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Physics final project

Anagha Sudhindra

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Field agent Ethan Hunt is attempting to single-handedly hijack a plane. With a running start, he leaps onto a taxiing Airbus A400M and hangs onto a protrusion on the side. As the plane starts its ascent, will Hunt be able to hang on?

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Airbus a400m

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A400M Stats

For calculating net force

For calculating net force

For calculating thrust force

For calculating thrust force

Mass

Engine Power

Acceleration

Take off Velocity

*all obtained from online sources

115212 kg

1.47 m/s2

61.3 m/s

8200 kw

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Forces

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Calculating the forces

FNet

m (mass) x a (acceleration) = FNet

115212 x 0.15(9.8) = 169361.64 N

FThrust

P (power) / v (velocity) = FThrust

8200000 / 61.3 = 133768.3 N

FDrag

FNet - FThrust = FDrag

169361.64 - 133768.3 = 35593.64 N

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Now that we know all the forces acting on the aircraft, we can analyze forces acting on Hunt.

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Net force:

𝐹Net=m a

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Ethan Hunt Stats

Hunt and aircraft are pretty much the same body, accelerating at the same rate.

Newton’s second law

Mass

Acceleration

*all obtained from online sources

68 kg

1.47 m/s2

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𝐹Net=m a

FNet = 68 x 1.47

99.96 N Net Force

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FNet = Ff - FDrag

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Drag force:

𝐹D=1/2𝐶𝜌𝐴𝑣2

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Drag force Stats

For calculating FD

For calculating net force

For calculating drag force

Density of air

Drag coefficient

Take off Velocity

1.225 kg/m3

0.9

61.3 m/s

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Drag force Stats

Area of Hunt “in contact” with the air. Head, shoulders, arms, back. Surface area of average male on all those body parts.

Area

1.8 m2

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𝐹D=1/2𝐶𝜌𝐴𝑣2

FD = .5 x .9 x 1.255 x 1.8 x 61.32

3728.56 N Drag Force

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Hunt’s frictional force must ≥ drag force (air resistance) he faces on the exterior of the aircraft + net force.

FDrag = 3728.56 N

FNet = 99.96

Ff ≥ 3828.52

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Frictional force:

𝐹f=𝐹N x μ

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Ethan Hunt Stats

The exterior of aircrafts is a layer of aluminum alloy. Hunt’s is hanging on by his bare skin. This is the coefficient of static friction between skin and aluminum.

This force replaces the role of a typical normal force in this scenario. FNormal is contact force, grip strength is the magnitude of contact. This value is the average max grip strength of an adult male.

Grip Strength

Frictional Coefficient

*all obtained from online sources

517 N

0.6

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Calculating the forces

FNormal x μ = Ff

517 x 0.6 = 310 N

Ff = 310 N < 3828.52 N

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Though Ethan Hunt has accomplished tons of crazy missions, it seems this one was truly impossible.

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  • Air & wind pressure would compromise breathing
  • Lack of oxygen as aircraft ascends
  • Sound, heat of propeller

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  • This stunt was accomplished with the use of a harness

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Thank you!

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“A400M (Future Large Aircraft) Military Transport Aircraft.” Airforce Technology, 28 Apr. 2022, www.airforce-technology.com/projects/fla/.

Airbus A400M - Military Analizer, militaryanalizer.com/airbus-a400m/. Accessed 22 May 2023.

“Aircraft Performance Database.” Aircraft Performance Database, contentzone.eurocontrol.int/aircraftperformance/details.aspx?ICAO=A400. Accessed 21 May 2023.

Man, George, and Mao-Qiang Man. “Skin Friction Coefficient.” SpringerLink, 1 Jan. 1970, link.springer.com/referenceworkentry/10.1007/978-3-319-32383-1_20#:~:text=The%20skin%20friction%20coefficient%20on,(Seo%20and%20Armstrong%202009).

“Mission: Impossible - Rogue Nation (2015) - Ethan Catches a Plane Scene (1/10) | Movieclips.” YouTube, 23 July 2018, www.youtube.com/watch?v=elpUGB9Ap1Y.

“Tom Cruise Height, Weight, Age, Biography, Wife & More " Starsunfolded.” StarsUnfolded, starsunfolded.com/tom-cruise/. Accessed 22 May 2023.

Williams, Wayne. “World’s Strongest Bionic Hands.” Bionics For Everyone, 25 Mar. 2022, bionicsforeveryone.com/worlds-strongest-bionic-hands/#:~:text=The%20average%20maximum%20grip%20force%20for%20males%20is%20517%20Newtons,daily%20activities%20is%2070%20Newtons.