Ch. 4: Isomorphism
(2) These two squares do NOT have exactly the same symmetry groups:
(2) These two squares do NOT have exactly the same symmetry groups:
(Symmetries of the red square are NOT also symmetries of the green square
because they move the green square around.)
(2) These two squares do NOT have exactly the same symmetry groups:
BUT the squares are rigidly equivalent, so their symmetry groups
are essentially the same.
What should this mean? How are their Cayley tables similar?
Rene’s red square:
{I, R90, R180, R270, H, V, D, D’}.
* | I | R90 | R180 | R270 | H | V | D | D’ |
I | I | R90 | R180 | R270 | H | V | D | D’ |
R90 | R90 | R180 | R270 | I | D’ | D | H | V |
R180 | R180 | R270 | I | R90 | V | H | D’ | D |
R270 | R270 | I | R90 | R180 | D | D’ | V | H |
H | H | D | V | D’ | I | R180 | R90 | R270 |
V | V | D’ | H | D | R180 | I | R270 | R90 |
D | D | V | D’ | H | R270 | R90 | I | R180 |
D’ | D’ | H | D | V | R90 | R270 | R180 | I |
(Same Cayley table we built in Ch. 2)
Rene’s red square:
{I, R90, R180, R270, H, V, D, D’}.
* | I | R90 | R180 | R270 | H | V | D | D’ |
I | I | R90 | R180 | R270 | H | V | D | D’ |
R90 | R90 | R180 | R270 | I | D’ | D | H | V |
R180 | R180 | R270 | I | R90 | V | H | D’ | D |
R270 | R270 | I | R90 | R180 | D | D’ | V | H |
H | H | D | V | D’ | I | R180 | R90 | R270 |
V | V | D’ | H | D | R180 | I | R270 | R90 |
D | D | V | D’ | H | R270 | R90 | I | R180 |
D’ | D’ | H | D | V | R90 | R270 | R180 | I |
How can Gretchen copy Rene’s work to build her Cayley table?
Gretchen’s green square:
{I, R90, R180, R270, F1, F2, F3, F4}.
* | | | | | | | | |
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Rene’s red square:
{I, R90, R180, R270, H, V, D, D’}.
* | I | R90 | R180 | R270 | H | V | D | D’ |
I | I | R90 | R180 | R270 | H | V | D | D’ |
R90 | R90 | R180 | R270 | I | D’ | D | H | V |
R180 | R180 | R270 | I | R90 | V | H | D’ | D |
R270 | R270 | I | R90 | R180 | D | D’ | V | H |
H | H | D | V | D’ | I | R180 | R90 | R270 |
V | V | D’ | H | D | R180 | I | R270 | R90 |
D | D | V | D’ | H | R270 | R90 | I | R180 |
D’ | D’ | H | D | V | R90 | R270 | R180 | I |
Gretchen’s green square:
{I, R90, R180, R270, F1, F2, F3, F4}.
* | | | | | | | | |
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I | R90 | R180 | R270 | H | D’ | V | D |
↕ | ↕ | ↕ | ↕ | ↕ | ↕ | ↕ | ↕ |
I | R90 | R180 | R270 | F1 | F2 | F3 | F4 |
She should use this dictionary to convert as she copies!
Rene’s red square:
{I, R90, R180, R270, H, V, D, D’}.
* | I | R90 | R180 | R270 | H | V | D | D’ |
I | I | R90 | R180 | R270 | H | V | D | D’ |
R90 | R90 | R180 | R270 | I | D’ | D | H | V |
R180 | R180 | R270 | I | R90 | V | H | D’ | D |
R270 | R270 | I | R90 | R180 | D | D’ | V | H |
H | H | D | V | D’ | I | R180 | R90 | R270 |
V | V | D’ | H | D | R180 | I | R270 | R90 |
D | D | V | D’ | H | R270 | R90 | I | R180 |
D’ | D’ | H | D | V | R90 | R270 | R180 | I |
Gretchen’s green square:
{I, R90, R180, R270, F1, F2, F3, F4}.
