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Conservation of Momentum

Unit 6: Momentum and Impulse

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Conservation of Momentum

The law of conservation of momentum states that the momentum of a system is constant if no external forces (like friction) are acting on the system

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Conservation of Momentum

Example: If you throw a rock forward from a skateboard, you will move backward in response

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What it means…

The total momentum of a system will stay the same before and after a collision

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Why does Mr. Stickfigure move backwards on the ice?

Before Collision

After Collision

Momentum = zero

(not moving)

ptotal = 0 kg∙m/s

Momentum = zero

ptotal = 5 + -5

ptotal = 0 kg∙m/s

+p

-p

p = -5 kgm/s

p = 5 kgm/s

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Why does Mr. Stickfigure move backwards?

Answer:

  • Mr. Stickfigure moves backwards because he threw the ball forward

Explain the Relationship

  • The Law of the Conservation of Momentum states that the total momentum of a system must stay the same before and after
  • Before the ball and Mr. Stickfigure had a total momentum of zero, so after the total momentum needed to stay zero

Support with Data/Observations

  • When the ball moved forward it had a positive momentum, so Mr. Stickfigure needed a negative momentum to cancel it out

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Why do both skaters move after?

Before

ptotal = 0 kg∙m/s

(not moving)

After

ptotal = 0 kg∙m/s

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Answer the Question

  • Both skaters move after in order to conserve momentum

Explain the Relationship

  • The Law of the Conservation of Momentum states that the total momentum of a system must stay the same before and after
  • Before the two skaters had a total momentum of zero, so after the total momentum needed to stay zero

Support with Data/Observations

  • When they push against each other one moved forward and had a positive momentum, so the other needed to move backwards to have a negative momentum, so the total momentum stayed zero

Why do both skaters move after?

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Recoil

  • Recoil is a term that refers to moment when a gun moves backwards after it is shot
  • Recoil happens because everything must follow “The Law of the Conservation of Momentum”!!!

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Why a gun “recoils”

The total momentum before was zero

So the total momentum after has to be zero

The gun moves with a negative momentum because the bullet moves with a positive momentum and they cancel out, the total momentum stays zero

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3 Types of Collisions

  • Elastic
  • Inelastic
  • Perfectly Inelastic

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Elastic or Inelastic?

An elastic collision loses no energy – the deformation on collision is fully restored

In an inelastic collision, energy is lost and the deformation may be permanent

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Elastic

  • A collision in which two objects move separately with different velocities, but not permanent deformation

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Inelastic

  • A collision in which two objects deform so that the objects move in the same direction but with different final velocities after colliding

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Perfectly Inelastic

  • A collision in which two objects stick together and move with the same velocity after colliding

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For each of the following examples, identify the type of collision…

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Perfectly Inelastic

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Perfectly Inelastic

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Elastic

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Perfectly Inelastic

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Inelastic

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Perfectly Inelastic

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Elastic

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Explain why the final velocity of the moving object “makes sense” in order to conserve total momentum.

  • After the collision, the 1st ball transferred its momentum to the 2nd ball
  • Since the balls have the same mass, the velocity of the second ball should be the same as the first in order to conserve momentum

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Explain why the final velocity of the moving object “makes sense” in order to conserve total momentum.

  • After the collision, the 1st block transferred its momentum to the 2nd block
  • Since the 2nd block has more mass, the velocity should be less, in order to conserve momentum

The block is 2x bigger, it is ½ as fast

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Explain why the final velocity of the moving object “makes sense” in order to conserve total momentum.

  • After the collision, the cart and McDonald are moving
  • Since there is more mass, there should be less velocity to conserve momentum

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Example 1

A 50 kg girl jumps into a 100 kg raft at rest on the water. If the velocity of the girl is 4 m/s as she jumps, what is the final velocity of the girl and the raft?

G

R

G

R

mG = 50 kg

vG = 4 m/s

mR = 100 kg

vR = 0 m/s

mGvG + mRvR = (mG + mR)vf

200 = (150)vf

vf = 1.33 m/s

Draw a Picture

Before After

mtotal = 150 kg

vf = ?

(50)(4) + (100)(0) = (50 + 100)(vf)

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Example 2

A 63 kg astronaut throws a 5 kg hammer in a direction away from the shuttle with a speed of 18 m/s, pushing the astronaut back to the shuttle. Assuming that the astronaut and hammer start from rest, find the final speed of the astronaut after throwing the hammer.

Draw a Picture

Before After

A

H

A

H

mA = 63 kg

vA = 0 m/s

mH = 5 kg

vH = 0 m/s

mA = 63 kg

vA = ?

mH = 5 kg

vH = 18 m/s

mAvA + mHvH = mAvAf + mHvHf

(63)(0)+(5)(0) = (63)vA + (5)(18)

0 = (63)vAf + 90

-90 = (63)vAf

vAf = -1.43 m/s

+90 kg∙m/s

-90 kg∙m/s

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Example 3

1st Draw a Picture

Before After

1

2

1

2

m1 = 15 kg

v1 = 4 m/s

m2 = 6.5 kg

v2 = -2 m/s

m1 = 15 kg

vf = ?

m2 = 6.5 kg

m1v1 + m2v2 = (m1 + m2)vf

(15)(4)+(6.5)(-2) = (15 + 6.5)(vf)

47 = 21.5vA

vf = 2.19m/s

A 15 kg cart moving to the right with a speed of 4 m/s collides with a 6.5 kg cart moving to the left with a speed of 2 m/s. If the carts stick together, find the final speed of the two carts.

60 -13 = 21.5vf

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Key Concepts

Elastic

m1v1i + m2v2i = m1v1f + m2v2f

Inelastic

m1v1i + m2v2i = m1v1f + m2v2f

Perfectly Inelastic

m1v1i + m2v2i = (m1+ m2)vf

“Starts from rest” Vi = 0m/s

“Stops” Vf = 0m/s

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Lesson Check 6.3