spring 2005
Numerical examples of kinetic energy
K.E. = ½×(0.145 kg)×(30 m/s)2
= 65.25 kg·m2/s2 ≈ 65 J
K.E. = ½×(0.00567 kg)×(5 m/s)2
= 0.07 kg·m2/s2 = 0.07 J
UCSD: Physics 8; 2005
17
Spring 2005
POTENTIAL ENERGY
GRAVITATIONAL PE
ELASTIC PE
PE OF SPRING MASS SYSTEM�
F = -K Δx
How much work is done to move the block?
Be careful with the signs of the forces!
The force to move the block must be equal and opposite to the force of the spring on the block.
F = K Δx
Force
Distance
X
F=Kx
W = ½ F X
W = ½ K X2
Work done to move a mass on a spring a distance “x”:
This work is stored in the form of potential energy of spring
WORK ENERGY THEOREM FOR CONSTANT FORCE
WORK ENERGY THEOREM FOR VARIABLE FORCE
MASS ENERGY EQUIVALENCE
POWER
COLLISIONS
TYPES OF COLLISION
TYPES OF COLLISION
Applying Newton’s experimental law, we have
Velocities after collision
v1 = (m1 – m2) u1 + 2m2u2 / (m1 + m2)
v2 = (m2 – m1) u2 + 2m1u1 / (m1 + m2)
When masses of two colliding bodies are equal, then after the collision, the bodies exchange
their velocities.
v1 = u2 and v2 = u1
If second body of same mass (m1 = m2) is at rest, then after collision first body comes to rest
and second body starts moving with the
initial velocity of first body.
v1 = 0 and v2 = u1
If a light body of mass m1 collides with a very heavy body of mass m2 at rest, then after collision.
v1 = – u1 and v2 = 0
It means light body will rebound with its own velocity and heavy body will continue to be at
rest.
If a very heavy body of mass m1 collides with a light body of mass m2(m1 > > m21) at rest, then
after collision
v1 = u1 and v2 = 2u1
Inelastic One Dimensional Collision
Elastic collision in one dimension
In horizontal direction,
m1u1 cos α1 + m2u2 cos α2= m1v1 cos β1 + m2v2 cos β2
In vertical direction.
m1u1 sin α1 – m2u2 sin α2 = m1u1 sin β1 – m2u2 sin β2
If m1 = m2 and α1 + α2 = 90°
then β1 + β2 = 90°
If the initial and final velocities of colliding bodies do not lie along the same line, then the collision is called two dimensional or oblique Collision.
Two Dimensional or Oblique Collision