* | I | R90 | R180 | R270 | F1 | F3 | F4 | F2 |
I | I | R90 | R180 | R270 | F1 | F3 | F4 | F2 |
R90 | R90 | R180 | R270 | I | F2 | F4 | F1 | F3 |
R180 | R180 | R270 | I | R90 | F3 | F1 | F2 | F4 |
R270 | R270 | I | R90 | R180 | F4 | F2 | F3 | F1 |
F1 | F1 | F4 | F3 | F2 | I | R180 | R90 | R270 |
F3 | F3 | F2 | F1 | F4 | R180 | I | R270 | R90 |
F4 | F4 | F3 | F2 | F1 | R270 | R90 | I | R180 |
F2 | F2 | F1 | F4 | F3 | R90 | R270 | R180 | I |
This creates a valid Cayley table for Gretchen (each cell is filled in correctly)!
I | R90 | R180 | R270 | H | D’ | V | D |
↕ | ↕ | ↕ | ↕ | ↕ | ↕ | ↕ | ↕ |
I | R90 | R180 | R270 | F1 | F2 | F3 | F4 |
* | I | R90 | R180 | R270 | H | V | D | D’ |
I | I | R90 | R180 | R270 | H | V | D | D’ |
R90 | R90 | R180 | R270 | I | D’ | D | H | V |
R180 | R180 | R270 | I | R90 | V | H | D’ | D |
R270 | R270 | I | R90 | R180 | D | D’ | V | H |
H | H | D | V | D’ | I | R180 | R90 | R270 |
V | V | D’ | H | D | R180 | I | R270 | R90 |
D | D | V | D’ | H | R270 | R90 | I | R180 |
D’ | D’ | H | D | V | R90 | R270 | R180 | I |
* | I | R90 | R180 | R270 | F1 | F3 | F4 | F2 |
I | I | R90 | R180 | R270 | F1 | F3 | F4 | F2 |
R90 | R90 | R180 | R270 | I | F2 | F4 | F1 | F3 |
R180 | R180 | R270 | I | R90 | F3 | F1 | F2 | F4 |
R270 | R270 | I | R90 | R180 | F4 | F2 | F3 | F1 |
F1 | F1 | F4 | F3 | F2 | I | R180 | R90 | R270 |
F3 | F3 | F2 | F1 | F4 | R180 | I | R270 | R90 |
F4 | F4 | F3 | F2 | F1 | R270 | R90 | I | R180 |
F2 | F2 | F1 | F4 | F3 | R90 | R270 | R180 | I |
This dictionary converts every true red equation into a true green equation!
H*D = R90
F1*F4 = R90
convert
I | R90 | R180 | R270 | H | D’ | V | D |
↕ | ↕ | ↕ | ↕ | ↕ | ↕ | ↕ | ↕ |
I | R90 | R180 | R270 | F1 | F2 | F3 | F4 |
DEFINITION: An isomorphism between two groups means a one-to-one matching (dictionary)
between their members that converts each true equation in one group into a true equation
in the other.
We say two groups are isomorphic there exists an isomorphism between them.
Thus, the symmetry group of the red square is isomorphic to
the symmetry group of the green square.
I | R90 | R180 | R270 | H | D’ | V | D |
↕ | ↕ | ↕ | ↕ | ↕ | ↕ | ↕ | ↕ |
I | R90 | R180 | R270 | F1 | F2 | F3 | F4 |
I | R90 | R180 | R270 | H | V | D | D’ |
↕ | ↕ | ↕ | ↕ | ↕ | ↕ | ↕ | ↕ |
I | R90 | R180 | R270 | F1 | F2 | F3 | F4 |
DEFINITION: An isomorphism between two groups means a one-to-one matching (dictionary)
between their members that converts each true equation in one group into a true equation
in the other.
We say two groups are isomorphic there exists an isomorphism between them.
EXERCISE: Prove that this dictionary is NOT an isomorphism between the red and green groups.
I | R90 | R180 | R270 | H | V | D | D’ |
↕ | ↕ | ↕ | ↕ | ↕ | ↕ | ↕ | ↕ |
I | R90 | R180 | R270 | F1 | F2 | F3 | F4 |
DEFINITION: An isomorphism between two groups means a one-to-one matching (dictionary)
between their members that converts each true equation in one group into a true equation
in the other.
