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Math Tutorial Series

Arithmetic Progression

Higher Order (Part 5)

Sn : Pascal Triangle

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English Subtitle

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Arithmetic Progression

Higher Order

Sn : Pascal Triangle

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Leonardo Sembiring

leonardo.sembiring@gmail.com

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2

arithmetic progression

a0

a1

a2

33

22

13

11

9

7

2

2

6

5

1

subtract

put

=

arithmetic progression order 2

=

Arithmetic Progression Order 2

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a0

a1

a1 + a0

a0

a1 + 2a0

a1 + 3a0

a0

......

a1 + 2a0

a0

1

Pascal Triangle

6

15

10

1

5

1

arithmetic progression order 2

a1 + a0

a0

a1 + 3a0

a0

a2 + 4a1+ 6a0

Arithmetic Progression Order 2

......

1

1

1

1

1

1

1

1

3

2

4

3

1

4

6

1

5

10

1

1

6

15

21

21

35

35

7

7

20

a2

a1

a0

S1

S2

S3

S4

S5

1

2

5

10

10

4

4

6

3

1

3

1

a0

a1

a2

a1

a0

U1

U2

U3

U4

U5

1

6

4

3

3

2

1

1

1

1

1

1

add

put

add

put

a2

a2 + a1

a2 + 2a1+ a0

a2 + 3a1+ 3a0

1

1

1

1

1

2

1

3

3

1

4

6

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1

1

1

1

2

1

1

3

3

1

1

4

6

4

1

...

...

...

...

...

...

n-1C0

n-1C1

n-1C2

...

n-1Cn-3

n-1Cn-2

n-1Cn-1

nC0

nC1

nC2

...

...

nCn-2

nCn-1

nCn

Pascal Triangle

can also be written as follows...

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Sn

.a2

=

.a1

+

.a0

+

nC2

nC1

nC3

1

1

1

1

2

1

1

3

3

1

1

4

6

4

1

...

...

...

...

...

...

n-1C0

n-1C1

n-1C2

...

n-1Cn-3

n-1Cn-2

n-1Cn-1

nC0

nC1

nC2

nC3

...

nCn-2

nCn-1

nCn

a2

a1

a0

a2

2a2 + a1

3a2 + 3a1+ a0

1.

S1

=

=

a2

a2

2.

S2

=

=

a1

+

1.

a2

3.

S3

=

a1

+

3.

a0

+

1.

=

Sn formula

and so on..

Arithmetic Progression Order 2

S1

S2

S3

S4

S5

Sn

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(n-1)!

n!

=

nC1

(n-1)!

n(n-1)!

=

1!

n

=

(n-2)!

n!

=

nC2

2!

(n-2)!

n(n-1)(n-2)!

=

2!

n(n-1)

=

2

(n-3)!

n!

=

nC3

3!

n(n-1)(n-2)

=

(n-3)!

n(n-1)(n-2)(n-3)!

=

3!

6

1!

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Sn

.a2

=

.a1

+

.a0

+

nC2

nC1

nC3

nC1

a2

a1

a0

nC2

nC3

n

1/2 n(n - 1)

1/6 n(n - 1)(n - 2)

Sn

.a2

=

.a1

+

.a0

+

n(n-1)

n

n(n - 1)(n - 2)

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Sn formula for the example...

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2

a0

a1

a2

33

22

13

11

9

7

2

2

6

5

1

Sn

n.1

=

.5

+

.2

+

n(n-1)

n(n - 1)(n - 2)

n

=

+

+

15n - 15

2.(n2 - 3n + 2)

=

(2n2 + 9n - 5)

Sn

Sn

.a2

=

.a1

+

.a0

+

n(n-1)

n

n(n - 1)(n - 2)

6

n

×3

×3

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Sn formula in general...

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a0

a3

a2

a1

S1

S2

S3

S4

S5

Sn

1

1

1

1

2

1

1

3

3

1

1

4

6

4

1

...

...

...

...

...

...

n-1C0

n-1C1

n-1C2

...

n-1Cn-3

n-1Cn-2

n-1Cn-1

nC0

nC1

nC2

nC3

...

nCn-2

nCn-1

nCn

arithmetic progression order 1

arithmetic progression order 2

arithmetic progression order 3

Sn formula

and so on..

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maximum index 3+1

maximum index 1+1

maximum index 2+1

maximum index 4+1

nC1

nC2

nC3

Arithmetic Progression Order

×

×

×

nC4

nC5

×

×

and so on...

1

2

3

4

+

+

+

+

Sn

=

a1

a0

a2

a1

a0

a3

a2

a1

a0

a4

a3

a2

a1

a0

fixed index n

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SMART IDEAS FOR MATHEMATICS

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