∑
CHAPTER 3
Modelling & Estimation
AQA Mathematical Studies — Level 3 Certificate
Gulf Stream
Standard Form
Scaling
Subdividing
Fermi Estimation
Critical Evaluation
AQA MATHEMATICAL STUDIES
Level 3 Certificate
CHAPTER 3 — AQA MATHEMATICAL STUDIES
Chapter Overview & Learning Objectives
Prerequisites: estimating calculations · volume of cuboid/cylinder · index laws · standard form · percentages
SECTION 3.1
Modelling the Gulf Stream
Estimate volume of water flow using cross-sectional area, speed, and clearly stated modelling assumptions.
SECTION 3.2
Standard Form
Express and calculate with very large and very small numbers; multiply and divide in standard form.
SECTION 3.3
Estimation Technique 1: Scaling
Use a known reference quantity and scale proportionally to estimate unknown real-world values.
SECTION 3.4
Estimation Technique 2: Subdividing
Break complex regions or populations into smaller, manageable sub-parts and sum the estimates.
SECTION 3.5
Estimation Technique 3: Stating Assumptions
Identify, justify, and simplify assumptions to make real-world problems mathematically tractable.
SECTIONS 3.6 – 3.7
Facts & Formulae · Evaluating Models
Apply useful reference facts; critically assess model accuracy, limitations, and potential improvements.
Gulf Stream — warm current, Florida → Northern Europe
AQA MATHEMATICAL STUDIES · CHAPTER 3.1
Modelling the Gulf Stream
CONTEXT & ASSUMPTIONS
Warm current gives the UK its mild climate
Rectangular cross-section assumed
Speed ≈ 5 km/h (walking pace; accepted 6.4 km/h)
Depth D = 1 km , Width W = 100 km
KEY VALUES USED
Width = 100 km
Depth = 1 km
Speed = 5 km/h
1 km³ = 10⁹ m³
VOLUME CALCULATION
V = W × D × speed
=
100 × 1 × 5
=
500 km³/h
Convert: 500 km³/h = 500 × 10⁹ m³/h = 5 × 10¹¹ m³/h
THE MODELLING CYCLE
Represent mathematically
→
Use techniques
→
Interpret results
→
Compare with real data
→
Improve model
Gulf Stream Modelling
CHAPTER 3.1
AQA Advanced Maths — Chapter 3.1
Fermi Estimation: Ocean Current Modelling
EX
2
Example 1 — Gulf Stream
Volume of warm water past the British Isles per hour
ASSUMPTIONS
Rectangular cross-section
Depth D = 1 km , Width W = 100 km
Constant speed v = 5 km/h
STEP-BY-STEP CALCULATION
1
Volume = Depth × Width × Speed
V = 1 × 100 × 5 = 500 km³/h
2
Convert km³ to m³ (1 km³ = 10⁹ m³)
500 × 10⁹ = 5 × 10¹¹ m³/h
FINAL ANSWER
500 km³/h = 5 × 10¹¹ m³/h
500 × 10⁹ m³ per hour
Example 2 — California Current
Estimate water flow along the California coast per hour
ASSUMPTIONS
Rectangular cross-section
Depth D = 1 km , Width W = 40 km
Speed ≈ 5 km/h (same as Gulf Stream estimate)
STEP-BY-STEP CALCULATION
1
Volume = Depth × Width × Speed
V = 1 × 40 × 5 = 200 km³/h
2
Convert km³ to m³ (1 km³ = 10⁹ m³)
200 × 10⁹ = 2 × 10¹¹ m³/h
FINAL ANSWER
200 km³/h = 2 × 10¹¹ m³/h
200 × 10⁹ m³ per hour
AQA 3.2
Standard Form: Large & Small Numbers
a × 10 n
where 1 ≤ a < 10 and n is an integer
Multiply: multiply numbers, ADD powers
Divide: divide numbers, SUBTRACT powers
Small numbers use negative powers
MULTIPLYING IN STANDARD FORM
4 × 10 2 × 2 × 10 3 = ?
NUMBERS
4 × 2 = 8
POWERS
10 2 × 10 3 = 10 2+3 = 10 5
ANSWER
8 × 10 5
Add the powers when multiplying
DIVIDING IN STANDARD FORM
6 × 10 5 ÷ 2 × 10 3 = ?