We say two groups are isomorphic there exists an isomorphism between them.
EXERCISE: Prove that this dictionary is NOT an isomorphism between the red and green groups.
When a pair of finite groups are isomorphic, they have the same patterns in their Cayley tables. An observer who doesn’t know or care what the names of the group members represent would study the two Cayley tables and discover exactly the same patterns. From this observer’s perspective, the two groups would look like a single group represented in two different notational systems.
When a pair of finite groups are isomorphic, they have the same patterns in their Cayley tables. An observer who doesn’t know or care what the names of the group members represent would study the two Cayley tables and discover exactly the same patterns. From this observer’s perspective, the two groups would look like a single group represented in two different notational systems.
When a pair of finite groups are isomorphic, they have the same patterns in their Cayley tables. An observer who doesn’t know or care what the names of the group members represent would study the two Cayley tables and discover exactly the same patterns. From this observer’s perspective, the two groups would look like a single group represented in two different notational systems.
In fact, here is a description that characterizes both groups simultaneously: in addition to the identity, there are two more members. Each is the inverse of the other. Each combines with itself to give the other.
In fact, here is a description that characterizes both groups simultaneously: in addition to the identity, there are two more members. Each is the inverse of the other. Each combines with itself to give the other.
To what familiar group are these two groups isomorphic?
QUESTION: Do the star and the moth have isomorphic symmetry groups?
QUESTION: Do the star and the moth have isomorphic symmetry groups?
ANSWER: Yes! Here are their Cayley tables:
And here is the isomorphism:
star | I | R180 |
I | I | R180 |
R180 | R180 | I |
moth | I | V |
I | I | V |
V | V | I |
I | R180 |
↕ | ↕ |
I | V |
QUESTION: Do the star and the moth have isomorphic symmetry groups?
ANSWER: Yes! Here are their Cayley tables:
star | I | R180 |
I | I | R180 |
R180 | R180 | I |
moth | I | V |
I | I | V |
V | V | I |
And here is the isomorphism:
I | R180 |
↕ | ↕ |
I | V |
Q: Are these two groups isomorphic:
D4 = The symmetry group of a square.
C5 = The symmetry group of an oriented 5 sided polygon (or star).
Q: Are these two groups isomorphic:
D4 = The symmetry group of a square.
C5 = The symmetry group of an oriented 5 sided polygon (or star).
NO! They have different sizes.
Q: Are these two groups isomorphic:
D4 = The symmetry group of a square.
C8 = The symmetry group of an oriented 8-sided polygon (or star).
NO! Because only C8 is commutative.
Q: Are these two groups isomorphic:
D4 = The symmetry group of a square.
C8 = The symmetry group of an oriented 8-sided polygon (or star).
Q: Are these two groups isomorphic:
D2 = The symmetry group of a rectangle.
C4 = The symmetry group of an oriented 4-sided polygon (or star).
Q: Are these two groups isomorphic:
D2 = The symmetry group of a rectangle.
C4 = The symmetry group of an oriented 4-sided polygon (or star).
No. Think about why no matching would work.
PROOF:
PROOF:
PROOF:
PROOF:
You have a large collection of bounded objects with finite symmetry
groups. Should you sort them into piles according to…
(1) rigid equivalence, or
(2) whether their symmetry groups are isomorphic.
You have a large collection of bounded objects with finite symmetry
groups. Should you sort them into piles according to…
(1) rigid equivalence, or
(2) whether their symmetry groups are isomorphic.
The only difference is whether these two piles merge into one pile.
You have a large collection of bounded objects with finite symmetry
groups. Should you sort them into piles according to…
(1) rigid equivalence, or
(2) whether their symmetry groups are isomorphic.
The only difference is whether these two piles merge into one pile.
Sorting is NOT the main purpose for isomorphisms in this book.
Q: Do these two border patterns have isomorphic symmetry groups?
G G G G G G G G G G G G G G G G G G G G G
P P P P P P P P P P P P P P
1 cm between Gs
2 cm between Ps
Q: Do these two border patterns have isomorphic symmetry groups?
