�SEASONAL PERFORMANCE OF�INDUCED AND FORCED DRAUGHT COOLING TOWER
Presented By
PROJECT GUIDE :-DR. U. V. ASWALEKAR
CO-GUIDE :-PROF. RAAHUL KRISHNA
INTRODUCTION
Objectives�
ABSTRACT
In a cooling tower, water is pumped to the top of the tower & while descending it brakes into minute particles, which comes in contact with the air which cools it. The water is then collected in the tank below on the basis of the draught. The cooling towers we are dealing with are forced & induced type towers.
FORCED DRAUGHT TYPE: The circulation of the air depends upon the fans/blower/pneumatic power supplies located at the bottom of the tower.
INDUCED DRAUGHT TYPE: The prime mover is located at the top from the construction point.
After understanding both the apparatus available in our college we have taken down sample observations twice on both the apparatus and fixed the flaws, cracks, leakages.
As our project deals with the seasonal analysis of both the cooling towers, we have started taking the observations/readings from 1st of October 2019 {WINTER SEASON}, different parameters required for the calculations are been are recorded for five working days of the week uptill now.
Parameters such as RANGE, APPROACH, EFFICIENCY, ALL TEMPERATURES {BOTH WBT & DBT}, WINDAGE LOSS, EVAPORATIVE LOSS, DRIFT LOSS, etc. are been calculated.
Forced draught cooling tower
Induced draught cooling tower
THERMAL ANALYSIS OF FILLS USING SOLIDWORKS
THERMAL ANALYSIS RESULT
MAX 3.133e+02 K
Observations for forced draught cooling tower:
Observation table:
Sr ` | T1 | T2 | T3 | T4 | T5 | T6 | T7 | T8 | Water Flow in lpm | Manometer Difference In mm |
1 | 33 | 24 | 23 | 23 | 31 | 30 | 30 | 35 | 6 | 160 |
2 | 35 | 25 | 21 | 22 | 28 | 31 | 29 | 38 | 5 | 160 |
3 | 37 | 26 | 22 | 22 | 29 | 31 | 29 | 39 | 4 | 160 |
Observations for forced draught :
Sample calculations for forced draught
CT Range (°C) = [HW inlet temp (°C) – CW outlet temp (°C)]
=33-23
=10
CT Approach (°C) = [CW outlet temp (°C) – Wet bulb temp (°C)]
=24-23
=1
ε = (RANGE)/(RANGE+APPROACH)
=(10)/(10+1)
=0.8182=81.82%
Calculation for Reading no 1
Q=M*CP*dT
1.5=M*4.187*10
M=0.039m3/hr
=0.00085*1.8*0.039*10
=0.00055m3/hr
RESULT TABLE
Forced Draught Cooling Tower Project | ||||||||||
Sl No | Date | Water Flowrate�(LPM) | Water Temperature |
| Air Temperature | Performance | ||||
T1 (inlet) | T2 (outlet) | WBT (air inlet) | T3 (inlet) | T4 (outlet) | Range | Approach | Tower Effective -ness | |||
1 | 12/3/2020
| 6 | 33 | 24 | 23 | 23 | 31 | 9 | 2 | 81.82% |
2 | 5 | 35 | 25 | 22 | 21 | 28 | 10 | 3 | 76.92% | |
3 | 4 | 37 | 26 | 22 | 22 | 39 | 11 | 4 | 73.33% | |
Forced draught
Forced draught
Week number
Forced draught
Observations for Induced draught cooling tower:
SR NO | T1 | T2 | T3 | T4 | T5 | WATER FLOW IN LPM |
1 | 29 | 22 | 21 | 23 | 21 | 6.66 |
2 | 31 | 23 | 20 | 23 | 21 | 5 |
3 | 35 | 24 | 20 | 26 | 21 | 3.33 |
OBSERVATIONS FOR INDUCED DRAUGHT
Sample calculations for induced draught
CT Range (°C) = [HW inlet temp (°C) – CW outlet temp (°C)] =
=29-22
=7
CT Approach (°C) = [CW outlet temp (°C) – Wet bulb temp (°C)]
=22-21
=1
ε = (RANGE)/(RANGE+APPROACH)
=(7)/(7+1)
=0.875=87.5%
Calculation for Reading no 1
Q=M*CP*dT
4.5=M*4.187*7
M=0.153m^3/hr
=0.00085*1.8*0.153*7
=0.0016m^3/hr
RESULT TABLE
Induced Draught Cooling Tower Project | ||||||||||
Sl No | Date
| Water Flowrate�(LPM) | Water Temperature |
| Air Temperature | Performance | ||||
T1 (inlet) | T2 (outlet) | WBT (air inlet) | T3 (inlet) | T4 (outlet) | Range | Approach | Tower Effective -ness | |||
1 | 12/03/2020
| 6.66 | 29 | 22 | 21 | 21 | 23 | 7 | 1 | 87.5% |
2 | 5 | 31 | 23 | 21 | 20 | 23 | 8 | 2 | 80% | |
3 | 3.33 | 35 | 24 | 21 | 20 | 26 | 11 | 3 | 78.5% | |
Induced draught
Induced draught
Induced draught
Induced v/s forced (comparison of range at 5 lpm)
Week number
Temprature (deg c)
conclusions:
THANK YOU