NUMBERS
6 ÷ 2 = 3
POWERS
10 5 ÷ 10 3 = 10 5−3 = 10 2
ANSWER
3 × 10 2
Subtract the powers when dividing
NOT standard form:
15 × 10
(15 > 10) → Rewrite as
1.5 × 10
. Always
check 1 ≤ a < 10!
NEGATIVE POWERS = SMALL NUMBERS
Negative power means the number is
less than 1
10 −7 = 0.000 000 1 (7 decimal places)
For Fermi estimation: round to
1 sig. fig.
first
Ordinary Number | Standard Form | Context |
500 000 000 000Large | 5 × 1011 | e.g. Gulf Stream m³/hr |
300 000 000Large | 3 × 108 | Speed of light (m/s) |
0.000 000 2Small | 2 × 10−7 | Very small quantity |
0.000 000 000 000 000 000 000 000 03Small | 3 × 10−26 | Water molecule mass (kg) |
KEY CONVERSIONS REFERENCE
10
11
Examples 1 & 2: Standard Form Calculations
Standard form: 1 ≤ a < 10, a × 10ⁿ
Example 1 — Distance to the Sun
AQA Ch 3.2 Example 2 · Multiplication of standard form
Given: speed of light = 299 792 458 m/s; time = 497 s. Round to 1 sig fig for Fermi estimation.
1
ROUND THE VALUES
Speed ≈ 3 × 10⁸ m/s | Time ≈ 5 × 10² s
2
APPLY: DISTANCE = SPEED × TIME
3 × 10⁸ × 5 × 10² = 15 × 10¹⁰
3
REWRITE IN STANDARD FORM (15 > 10, SO ADJUST)
15 × 10¹⁰ = 1.5 × 10¹¹ m
DISTANCE TO THE SUN
≈ 1.5 × 10¹¹ m
Standard form check: 1 ≤ 1.5 < 10 ✓ | Powers added: 8 + 2 = 10, then adjusted to 11 ✓
Example 2 — Movies on a Hard Disc
AQA Ch 3.2 Example 3 · Division of standard form
Given: hard disc = 10¹³ bits; each movie ≈ 900 MB. Convert MB to bits first.
1
CONVERT MOVIE SIZE TO BITS
900 MB = 900 × 8 × 10⁶ = 7.2 × 10⁹ ≈ 7 × 10⁹ bits
2
DIVIDE: NUMBER OF MOVIES = DISC ÷ MOVIE SIZE
10¹³ ÷ 7 × 10⁹ = 10⁴ / 7
3
EVALUATE THE RESULT
10 000 ÷ 7 ≈ 1 500 movies
MOVIES STORED ON DISC
≈ 1 500 movies
Powers subtracted: 13 − 9 = 4 | Result is a Fermi estimate — 1 sig fig is sufficient ✓
&
Exercise 3A — Questions
NO CALCULATOR (Q3)
Answer all questions. Show full working. Q3 must be completed without a calculator. Q4–Q6 require clear assumptions.
Note: Q4–Q6 are modelling and estimation problems — show all assumptions clearly. There is no single correct answer for Q4 and Q5.
Q1 — STANDARD FORM
Write in standard form
(a) 9 000 (b) 0.000 002
(c) 85 000 000 (d) 0.000 015
Q2 — CORRECT TO STANDARD FORM
Rewrite correctly in standard form
(a) 24 × 10³ (b) 360 × 10⁵
(c) 0.8 × 10³ (d) 0.03 × 10⁵
Q3 — MULTIPLY & DIVIDE (NO CALCULATOR)
Calculate, giving answers in standard form
(a) 2×10⁷ × 3×10⁴ (b) 6×10⁷ ÷ 3×10⁴
(c) (1.2×10⁷) × (1.2×10⁴) (d) (4×10⁷) ÷ (8×10⁵)
(e) 6×10⁻² × 3×10⁴ (f) (6×10⁷) ÷ (3×10⁻⁴)
Q4 — MODELLING PROBLEM
Estimate the volume of your body
Model your body using cuboids and/or cylinders. State all dimensions assumed and show full working. Give your answer in cm³ and litres.
Q5 — ESTIMATION PROBLEM
Walking from Land's End to John O'Groats
Estimate how many days it would take to walk the full length of Great Britain. State your assumptions for distance and daily walking hours.