G G G G G G G G G G G G G G G G G G G G G
P P P P P P P P P P P P P P
1 cm between Gs
2 cm between Ps
YES! Here is an isomorphism:
… | T–4 | T–3 | T–2 | T–1 | T0 | T1 | T2 | T3 | T4 | … |
| ↕ | ↕ | ↕ | ↕ | ↕ | ↕ | ↕ | ↕ | ↕ | |
… | T–8 | T–6 | T–4 | T–2 | T0 | T2 | T4 | T6 | T8 | … |
Symmetries of G-pattern
Symmetries of P-pattern
“T” means translate the subscripted number of centimeters (right if positive, left if negative).
Q: Do these two border patterns have isomorphic symmetry groups?
G G G G G G G G G G G G G G G G G G G G G
P P P P P P P P P P P P P P
1 cm between Gs
2 cm between Ps
YES! Here is an isomorphism:
Symmetries of G-pattern
Symmetries of P-pattern
T5 * T8 = T13
↓ ↓ ↓
T10 * T16 = T26
Watch this dictionary turn a true green
equation into a true purple equation:
… | T–4 | T–3 | T–2 | T–1 | T0 | T1 | T2 | T3 | T4 | … |
| ↕ | ↕ | ↕ | ↕ | ↕ | ↕ | ↕ | ↕ | ↕ | |
… | T–8 | T–6 | T–4 | T–2 | T0 | T2 | T4 | T6 | T8 | … |
G G G G G G G G G G G G G G G G G G G G G
Q: Are these two groups isomorphic:
G G G G G G G G G G G G G G G G G G G G G
YES! Here is an isomorphism:
… | T–4 | T–3 | T–2 | T–1 | T0 | T1 | T2 | T3 | T4 | … |
| ↕ | ↕ | ↕ | ↕ | ↕ | ↕ | ↕ | ↕ | ↕ | |
… | -4 | -3 | -2 | -1 | 0 | 1 | 2 | 3 | 4 | … |
Symmetries of G-pattern
The integers
Q: Are these two groups isomorphic:
G G G G G G G G G G G G G G G G G G G G G
YES! Here is an isomorphism:
… | T–4 | T–3 | T–2 | T–1 | T0 | T1 | T2 | T3 | T4 | … |
| ↕ | ↕ | ↕ | ↕ | ↕ | ↕ | ↕ | ↕ | ↕ | |
… | -4 | -3 | -2 | -1 | 0 | 1 | 2 | 3 | 4 | … |
Symmetries of G-pattern
The integers
Watch this dictionary turn a true green
equation into a true purple equation:
T5 * T8 = T13
↓ ↓ ↓
5 + 8 = 13
Q: Are these two groups isomorphic:
EXERCISE: Prove that the symmetry group of this border pattern is
isomorphic to Z = {…, -3, -2, -1, 0, 1, 2, 3,…}
“the additive group of all integers”
EXERCISE: Prove that the symmetry group of this border pattern is
isomorphic to Z = {…, -3, -2, -1, 0, 1, 2, 3,…}
“the additive group of all integers”
… | T–4 | H*T–3 | T–2 | H*T–1 | T0 | H*T1 | T2 | H*T3 | T4 | … |
| | | | | | | | | | |
| | | | | | | | | | |
Symmetries of pattern
Here is one system for naming all of the symmetries, including
the translations and the glide-reflections (where H = horizontal reflection).
One letter
EXERCISE: Prove that the symmetry group of this border pattern is
isomorphic to Z = {…, -3, -2, -1, 0, 1, 2, 3,…}
“the additive group of all integers”
… | T–4 | H*T–3 | T–2 | H*T–1 | T0 | H*T1 | T2 | H*T3 | T4 | … |
| | | | | | | | | | |
| | | | | | | | | | |
Symmetries of pattern
Here is one system for naming all of the symmetries, including
the translations and the glide-reflections (where H = horizontal reflection).
Composition examples … why is it just like integer addition?
One letter
EXERCISE: Prove that the symmetry group of this border pattern is
isomorphic to Z = {…, -3, -2, -1, 0, 1, 2, 3,…}
“the additive group of all integers”
… | T–4 | H*T–3 | T–2 | H*T–1 | T0 | H*T1 | T2 | H*T3 | T4 | … |
| | | | | | | | | | |
| | | | | | | | | | |
Symmetries of pattern
Here is one system for naming all of the symmetries, including
the translations and the glide-reflections (where H = horizontal reflection).
