LPN INTENSIVE CALCULATIONS�� CALCULATIONS WORKBOOK 4 ��� INTENSIVE GPHC Exam revision � programme FOR JUNE 2025
LONDON PHARMACIST NETWORK (LPN)
INTENSIVE REVISION FOR JUNE 2025
GPHC EXAM.
TODAY’S TOPICS
RDA -QUESTION 1
RDA OF PROTEIN - 2
RDA - QUESTION 3
RDA - QUESTION 4
QUESTION 5 - RDA OF PROTEIN
QUESTION 6 – R.D.A
Miss . G a 3-year-old has been prescribed Gaviscon Infant Sachets one dose with feeds, 6 times in 24 hours. Assume Gaviscon Infant sachets contain 0.95mmol Na+/dose. The recommended daily allowance (RDA) of salt for this patient is 3g (equivalent to 1.2 g sodium) per day. The atomic mass of sodium is 23.
What percentage of this child’s recommended daily salt allowance is contained in a total daily dose of Gaviscon Infant Sachets? ANSWER AS WHOLE NUMBER
Give your answer to the nearest whole number.
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ANSWER 1 RDA
ANSWER 2 RDA
ANSWER- RDA 3
ANSWER- RDA 4
ANSWER RDA 5
The patient has not undergone any surgical or hormonal changes. So , biologically still a woman.
ANSWER 6 - RDA
QUESTION 1
Mrs. E. is a 71-year-old Parkinson’s disease patient who needs to be switched to rotigotine patches. She currently takes
Calculate what strength of rotigotine patches, Miss E should be prescribed every 24 hours.
Use resource provided above.
�QUESTION 2
MRS .G. is a 62-year-old Parkinson’s disease patient who needs to be switched to rotigotine patches. She currently takes
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Calculate what strength of rotigotine patches, should be prescribed every 24 hours. Ans to nearest whole number
�QUESTION 3
QUESTION 4
�QUESTION 5
�QUESTION 6
MR K is a 60-year-old Parkinson’s disease patient who needs to be switched to rotigotine patches. he currently takes
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Calculate what strength of rotigotine patches, MR. K should be prescribed every 24 hours. Ans to nearest whole number
QUESTION 1 ANSWER
Step 1 - 50 x 4 = 200mg
Step 2 - 200mg x 1.3 = 260mg
Step 3 – 7mg x 20 = 140
Step 4 - 260 + 140 = 400
Step 5 - 400 x 0.55 = 220 mg
220/20 = 11mg
ANSWER =Supply 12mg ropinirole patches
ANSWER 2
ANSWER 3
ANSWER 4
ANSWER 5
ANSWER 6
QUESTION 1 – CLINICAL RATIO
QUESTION 2 – CLINICAL RATIO
QUESTION 3- CLINICAL RATIO
ANSWER 1
ANSWER 2
ANSWER 3
7 x 20 = 140
Answer = 140
PAIN DOSES CALC -QUESTION 1
Mr. Fred is a 45-year-old patient admitted in the orthopedic ward after a car accident. He is to receive 120mg of oxycodone per day via a 10cm syringe driver for pain. The oxycodone dose has been made up to 75ml with water for injection and the syringe driver has been set at a rate of 4.2 mm/hour. Mr. Fred weighs 70kg . What dose of oxycodone in mcg/kg/min is Mr. . Fred going to receive?
ANSWER TO 1 D.P
OPIOID QUESTION 2
INCREASE IN OPIOID DOSES - QUESTION 3
PAIN DOSES - QUESTION 4
OPIOID DOSES 5
A 56-year-old lady is going to be converted from oxycodone to tapentadol to achieve better pain management. She currently takes oxycodone modified release 20mg, one twice a day. In addition she takes 5mg capsules for breakthrough pain. She averages at four oxycodone 5mg capsules a day for breakthrough pain.
What is the equivalent total daily dose of Tapentadol in milligrams? WHOLE NUMBER.
ANSWER 1
ANSWER 2
ANSWER 3
100 + 64 = 164MG
ANSWER 4
30mg plus 60mg plus 40mg plus 64mg = 194MG
ANSWER 5
ANSWER = 300mg tapentadol daily
QUESTION – HALF LIFE 1
HALF-LIFE 2
Drug P contains 400g of paracetamol effervescent which has a half-life of 6 hours. Calculate how long in hours it will take for nearly all of the effervescent paracetamol to evaporate i.e. approx. 0.01 to remain?
QUESTION – HALF LIFE 3
QUESTION 4 – HALF LIFE
HALF-LIFE 5
Mrs. F. was administered an injection of gentamicin. The plasma concentration immediately after administration was found to be 4.8mg/L.
Calculate how many half lives it would take to reach approximately 0.0749mg/L from initial plasma concentration.
HALF LIFE - QUESTION 6
F x T
Cp = Desired peak conc of drug
F = Bioavailability (1 )
S = Salt factor is 1
T = time interval in hours
Half-life = 20 hours
Using the bioavailable amount(dose which reaches bloodstream), state how many half-lives it will take to have 9mg left in the body.
ANSWER 1- HALF LIFE
ANSWER 2 – HALF LIFE
ANSWER 3 - HALF LIFE
ANSWER 4 – HALF LIFE
ANSWER HALF-LIFE 5
4.8mg/L = 0
2.4mg/L= 1
1.2mg/L = 2
0.6mg/L= 3
0.3mg/L= 4
0.15mg/L = 5
0.0075mg/L = 6
ANSWER 6 - HALF LIFE
F x T
1 x 24
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