ARITHMETIC
PROGRESSIONS
a16 = 73
7) Find the 31st term of an AP whose 11th term is 38 and
the 16th term is 73:
Sol:
For given AP:
a11 = 38,
a11 = a + 10d
∴ 38
= a + 10d
…..(i)
a16 = a + 15d
∴ 73
= a + 15d
…..(ii)
Subtracting (i) from (ii)
a + 15d =
73
a + 10d =
38
( - )
( - )
( - )
5d =
35
d = 7
Substituting d = 7 in (i)
a + 10(7) =
38
∴ a + 70 =
38
∴ a =
38 – 70
∴ a =
– 32
Now, lets find a31
a31 = a + 30d
= – 32 + 30(7)
∴ a31 = 178
= – 32 + 210
∴ 31st term of AP is 178.
We know that,
We need to find a31
These are linear eqn
in 2 variables a & d
Since, terms with variable ‘a’
has same coefficient and same sign
∴Subtract the two equations
Exercise 5.2 7
8) An AP consists of 50 terms of which 3rd term is 12 and
last term is 106. Find the 29th term.
Sol:
We need to find a29
For given AP:
a3 = 12,
a50 = 106
a3 = a + 2d
∴ 12
= a + 2d
…..(i)
a50 = a + 49d
∴ 106
= a + 49d
…..(ii)
Subtracting (i) from (ii)
a + 49d =
106
a + 2d =
12
( - )
( - )
( - )
47d =
94
d = 2
These are linear eqn
in 2 variables a & d
Substituting d = 2 in (i)
a + 2(2) =
12
∴ a + 4 =
12
∴ a =
12 – 4
∴ a =
8
Now, lets find a29
a29 = a + 28d
= 8 + 28(2)
∴ a29 = 64
= 8 + 56
∴ 29th term of AP is 64.
We know that,
Since, AP consist of 50 terms
Then, last term is a50
Since, terms with variable ‘a’
has same coefficient and same sign
Subtract the two equations
Exercise 5.2 8
HOMEWORK