Q6 — PLANCK'S CONSTANT
Express in standard form
Planck's constant:
h = 0.000 000 000 000 000 000 000 000 000 000 000 662 6
Write h in the form a × 10ⁿ where 1 ≤ a < 10 .
Exercise 3A — Answers
✓ WORKED ANSWERS
Full worked answers for Q1–Q6. Green values indicate correct standard form — coefficient must satisfy 1 ≤ a < 10.
Key Rule: Standard form requires the coefficient a to satisfy 1 ≤ a < 10 . If a ≥ 10 or a < 1, adjust the power of 10 accordingly.
Q1 — CONVERTING TO STANDARD FORM
Write in standard form
(a) 9000 = 9 × 10³ | (b) 0.000 002 = 2 × 10⁻⁶
(c) 85 000 000 = 8.5 × 10⁷ | (d) 0.000 015 = 1.5 × 10⁻⁵
Q2 — CORRECTING TO STANDARD FORM
Rewrite correctly in standard form
(a) 24 × 10³ = 2.4 × 10⁴ | (b) 360 × 10⁵ = 3.6 × 10⁷
(c) 0.8 × 10³ = 8 × 10² | (d) 0.03 × 10⁵ = 3 × 10³
Q3 — MULTIPLYING & DIVIDING (NO CALCULATOR)
Calculate without a calculator
(a) 2×10⁷ × 3×10⁴ = 6×10¹¹ | (b) 6×10⁷ ÷ 3×10⁴ = 2×10³
(c) 1.2×10⁷ × 1.2×10⁴ = 1.44×10¹¹ | (d) 4×10⁷ ÷ 8×10⁵ = 5×10¹
(e) 6×10⁻² × 3×10⁴ = 1.8×10³ | (f) 6×10⁷ ÷ 3×10⁻⁴ = 2×10¹¹
Q4 — MODELLING: BODY VOLUME
Estimate volume of your body
Head ≈ sphere r=10 cm; torso ≈ cylinder r=15 cm, h=60 cm;
Arms ≈ cylinders r=4 cm, h=60 cm each; legs ≈ r=7 cm, h=90 cm each.
Total ≈ 70 000 cm³ = ≈ 70 litres
Q5 — MODELLING: LAND'S END TO JOHN O'GROATS
Estimate walking time
Distance ≈ 1400 km; walking speed ≈ 5 km/h; 8 hours/day.
Time = 1400 ÷ (5 × 8) = ≈ 35 days
Q6 — PLANCK'S CONSTANT
Express h in standard form
h = 0.000 000 000 000 000 000 000 000 000 000 000 662 6
= 6.626 × 10⁻³⁴ J·s
3.3 Estimation Technique 1: Scaling
Scaling: Estimate a quantity that can be multiplied or divided to reach the required quantity — choose something known or easier to estimate, then scale up or down.
Example 5 — UK Heartbeats/Year
Scale from pulse rate → national total
1
MEASURE PULSE
Count 20 beats in 15 seconds
20 ÷ 15 × 60 = 80 beats/min
2
SCALE PER PERSON PER YEAR
80 × 60 × 24 × 365 — round to simplify
≈ 100 × 50 × 20 × 400 = 4 × 10⁷ beats/year
3
SCALE TO UK POPULATION
Multiply by UK population ≈ 6 × 10⁷ people
6 × 10⁷ × 4 × 10⁷ = 24 × 10¹⁴
TOTAL UK HEARTBEATS/YEAR
2.4 × 10¹⁵ beats per year
Example 6 — Radius of the Earth
Scale from UK length → Earth's radius
1
KNOWN QUANTITY
Estimate the length of the UK (Land's End to John O'Groats)
UK length ≈ 1 000 km
2
VISUAL SCALING FROM GLOBE
From a globe, the Earth's radius looks about 6 × the UK length
radius ≈ 6 × 1 000 km
3
CHECK AGAINST ACTUAL VALUE
Actual radius of Earth = 6 371 km — very close!
estimate: 6 000 km ✓
ESTIMATED EARTH RADIUS
6 000 km (actual: 6 371 km)
3.4 Estimation Technique 2: Subdividing
Subdividing: Break a difficult estimation problem into smaller, more manageable geometric parts — then combine the results.