Composition examples … why is it just like integer addition?
One letter
EXERCISE: Prove that the symmetry group of this border pattern is
isomorphic to Z = {…, -3, -2, -1, 0, 1, 2, 3,…}
“the additive group of all integers”
… | T–4 | H*T–3 | T–2 | H*T–1 | T0 | H*T1 | T2 | H*T3 | T4 | … |
| ↕ | ↕ | ↕ | ↕ | ↕ | ↕ | ↕ | ↕ | ↕ | |
… | -4 | -3 | -2 | -1 | 0 | 1 | 2 | 3 | 4 | … |
Symmetries of pattern
The integers
Here is an isomorphism.
EXERCISE: Prove that the symmetry group of this border pattern is
isomorphic to Z = {…, -3, -2, -1, 0, 1, 2, 3,…}
“the additive group of all integers”
… | T–4 | H*T–3 | T–2 | H*T–1 | T0 | H*T1 | T2 | H*T3 | T4 | … |
| ↕ | ↕ | ↕ | ↕ | ↕ | ↕ | ↕ | ↕ | ↕ | |
… | -4 | -3 | -2 | -1 | 0 | 1 | 2 | 3 | 4 | … |
Symmetries of pattern
The integers
Here is an isomorphism. But a simpler naming system makes it
easier to verify it’s an isomorphism, since you can distinguish
reflections vs. translations just based on even vs. odd…
EXERCISE: Prove that the symmetry group of this border pattern is
isomorphic to Z = {…, -3, -2, -1, 0, 1, 2, 3,…}
“the additive group of all integers”
… | T–4 | H*T–3 | T–2 | H*T–1 | T0 | H*T1 | T2 | H*T3 | T4 | … |
| ↕ | ↕ | ↕ | ↕ | ↕ | ↕ | ↕ | ↕ | ↕ | |
… | -4 | -3 | -2 | -1 | 0 | 1 | 2 | 3 | 4 | … |
Symmetries of pattern
The integers
… | S–4 | S–3 | S–2 | S–1 | S0 | S1 | S2 | S3 | S4 | … |
Here is an isomorphism. But a simpler naming system makes it
easier to verify it’s an isomorphism, since you can distinguish
reflections vs. translations just based on even vs. odd…
Here Sn means the only symmetry that shifts n letters.
This “slide-and-tilt” is a rigid motion of the plane.
We used it to create our isomorphism between their symmetry groups.
I | R90 | R180 | R270 | H | D’ | V | D |
↕ | ↕ | ↕ | ↕ | ↕ | ↕ | ↕ | ↕ |
I | R90 | R180 | R270 | F1 | F2 | F3 | F4 |
This “slide-and-tilt” is a rigid motion of the plane.
We used it to create our isomorphism between their symmetry groups.
THEOREM: If two objects are rigidly equivalent, then their symmetry groups are isomorphic.
This theorem is the real reason that the red and green
squares have isomorphic symmetry groups.
I | R90 | R180 | R270 | H | D’ | V | D |
↕ | ↕ | ↕ | ↕ | ↕ | ↕ | ↕ | ↕ |
I | R90 | R180 | R270 | F1 | F2 | F3 | F4 |
THEOREM: If two objects are rigidly equivalent, then their symmetry groups are isomorphic.
Q: Are these two stars rigidly
equivalent?
THEOREM: If two objects are rigidly equivalent, then their symmetry groups are isomorphic.
Q: Are these two stars rigidly
equivalent?
YES!
(so their symmetry groups
must be isomorphic)
THEOREM: If two objects are rigidly equivalent, then their symmetry groups are isomorphic.
Q: Are the star and the moth rigidly
equivalent?
THEOREM: If two objects are rigidly equivalent, then their symmetry groups are isomorphic.
Q: Are the star and the moth rigidly
equivalent?
NO!
(but their symmetry groups are isomorphic anyways)
THEOREM: If two objects are rigidly equivalent, then their symmetry groups are isomorphic.
Q: Are these two border patterns rigidly equivalent?
