DEPARTMENT OF CIVIL ENGINEERING
TOPIC-DETERMING REDUCED LEVELS OF FIVE GIVEN POINTS
SEMESTER-4TH
BY-MRS. MANDALINI MOHANTA
AY:2021-2022
Figure of Dumpy Level
Definition
A level surface is a surface which is everywhere perpendicular to the direction of the force of gravity. An example is the surface of a completely still lake. For ordinary levelling, level surfaces at different elevations can be considered to be parallel.
A level datum is an arbitrary level surface to which elevations are referred. The most common surveying datum is mean sea-level (MSL).
An assumed datum, which is established by giving a benchmark an assumed value (e.g. 100.000 m) to which all levels in the local area will be reduced. It is not good practice to assume a level which is close to the actual MSL value, as it creates potential for confusion.
A reduced level is the vertical distance between a survey point and the adopted level datum.
A bench mark (BM) is the term given to a definite, permanent accessible point of known height above a datum to which the height of other points can be referred.
Back Sight: The first observation is made to the known point.
Intermediate Sight: Staff readings between BS and FS.
Fore Sight : The last observation is to the final point before shifting the instrument.
Change points: They are points of measurement which are used to carry the measurements forward in a run. Each one will be read first as a foresight, the instrument position is changed, and then it will be read as a back sight.
Height of Collimation is the elevation of the optical axis of the telescope at the time of the setup. The line of collimation is the imaginary line at the elevation.
Axis of Telescope: Imaginary line passing through optical center of eye piece and object glass
Methods to calculate reduced level.
The Height Of Instrument Method.
the height of instrument is calculated by adding the backsight reading (bs) to the rl of the bm (first method).
Rl of hi = rl of bm +bs
Observation Table: (BY HI Method)
Sr.No. | Station | BS | IS | FS | HI | RL | Remark |
1 | A | 1.36 | | | 51.360 | 50.00 | RL of BM = 50.0m |
2 | B | | 1.19 | | | 50.17 | |
3 | C | | 1.04 | | | 50.32 | |
4 | D | | 0.895 | | | 50.465 | |
5 | E | | 0.735 | | | 50.625 | |
6 | F | | 0.580 | | | 50.780 | |
7 | G | | 0.535 | | | 50.825 | |
8 | H | | 0.415 | | | 50.945 | |
9 | I | | | 1.085 | | 50.275 | |
| | ∑BS=1.36 | | ∑FS=1.085 | | | |
Arithmetic Check: ∑BS−∑FS = LRL − FRL
1.36 – 1.085 = 50.275 – 50.00
0.275 = 0.275 (Checked)
Calculations by HI method
The Rise And Fall Method.
Rl of point b = rl of a + rise.
Rl of b= rl of a- fall.
Observation Table: (BY Rise & Fall Method)
Sr.No. | St. | BS | IS | FS | Rise | Fall | RL | Remark |
1 | A | 1.36 | | | | | 50.00 | RL of BM = 50.0m |
2 | B | | 1.19 | | 0.170 | | 50.17 | |
3 | C | | 1.04 | | 0.150 | | 50.32 | |
4 | D | | 0.895 | | 0.145 | | 50.465 | |
5 | E | | 0.735 | | 0.160 | | 50.625 | |
6 | F | | 0.580 | | 0.155 | | 50.780 | |
7 | G | | 0.535 | | 0.045 | | 50.825 | |
8 | H | | 0.415 | | 0.12 | | 50.945 | |
9 | I | | | 1.085 | | 0.67 | 50.275 | |
| | ∑BS=1.36 | | ∑FS=1.085 | ∑Rise=0.945 | ∑Fall=0.67 | | |
Arithmetic Check: ∑BS−∑FS = LRL − FRL = ∑Rise - ∑Fall
1.36 – 1.085 = 50.275 – 50.00 = 0.945 – 0.67
0.275 = 0.275 = 0.275 (Checked)
Calculations by Rise & Fall Method
∑BS(a)−∑IS(b) = 1.36 -1.19 = 0.170 ( Rise of b ) | RL(b) = RL(a) + Rise (b)= 50.00 + .170 = 50.17 |
∑IS(b)−∑IS(c) =1.19 – 1.04 = +0.150 ( Rise of c ) | RL(c) = RL(b) + Rise(c) = 50.17 + 0.150 =50.32 |
∑IS(c)−∑IS(d) =1.04 – 0.895 = +0.145 ( Rise of d) | RL(d) = RL(c) + Rise(d) = 50.32+ 0.145 = 50.465 |
∑IS(d)−∑IS(e) =0.895 – 0.735 =+0.160 (Rise of e ) | RL(e) = RL(d) + Rise(e) = 50.465 + 0.160 = 50.625 |
∑IS(e)−∑IS(f) =0.735 – 0.580 =+0.155 ( Rise of f ) | RL(f) = RL(e) + Rise(f) = 50.625 + 0.580 = 50.780 |
∑IS(f)−∑IS(g) =0.580 – 0.535 =+0.045 ( Rise of g ) | RL(g) = RL(f) + Rise(g) = 50.780 + 0.535 = 50.825 |
∑IS(g)−∑IS(h) =0.535 – 0.415 =+0.12 ( Rise of h ) | RL(h) = RL(g) + Rise(h) = 50.825 + 0.415 = 50.945 |
∑IS(h) −∑FS(i) =0.415 – 1.085 = - 0.67 ( Fall of i ) | RL(i) = RL(h) - Fall(i) = 50.945 – 1.085 = 50.275 |