EXAMPLE 7
Land Area of the British Isles
GREAT BRITAIN
+
IRELAND
=
≈ 3×10⁵
km²
1
Approximate Great Britain as a triangle: height 1000 km , base 500 km
2
Area of GB = ½ × 500 × 1000 = 2.5 × 10⁵ km²
3
Approximate Ireland as a square: side 250 km
4
Area of Ireland = 250² ≈ 6 × 10⁴ km²
5
Total = 2.5×10⁵ + 6×10⁴ ≈ 3 × 10⁵ km²
Total land area of British Isles ≈ 3 × 10⁵ km²
EXAMPLE 8
Volume of Water in Earth's Oceans
Radius of Earth ≈ 6000 km
Ocean coverage ≈ 70% of surface
Mean depth ≈ 4 km
1
Radius of Earth ≈ 6000 km
2
Surface area = 4πr² ≈ 4 × 3 × 6000² ≈ 4 × 10⁸ km²
3
70% is ocean → ocean surface ≈ 3 × 10⁸ km²
4
Mean ocean depth ≈ 4 km
5
Volume = 3×10⁸ × 4 ≈ 10⁹ km³
Volume of Earth's oceans ≈ 10⁹ km³
Exercise 3B — Questions
CHAPTER 3.4
💡 All data needed is in the Reference Panel on the left — use Speed = Distance ÷ Time and the Gulf Stream facts to answer Q4–Q6.
📋 REFERENCE DATA — USE THESE TO ANSWER THE QUESTIONS
Pulse:
Count beats for 10 seconds, then × 6 = beats per minute
Heart rate:
Typical resting rate ≈ 60–80 beats per minute
Lifetime to age 18:
18 years × 365 days × 24 h × 60 min
England → New York:
Distance ≈ 5 500 km
American ships:
Journey time ≈ 20 days (mid-19th century)
Gulf Stream:
Warm current flowing NE from Florida to UK
Gulf Stream speed:
≈ 6 km/h (flows towards UK, not towards USA)
Gulf Stream length:
Florida to UK ≈ 7 000 km
Africa (N–S):
Estimate from globe — compare to known distances
Mercator maps:
Distort size near the poles — Greenland appears much larger than it really is
Speed formula:
Speed = Distance ÷ Time
Time formula:
Time = Distance ÷ Speed
Q1 — GLOBE ESTIMATION
Use a globe to estimate:
(a) Distance south to north of Africa
(b) Distance west to east of Africa at its widest point
(c) Length of the Gulf Stream from Florida to the UK
Q2 — SCALING
Count your pulse for 10 seconds. Estimate how many times your heart beats from birth to your 18th birthday.
Q3 — MAP DISTORTION
Daisy estimated Greenland's length from a map and found it very inaccurate.
(a) What might she not have noticed about the map?
(b) Would this make her estimate too small or too large?
(c) How could she improve her method?
Q4 — SPEED CALCULATION
American ships sailed England → New York in ≈ 20 days. Estimate their average speed in km/h. (Distance ≈ 5 500 km)
Q5 — GULF STREAM REASONING
British ships took significantly longer for the same journey.
(a) What could have affected their speed? (Hint: think about the Gulf Stream direction)
(b) How had American captains avoided this problem?
Q6 — FERMI ESTIMATE
Estimate how much longer British ships took. Use Gulf Stream speed ≈ 6 km/h and ship speed ≈ 11 km/h.
Exercise 3B — Answers
✓ WORKED SOLUTIONS
Full worked answers for all six questions in Exercise 3B — estimation using globes, Fermi techniques, and real-world geography.
Key Insight: Gulf Stream knowledge gave American captains a decisive navigational advantage — a real-world example of how estimation and geography intersect.
Q1 / GLOBE ESTIMATION
Africa Dimensions & Gulf Stream Length
(a) Africa north–south ≈ 8 000 km | (b) Africa east–west ≈ 7 500 km | (c) Gulf Stream (Florida → UK) ≈ 7 000 km
Q2 / FERMI ESTIMATE
Heartbeats from Birth to Age 18
80 × 60 × 24 × 365 × 18 ≈ 7.6 × 10⁸ beats. Approximately 760 million heartbeats by your 18th birthday.
Q3 / MAP DISTORTION
Greenland & Mercator Projection
(a) Mercator projection greatly exaggerates land area near the poles. (b) Estimate would be too large . (c) Use a globe or an equal-area projection map.