G G G G G G G G G G G G G G G G G G G G G
P P P P P P P P P P P P P P
THEOREM: If two objects are rigidly equivalent, then their symmetry groups are isomorphic.
Q: Are these two border patterns rigidly equivalent?
G G G G G G G G G G G G G G G G G G G G G
P P P P P P P P P P P P P P
NO!
But their symmetry groups are isomorphic anyways.
(notice that they have the same symmetry type.)
Two notation systems for
C5 = this star’s five rotation symmetries
1
2
C5 = {I, R72, R144, R216, R288}
C5 = {0, 1, 2, 3, 4}
How many “turns”
How many degrees
Two notation systems for
C5 = this star’s five rotation symmetries
1
2
C5 = {I, R72, R144, R216, R288}
C5 = {0, 1, 2, 3, 4}
How many degrees
How many “turns”
Which system do you prefer?
Two notation systems for
C5 = this star’s five rotation symmetries
1
2
C5 = {I, R72, R144, R216, R288}
C5 = {0, 1, 2, 3, 4}
How many degrees
How many “turns”
R216* R288 = R144
3 + 4 = 2 (in C5)
Two notation systems for
C5 = this star’s five rotation symmetries
1
2
C5 = {I, R72, R144, R216, R288}
C5 = {0, 1, 2, 3, 4}
How many degrees
How many “turns”
R216* R288 = R144
3 + 4 = 2 (in C5)
Convention: We’ll use this simpler notation system from now on.
The members of Cn will be denoted:
Cn = {0, 1, 2, 3, …, n-1}.
We’ll write “+” for the algebraic operation in Cn.
We’ll think of this as “addition with wrap-around”.
* | R0 | R1(360/7) | R2(360/7) | R3(360/7) | R4(360/7) | R5(360/7) | R6(360/7) |
R0 | R0 | R1(360/7) | R2(360/7) | R3(360/7) | R4(360/7) | R5(360/7) | R6(360/7) |
R1(360/7) | R1(360/7) | R2(360/7) | R3(360/7) | R4(360/7) | R5(360/7) | R6(360/7) | R0 |
R2(360/7) | R2(360/7) | R3(360/7) | R4(360/7) | R5(360/7) | R6(360/7) | R0 | R1(360/7) |
R3(360/7) | R3(360/7) | R4(360/7) | R5(360/7) | R6(360/7) | R0 | R1(360/7) | R2(360/7) |
R4(360/7) | R4(360/7) | R5(360/7) | R6(360/7) | R0 | R1(360/7) | R2(360/7) | R3(360/7) |
R5(360/7) | R5(360/7) | R6(360/7) | R0 | R1(360/7) | R2(360/7) | R3(360/7) | R4(360/7) |
R6(360/7) | R6(360/7) | R0 | R1(360/7) | R2(360/7) | R3(360/7) | R4(360/7) | R5(360/7) |
This new system is much better for
C7 = the symmetry group of an oriented
seven-pointed star.
* | 0 | 1 | 2 | 3 | 4 | 5 | 6 |
0 | 0 | 1 | 2 | 3 | 4 | 5 | 6 |
1 | 1 | 2 | 3 | 4 | 5 | 6 | 0 |
2 | 2 | 3 | 4 | 5 | 6 | 0 | 1 |
3 | 3 | 4 | 5 | 6 | 0 | 1 | 2 |
4 | 4 | 5 | 6 | 0 | 1 | 2 | 3 |
5 | 5 | 6 | 0 | 1 | 2 | 3 | 4 |
6 | 6 | 0 | 1 | 2 | 3 | 4 | 5 |
R2(360/7) * R3(360/7) = R5(360/7)
2 + 3 = 5 (in C7)
OLD
NEW
* | R0 | R1(360/7) | R2(360/7) | R3(360/7) | R4(360/7) | R5(360/7) | R6(360/7) |
R0 | R0 | R1(360/7) | R2(360/7) | R3(360/7) | R4(360/7) | R5(360/7) | R6(360/7) |
R1(360/7) | R1(360/7) | R2(360/7) | R3(360/7) | R4(360/7) | R5(360/7) | R6(360/7) | R0 |
R2(360/7) | R2(360/7) | R3(360/7) | R4(360/7) | R5(360/7) | R6(360/7) | R0 | R1(360/7) |
R3(360/7) | R3(360/7) | R4(360/7) | R5(360/7) | R6(360/7) | R0 | R1(360/7) | R2(360/7) |
R4(360/7) | R4(360/7) | R5(360/7) | R6(360/7) | R0 | R1(360/7) | R2(360/7) | R3(360/7) |
R5(360/7) | R5(360/7) | R6(360/7) | R0 | R1(360/7) | R2(360/7) | R3(360/7) | R4(360/7) |
R6(360/7) | R6(360/7) | R0 | R1(360/7) | R2(360/7) | R3(360/7) | R4(360/7) | R5(360/7) |
This new system is much better for
C7 = the symmetry group of an oriented
seven-pointed star.
