DYNAMICS - Lecture Notes / Mehmet Zor
1
23 Agust, 2024
1.2.5 Curvilinear Motion in Polar Coordinates :
we will determine the position, velocity and acceleration of an object moving curvilinearly on a plane according to the polar coordinates r - θ, at a time t
At the examined time t, (at point P):
1.2.5 Kinematics of Particle / Curvilinear Motion / Polar Components
Figure 1.2.23
Figure 1.2.22
DYNAMICS - Lecture Notes / Mehmet Zor
2
23 Agust, 2024
1.2.5 Kinematics of Particle / Curvilinear Motion / Polar Components
dθ
θ
First, we will derive the relationships between the unit vectors on the r and θ axes:
dθ
When we move from position P by the angle dq, we come to position P’. Unit vectors at position P’:
magnitudes of unit vectors are 1:
Magnitude of diff. unit vectors:
(We liken it to the equation radius x central angle = arc length.)
//
//
Position at time t :
instantaneous velocity vector :
Since
instantaneous acceleration vector :
instantaneous
acceleration components:
instantaneous velocity components :
(1.27)
(1.28)
(1.29)
(1.30)
Figure 1.2.24
Figure 1.2.25
DYNAMICS - Lecture Notes / Mehmet Zor
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23 Agust, 2024
Example 1.2.6
On a sufficiently long arm AC, the ring B slides freely. The position of the ring B at time t is described by the equations
r = 2t2 -2t +20, θ = 0.2t2
Accordingly, calculate the velocity and acceleration of the ring when θ = 120o
Solution:
r = 2t2 -2t +20
θ = 0.2t2
1.2.5 Kinematics of Particle / Curvilinear Motion / Polar Components
(from equations 1.27-1.30)
r
Figure 1.2.26
Figure 1.2.27
DYNAMICS - Lecture Notes / Mehmet Zor
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23 Agust, 2024
Question 1.2.3 (*)
1.2.5 Kinematics of Particle / Curvilinear Motion / Polar Components
Figure 1.2.28
DYNAMICS - Lecture Notes / Mehmet Zor
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23 Agust, 2024
Example 1.2.7
x
y
8.66km
θ
r
r
Valid for rectilinear motion with constant acceleration.
Timeless Velocity Equation (1.9):
Solution:
1.2.5 Kinematics of Particle / Curvilinear Motion / Polar Components
8.66km
Figure 1.2.29
Figure 1.2.30
angular accelaration
DYNAMICS - Lecture Notes / Mehmet Zor
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23 Agust, 2024
Example 1.2.8
1.2.5 Kinematics of Particle / Curvilinear Motion / Polar Components
Remzi
Solution:…>>>
Figure 1.2.31
DYNAMICS - Lecture Notes / Mehmet Zor
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23 Agust, 2024
x
t=0
t=5s
:constant
y
Velocity components of the bullet at time t= 0 (oblique shot)
The bullet starts moving with the speed of the car + its own speed:
the bullet is in the rise zone.
Figure 1.2.32
1.2.5 Kinematics of Particle / Curvilinear Motion / Polar Components
DYNAMICS - Lecture Notes / Mehmet Zor
8
23 Agust, 2024
Question 1.2.4 (*)
1.2.5 Kinematics of Particle / Curvilinear Motion / Polar Components
a-)
Answers:
b-) 6369.8m
Figure 1.2.33
DYNAMICS - Lecture Notes / Mehmet Zor
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23 Agust, 2024
Question1.2.5 (*)
A
1.2.5 Kinematics of Particle / Curvilinear Motion / Polar Components
Hasan
Figure 1.2.34