Q4 / SPEED CALCULATION
American Ships: England to New York
Distance ≈ 5 500 km . Time = 20 days × 24 h = 480 h . Average speed = 5 500 ÷ 480 ≈ 11 km/h .
Q5 / GULF STREAM
Why British Ships Were Slower
(a) British ships sailed against the Gulf Stream current, adding resistance. (b) American captains knew about the Gulf Stream and used it to speed their return journey.
Q6 / FERMI ESTIMATE
How Much Longer Did British Ships Take?
Gulf Stream speed ≈ 6 km/h resistance added to journey. This makes the trip roughly 50% longer → approximately 10 extra days compared to American ships.
3.5 Estimation Technique 3: Stating Assumptions
EXAMPLE 9
Key Principle: State assumptions clearly so they can be checked and improved later — even rough assumptions can give surprisingly accurate results.
ASSUMPTIONS
CALCULATION STEPS
Step 1
Volume for fish
= 10¹⁸ × (20 ÷ 4000)
= 5 × 10¹⁵ m³
Step 2
Number of fish
= 5 × 10¹⁵ ÷ 10³
= 5 × 10¹²
Step 3
Final answer
5 × 10¹² fish
≈ 5 trillion fish
OUR ESTIMATE
5 × 10¹²
≈ 5 trillion fish
Finding Nemo claimed there are 3.7 trillion fish in the ocean — remarkably close to our estimate!
OCEAN VOLUME
10⁹ km³
= 10¹⁸ m³
AVG. DEPTH
4 km
= 4000 m total
FISH ZONE
Top 20 m
Most fish live near surface
TERRITORY / FISH
10 m cube
= 10³ m³ per fish
Earth's oceans — how many fish?
Example 1 & 2: Stating Assumptions
AQA Chapter 3.5
Key Principle: Always state your assumptions clearly before calculating — this allows others (and you) to review, challenge, and improve them later.
&
Example 1: Fish in Earth's Oceans
How many fish are there? (Example 9 in book)
ASSUMPTIONS
Volume of oceans = 10⁹ km³ = 10¹⁸ m³
Most fish live in top 20 m below surface
Each fish has territory = cube of side 10 m = 10³ m³
CALCULATION
1
Volume for fish = 10¹⁸ × (20 ÷ 4000) = 5 × 10¹⁵ m³
2
Number of fish = 5 × 10¹⁵ ÷ 10³ = 5 × 10¹²
ANSWER
5 × 10¹² ≈ 5 trillion fish
Finding Nemo estimated 3.7 trillion — remarkably close!
Key: state each assumption clearly so it can be checked and improved later
Example 2: Shanghai Maglev Journey
How long to travel the length of Great Britain? (Example 10)
ASSUMPTIONS
Shanghai Maglev speed = 430 km/h
Length of Great Britain ≈ 1000 km
Approximate 430 ≈ 400 for easier mental arithmetic
CALCULATION
1
Formula: Time = Distance ÷ Speed
2
Time = 1000 ÷ 430 ≈ 1000 ÷ 400 = 2.5 hours
ANSWER
≈ 2.5 hours
Rounding 430 → 400 makes division straightforward
Word formula: Speed = Distance ÷ Time → Time = Distance ÷ Speed
3.6
Useful Facts & Formulae
Human Body
▸
80 kg
— typical weight
▸
1.7 m
— typical height
▸
75 yr
— lifetime
▸
80 bpm
— heart rate
▸
5 L
— blood volume
▸
10 m/s
sprint · 3 mph walk
Earth
▸
6 000 km
— radius
▸
1 rotation
per day
▸
1 orbit
per year (365 days)
▸
10⁹ km³
— ocean volume
▸
4 km
— avg ocean depth
Water & Density
▸
1 g/cm³
— density of water
▸
1 litre
= 1 000 cm³
▸
1 m³
= 1 000 litres
▸
Density = Mass ÷ Volume
Data Storage
▸
1 bit
= binary digit (0 or 1)
▸
1 byte
= 8 bits
▸
1 KB
= 10³ bytes
▸
1 MB
= 10⁶ bytes
▸
1 GB
= 10⁹ bytes
Equivalences
▸
1 mile
≈ 1 600 m
▸
1 foot
≈ 30 cm
▸
1 pound
≈ 500 g
▸
1 year
≈ 3.15 × 10⁷ s
▸
1 hour
= 3 600 s
Key Formulae
▸
V = l³
— cube volume
▸
A = 4πr²
— sphere surface
▸
V = (4/3)πr³
— sphere volume
▸
T = D ÷ S
— time = dist ÷ speed
▸
A = πr²
— circle area
AQA Advanced Maths — Chapter 3.6 Reference
CHAPTER 3.6 — WORKED EXAMPLES
Example 1 & 2: Using Facts & Formulae
EXAMPLE 1 (BOOK: EX. 11)