* | 0 | 1 | 2 | 3 | 4 | 5 | 6 |
0 | 0 | 1 | 2 | 3 | 4 | 5 | 6 |
1 | 1 | 2 | 3 | 4 | 5 | 6 | 0 |
2 | 2 | 3 | 4 | 5 | 6 | 0 | 1 |
3 | 3 | 4 | 5 | 6 | 0 | 1 | 2 |
4 | 4 | 5 | 6 | 0 | 1 | 2 | 3 |
5 | 5 | 6 | 0 | 1 | 2 | 3 | 4 |
6 | 6 | 0 | 1 | 2 | 3 | 4 | 5 |
R2(360/7) * R3(360/7) = R5(360/7)
2 + 3 = 5 (in C7)
OLD
NEW
When a pair of groups is isomorphic, it is often best to think of them as a single group
described in two different notation systems.
The Converse
STATEMENT 1: If two objects are rigidly equivalent, then their symmetry groups are isomorphic.
STATEMENT 2: If two objects have isomorphic symmetry groups, then they are rigidly equivalent.
For each statement, decide whether it’s true or false.
The Converse
STATEMENT 1: If two objects are rigidly equivalent, then their symmetry groups are isomorphic.
STATEMENT 2: If two objects have isomorphic symmetry groups, then they are rigidly equivalent.
For each statement, decide whether it’s true or false.
TRUE
FALSE
The Converse
STATEMENT 1: If two objects are rigidly equivalent, then their symmetry groups are isomorphic.
STATEMENT 2: If two objects have isomorphic symmetry groups, then they are rigidly equivalent.
For each statement, decide whether it’s true or false.
Each statement is called the converse of the other.
TRUE
FALSE
The Converse
STATEMENT 1: If two objects are rigidly equivalent, then their symmetry groups are isomorphic.
STATEMENT 2: If two objects have isomorphic symmetry groups, then they are rigidly equivalent.
For each statement, decide whether it’s true or false.
Each statement is called the converse of the other.
TRUE
FALSE
These statements about an arbitrary member of a set
are called converses:
STATEMENT 1: If it has property A, then it has property B.
STATEMENT 2: If it has property B, then it has property A.
The Converse
STATEMENT 1: If two objects are rigidly equivalent, then their symmetry groups are isomorphic.
STATEMENT 2: If two objects have isomorphic symmetry groups, then they are rigidly equivalent.
TRUE
FALSE
These statements about an arbitrary member of a set
are called converses:
STATEMENT 1: If it has property A, then it has property B.
STATEMENT 2: If it has property B, then it has property A.
SET = the set of all pairs of objects
A = being rigidly equivalent
B = having isomorphic symmetry groups.
The Converse
STATEMENT: If you’re a Jesuit priest, then you’re a man.
CONVERSE If you’re a man, then you’re a Jesuit.
These statements about an arbitrary member of a set
are called converses:
STATEMENT 1: If it has property A, then it has property B.
STATEMENT 2: If it has property B, then it has property A.
The Converse
STATEMENT: If you’re a Jesuit priest, then you’re a man.
CONVERSE: If you’re a man, then you’re a Jesuit priest.
These statements about an arbitrary member of a set
are called converses:
STATEMENT 1: If it has property A, then it has property B.
STATEMENT 2: If it has property B, then it has property A.
The Converse
STATEMENT: If you’re a Jesuit priest, then you’re a man.
