Physics final project
Anagha Sudhindra
Field agent Ethan Hunt is attempting to single-handedly hijack a plane. With a running start, he leaps onto a taxiing Airbus A400M and hangs onto a protrusion on the side. As the plane starts its ascent, will Hunt be able to hang on?
Airbus a400m
A400M Stats
For calculating net force
For calculating net force
For calculating thrust force
For calculating thrust force
Mass
Engine Power
Acceleration
Take off Velocity
*all obtained from online sources
115212 kg
1.47 m/s2
61.3 m/s
8200 kw
Forces
Calculating the forces
FNet
m (mass) x a (acceleration) = FNet
115212 x 0.15(9.8) = 169361.64 N
FThrust
P (power) / v (velocity) = FThrust
8200000 / 61.3 = 133768.3 N
FDrag
FNet - FThrust = FDrag
169361.64 - 133768.3 = 35593.64 N
Now that we know all the forces acting on the aircraft, we can analyze forces acting on Hunt.
Net force:
𝐹Net=m a
Ethan Hunt Stats
Hunt and aircraft are pretty much the same body, accelerating at the same rate.
Newton’s second law
Mass
Acceleration
*all obtained from online sources
68 kg
1.47 m/s2
𝐹Net=m a
FNet = 68 x 1.47
99.96 N Net Force
FNet = Ff - FDrag
Drag force:
𝐹D=1/2𝐶𝜌𝐴𝑣2
Drag force Stats
For calculating FD
For calculating net force
For calculating drag force
Density of air
Drag coefficient
Take off Velocity
1.225 kg/m3
0.9
61.3 m/s
Drag force Stats
Area of Hunt “in contact” with the air. Head, shoulders, arms, back. Surface area of average male on all those body parts.
Area
1.8 m2
𝐹D=1/2𝐶𝜌𝐴𝑣2
FD = .5 x .9 x 1.255 x 1.8 x 61.32
3728.56 N Drag Force
Hunt’s frictional force must ≥ drag force (air resistance) he faces on the exterior of the aircraft + net force.
FDrag = 3728.56 N
FNet = 99.96
Ff ≥ 3828.52
Frictional force:
𝐹f=𝐹N x μ
Ethan Hunt Stats
The exterior of aircrafts is a layer of aluminum alloy. Hunt’s is hanging on by his bare skin. This is the coefficient of static friction between skin and aluminum.
This force replaces the role of a typical normal force in this scenario. FNormal is contact force, grip strength is the magnitude of contact. This value is the average max grip strength of an adult male.
Grip Strength
Frictional Coefficient
*all obtained from online sources
517 N
0.6
Calculating the forces
FNormal x μ = Ff
517 x 0.6 = 310 N
Ff = 310 N < 3828.52 N
Though Ethan Hunt has accomplished tons of crazy missions, it seems this one was truly impossible.
Thank you!
“A400M (Future Large Aircraft) Military Transport Aircraft.” Airforce Technology, 28 Apr. 2022, www.airforce-technology.com/projects/fla/.
Airbus A400M - Military Analizer, militaryanalizer.com/airbus-a400m/. Accessed 22 May 2023.
“Aircraft Performance Database.” Aircraft Performance Database, contentzone.eurocontrol.int/aircraftperformance/details.aspx?ICAO=A400. Accessed 21 May 2023.
Man, George, and Mao-Qiang Man. “Skin Friction Coefficient.” SpringerLink, 1 Jan. 1970, link.springer.com/referenceworkentry/10.1007/978-3-319-32383-1_20#:~:text=The%20skin%20friction%20coefficient%20on,(Seo%20and%20Armstrong%202009).
“Mission: Impossible - Rogue Nation (2015) - Ethan Catches a Plane Scene (1/10) | Movieclips.” YouTube, 23 July 2018, www.youtube.com/watch?v=elpUGB9Ap1Y.
“Tom Cruise Height, Weight, Age, Biography, Wife & More " Starsunfolded.” StarsUnfolded, starsunfolded.com/tom-cruise/. Accessed 22 May 2023.
Williams, Wayne. “World’s Strongest Bionic Hands.” Bionics For Everyone, 25 Mar. 2022, bionicsforeveryone.com/worlds-strongest-bionic-hands/#:~:text=The%20average%20maximum%20grip%20force%20for%20males%20is%20517%20Newtons,daily%20activities%20is%2070%20Newtons.