Earth's Density
GIVEN
Mass of Earth = 6 × 10²⁷ g
Volume of Earth = 1.1 × 10²⁷ cm³
1
Write the formula
Density = Mass ÷ Volume
2
Substitute values
= (6 × 10²⁷) ÷ (1.1 × 10²⁷)
3
Divide coefficients; subtract powers: 27 − 27 = 0
= (6 ÷ 1.1) × 10⁰ ≈ 5.5 × 1
Density ≈ 5.5 g/cm³
Earth is the most dense planet in the Solar System
EXAMPLE 2 (BOOK: EX. 4)
Water Molecules in Your Body
GIVEN
Body mass = 70 kg = 7 × 10¹ kg
Mass of H₂O molecule = 3 × 10⁻²⁶ kg
1
Write the formula
Number = Body mass ÷ Molecule mass
2
Substitute values
= (7 × 10¹) ÷ (3 × 10⁻²⁶)
3
Divide coefficients; subtract powers: 1 − (−26) = 27
= (7 ÷ 3) × 10²⁷ ≈ 2.3 × 10²⁷
≈ 2 × 10²⁷ molecules
That's 2 octillion water molecules in a 70 kg body
÷
AQA CHAPTER 3.7 — MODELLING CYCLE: STEP 4
Critically Evaluating Models — Light Through History
55 BC
Lucretius
Light = particles travelling to the eye (Ancient Greece)
Late 1600s
Newton (corpuscles) vs Huygens (waves) —competing models emerge
1700s
Newton's corpuscular theory prevails — particle model dominates
1800s
Maxwell's wave theory becomes accepted — light travels as electromagnetic waves
Early 1900s
Einstein — photoelectric effect proves light is photons (particles again)
21st Century
Wave–particle duality —light exhibits both properties simultaneously
Key Lesson: Models are refined over time — a good model that is later improved is still valuable. It paves the way for further progress. The modelling cycle: Represent → Use techniques → Interpret → Compare with data → Improve.
EARLY / SUPERSEDED
ESTABLISHED MODEL
CURRENT UNDERSTANDING
Consolidation Exercise 3 — Questions
CHAPTER 3 · AQA MATHEMATICAL STUDIES
Apply your modelling and estimation skills to the following six questions. State all assumptions clearly and show your working.
Technique reminder: For each question, identify whether you are using scaling , subdividing , or known facts and formulae — and state your assumptions explicitly.
Q1 · ESTIMATION
Fish in the Oceans
How many fish are there in the Earth's oceans? State all assumptions you make and explain your estimation technique.
Q4 · REAL-WORLD CONTEXT
Grace Madeje's Water Journey
Grace lives 11 km from the nearest water source. Estimate how many hours per day she spends collecting water.
Q2 · STANDARD FORM
Antarctic Ice Melt — Sea Level Rise
If all Antarctic ice melts, by how much will the oceans rise? Ice cap area ≈ 14 ×10⁶ km², thickness ≈ 2 km, ocean area ≈ 3 × 10⁸ km².
Q5 · FORMULAE
Blood Pumped in a Lifetime
Estimate the total volume of blood your heart pumps in a lifetime. Blood ≈ 7% of body volume; all blood passes through the heart every 1 minute.
Q3 · SCALING
Access to Safe Water
How many people worldwide do not have access to safe water? Roughly 1 in 9 people lack safe water access.
Q6 · STANDARD FORM
Voyager 1 to Alpha Centauri
Voyager 1 travels at 6.1 × 10⁴ km/h . Distance to Alpha Centauri = 2.4 light years . How many years to travel there?
Full worked answers for all six questions. Key steps shown for each calculation — all use standard form and estimation techniques from Chapter 3.
Key Takeaway: All six answers apply standard form arithmetic — multiply/divide powers of 10, state assumptions clearly, and interpret results in context.
Q1 / FISH IN THE OCEANS
≈ 5 × 10¹² fish (5 trillion)
See Example 9 for full working. Scale from known fish densities across ocean zones to estimate total global population.
