PROBABILITY
favourable cases are (3, 6) , (4, 5), (5, 4), (6, 3)
∴ No. of favourable outcomes = 4
4
36
3
36
(1,1),
(2,1), (2,2), (2,3), (2,4), (2,5), (2,6),
(3,1), (3,2), (3,3), (3,4), (3,5), (3,6),
(4,1), (4,2), (4,3), (4,4), (4,5), (4,6),
(5,1), (5,2), (5,3), (5,4), (5,5), (5,6),
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)
(1,2),
(1,3),
(1,4),
(1,5),
(1,6),
(1,1)
(2,1) (2,2), (2,3), (2,4), (2,5), (2,6),
(3,1), (3,2), (3,3), (3,4), (3,5), (3,6),
(4,1), (4,2), (4,3), (4,4), (4,5), (4,6),
(5,1), (5,2), (5,3), (5,4), (5,5), (5,6),
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)
(1,2),
(1,3),
(1,4),
(1,5),
(1,6),
(1,1),
(2,1), (2,2), (2,3), (2,4), (2,5), (2,6),
(3,1), (3,2), (3,3), (3,4), (3,5), (3,6),
(4,1), (4,2), (4,3), (4,4), (4,5), (4,6),
(5,1), (5,2), (5,3), (5,4), (5,5), (5,6),
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)
(1,2),
(1,3),
(1,4),
(1,5),
(1,6),
2
3
4
5
6
7
8
9
10
11
12
3
36
4
36
Q. Two dice, one blue and one grey are thrown at the same time (i) Complete the following table :
Event ‘Sum
on 2 dice’
Probability
2 3 4 5 6 7 8 9 10 11 12
1
36
5
36
1
36
2
36
5
36
6
36
Sol.
favourable cases are (4, 6), (5, 5), (6, 4)
∴ No. of favourable outcomes = 3
Sol.
favourable cases are (5, 6), (6, 5)
∴ No. of favourable outcomes = 2
(1,1),
(2,1), (2,2), (2,3), (2,4), (2,5), (2,6),
(3,1), (3,2), (3,3), (3,4), (3,5), (3,6),
(4,1), (4,2), (4,3), (4,4), (4,5), (4,6),
(5,1), (5,2), (5,3), (5,4), (5,5), (5,6),
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)
(1,2),
(1,3),
(1,4),
(1,5),
(1,6),
(1,1),
(2,1) (2,2), (2,3), (2,4), (2,5), (2,6),
(3,1), (3,2), (3,3), (3,4), (3,5), (3,6),
(4,1), (4,2), (4,3), (4,4), (4,5), (4,6),
(5,1), (5,2), (5,3), (5,4), (5,5), (5,6),
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)
(1,2),
(1,3),
(1,4),
(1,5),
(1,6),
2
3
4
5
6
7
8
9
10
11
12
2
36
3
36
4
36
Q. Two dice, one blue and one grey are thrown at the same time (i) Complete the following table :
Event ‘Sum
on 2 dice’
Probability
2 3 4 5 6 7 8 9 10 11 12
1
36
1
36
2
36
5
36
6
36
4
36
3
36
5
36
Do you agree with this argument? Justify your answer.
Sol.
No. The eleven sums are not equally likely
Therefore, each of them has probability
1
11
(1,1),
(2,1), (2,2), (2,3), (2,4), (2,5), (2,6),
(3,1), (3,2), (3,3), (3,4), (3,5), (3,6),
(4,1), (4,2), (4,3), (4,4), (4,5), (4,6),
(5,1), (5,2), (5,3), (5,4), (5,5), (5,6),
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)
(1,2),
(1,3),
(1,4),
(1,5),
(1,6),