CONVERSE: If you’re a man, then you’re a Jesuit priest.
These statements about an arbitrary member of a set
are called converses:
STATEMENT 1: If it has property A, then it has property B.
STATEMENT 2: If it has property B, then it has property A.
TRUE
FALSE
The Converse
STATEMENT: If an integer is a multiple of 4, then it is a multiple of 2.
CONVERSE: If an integer is a multiple of 2, then it is a multiple of 4.
These statements about an arbitrary member of a set
are called converses:
STATEMENT 1: If it has property A, then it has property B.
STATEMENT 2: If it has property B, then it has property A.
Find the converse.
The Converse
STATEMENT: If an integer is a multiple of 4, then it is a multiple of 2.
CONVERSE: If an integer is a multiple of 2, then it is a multiple of 4.
These statements about an arbitrary member of a set
are called converses:
STATEMENT 1: If it has property A, then it has property B.
STATEMENT 2: If it has property B, then it has property A.
Find the converse. Is it true or false?
The Converse
STATEMENT: If an integer is a multiple of 4, then it is a multiple of 2.
CONVERSE: If an integer is a multiple of 2, then it is a multiple of 4.
These statements about an arbitrary member of a set
are called converses:
STATEMENT 1: If it has property A, then it has property B.
STATEMENT 2: If it has property B, then it has property A.
Find the converse. Is it true or false?
TRUE
FALSE
The Converse
You and I both have a favorite planet of the solar system.
STATEMENT: If our favorite planets are the same, then they start with the same letter.
CONVERSE: If they start with the same letter, then our favorite planets are the same.
Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, Neptune
The Converse
You and I both have a favorite planet of the solar system.
STATEMENT: If our favorite planets are the same, then they start with the same letter.
CONVERSE: If they start with the same letter, then our favorite planets are the same.
Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, Neptune
TRUE
FALSE
The Converse
You and I both have a favorite planet of the solar system.
STATEMENT: If our favorite planets are the same, then they start with the same letter and end with the same letter.
CONVERSE: If they start with the same letter and end with the same letter, then our favorite planets are the same.
Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, Neptune
The Converse
You and I both have a favorite planet of the solar system.
STATEMENT: If our favorite planets are the same, then they start with the same letter and end with the same letter.
CONVERSE: If they start with the same letter and end with the same letter, then our favorite planets are the same.
Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, Neptune
The Converse
You and I both have a favorite planet of the solar system.
STATEMENT: If our favorite planets are the same, then they start with the same letter and end with the same letter.
CONVERSE: If they start with the same letter and end with the same letter, then our favorite planets are the same.
Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, Neptune
TRUE
TRUE
The expression “if and only if” means that a statement and its
converse are true.
“Property A is true if and only if property B is true.”
The Converse
You and I both have a favorite planet of the solar system.
STATEMENT: If our favorite planets are the same, then they start with the same letter and end with the same letter.
CONVERSE: If they start with the same letter and end with the same letter, then our favorite planets are the same.
Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, Neptune
TRUE
TRUE
The expression “if and only if” means that a statement and its
converse are true.
“Property A is true if and only if property B is true.”
The Converse
The expression “if and only if” means that a statement and its
converse are true.
TRUE or FALSE: A pair of 2-letter words are the same if and only if they have the
same first letter and the same second letter.
TRUE or FALSE: A real number is greater than or equal to zero if and only if
it equals its absolute value.
The Converse
The expression “if and only if” means that a statement and its
converse are true.
TRUE or FALSE: A pair of 2-letter words are the same if and only if they have the
same first letter and the same second letter.
TRUE or FALSE: A real number is greater than or equal to zero if and only if
it equals its absolute value.
TRUE
The Converse
The expression “if and only if” means that a statement and its
converse are true.
TRUE or FALSE: A pair of 2-letter words are the same if and only if they have the
same first letter and the same second letter.
TRUE or FALSE: You are a Jesuit priest if and only if you are a man.
TRUE
The Converse
The expression “if and only if” means that a statement and its
converse are true.
TRUE or FALSE: A pair of 2-letter words are the same if and only if they have the
same first letter and the same second letter.
TRUE or FALSE: You are a Jesuit priest if and only if you are a man.
TRUE
FALSE