Q4 / GRACE'S WATER COLLECTION
≈ 5.5 hours per day
11 km each way → 22 km round trip. Walking speed ≈ 4 km/h → 22 ÷ 4 ≈ 5.5 hours/day collecting water.
Q2 / ANTARCTIC ICE MELT — SEA LEVEL RISE
Sea level rise ≈ 90 m
Ice volume = 14×10⁶ × 2 = 2.8×10⁷ km³. Rise = 2.8×10⁷ ÷ 3×10⁸ ≈ 0.09 km = 90 m .
Q5 / BLOOD PUMPED IN A LIFETIME
≈ 2 × 10⁸ litres
Blood ≈ 5 L, pumped every minute. 5 × 60 × 24 × 365 × 75 ≈ 2 × 10⁸ litres over a 75-year lifetime.
Q3 / PEOPLE WITHOUT SAFE WATER
≈ 9 × 10⁸ people (900 million)
World population ≈ 8×10⁹. 1/9 × 8×10⁹ ≈ 9×10⁸ . That is about 13 times the UK population (6.7×10⁷).
Q6 / VOYAGER 1 TO ALPHA CENTAURI
≈ 42,000 years
1 light year ≈ 9.5×10¹² km. Distance = 2.4×9.5×10¹² ≈ 2.3×10¹³ km. Time = 2.3×10¹³ ÷ 6.1×10⁴ ÷ 8760 ≈ 42,000 years .
Consolidation Exercise 3 — Answers
✓ WORKED SOLUTIONS
Key Formulae & Methods Summary
Chapter 3 · Sections 3.1–3.7
STANDARD FORM
a × 10ⁿ where 1 ≤ a < 10
Expresses very large or very small numbers in compact scientific notation.
MULTIPLYING STD FORM
(a × 10ᵐ) × (b × 10ⁿ)
= (a × b) × 10^(m+n)
Multiply the coefficients; add the powers of 10.
DIVIDING STD FORM
(a × 10ᵐ) ÷ (b × 10ⁿ)
= (a ÷ b) × 10^(m−n)
Divide the coefficients; subtract the powers of 10.
VOLUME FORMULAE
Cuboid: V = l × w × h
Cylinder: V = πr²h
Used to model real-world volumes such as ocean currents and ice caps.
SURFACE AREA — SPHERE
SA = 4πr²
V = (4/3)πr³
Surface area and volume of a sphere; key for planetary and biological models.
SPEED & DENSITY
Speed = Distance ÷ Time
Density = Mass ÷ Volume
Applied to Voyager 1 travel time and Earth's density calculations.
ESTIMATION TECHNIQUES
① Scaling — known → unknown
② Subdividing — break into parts
③ State all assumptions clearly. Fermi estimation builds on these three strategies.
MODELLING CYCLE
Represent → Techniques
→ Interpret → Compare →Improve
Critically evaluate and refine models; good models pave the way for further progress.
Interactive Quiz — Modelling & Estimation
CHAPTER 3
1
2
3
4
5
Question 1 of 5
TIME
29
Reveal Answer
Next
Restart
QUESTION 1 — STANDARD FORM
Write 85 000 000 in standard form.
Remember: standard form is a × 10ⁿ where 1 ≤ a < 10
Prev
CHAPTER SUMMARY
TOPICS MASTERED
Gulf Stream modelling — volume flow, real-world geometric approximation
Standard form — multiply & divide powers of 10 without a calculator
Three Fermi techniques — scaling, subdividing, and stating assumptions clearly
Critical evaluation — refining models using the four-step modelling cycle
NEXT STEPS
Practise past AQA exam questions on standard form and estimation
Apply the modelling cycle to real-world problems of your choice
Review the key formulae card — volume, surface area, speed, density
Well done! A model that is later improved is still valuable — it paves the way for further progress. Keep thinking mathematically.
AQA MATHEMATICAL STUDIES
Chapter 3
Complete!
Modelling & Estimation — from the Gulf Stream to the stars. You've mastered the tools of mathematical thinking.
Gulf Stream
Standard Form
Fermi Estimation
Critical Evaluation
Chapter 3 Quiz
MODELLING & ESTIMATION
QUESTION 1 OF 5
Write 85 000 000 in standard form.
29
Reveal Answer