AP Chemistry
Unit 9.2
ABSOLUTE ENTROPY AND ENTROPY CHANGE
Unit 9.2
Enduring Understanding:
Learning Objective:
Calculating Entropy
Calculating Entropy
Entropy of the System
ΔS°rxn = ΣΔS°products - ΣΔS°reactants
Entropy of the System
ΔS°rxn = ΣΔS°products - ΣΔS°reactants
aA + bB → cC + dD
Entropy of the System
ΔS°rxn = ΣΔS°products - ΣΔS°reactants
aA + bB → cC + dD
ΔS°rxn = [(cΔS°C)+(dΔS°D)] - [(aΔS°A)+(bΔS°B)]
Entropy of the System
ΔS°rxn = ΣΔS°products - ΣΔS°reactants
aA + bB → cC + dD
ΔS°rxn = [(cΔS°C)+(dΔS°D)] - [(aΔS°A)+(bΔS°B)]
Entropy of the System
ΔS°rxn = ΣΔS°products - ΣΔS°reactants
aA + bB → cC + dD
ΔS°rxn = [(cΔS°C)+(dΔS°D)] - [(aΔS°A)+(bΔS°B)]
Practice: I Do
4NH3 (g) + 7O2 (g) → 4NO2 (g) + 6H2O (g)
Practice: I Do
4NH3 (g) + 7O2 (g) → 4NO2 (g) + 6H2O (g)
ΔS°rxn = ΣΔS°products - ΔS°reactants
NO2 : 4 moles x (240.1 J / mol・K) = 960.4 J/K
H2O: 6 moles x (188.8 J / mol・K) = 1132.8 J/K
NH3 : 4 moles x (192.8 J / mol・K) = 771.2 J/K
O2: 7 moles x (205.3 J / mol・K) = 1437.1 J/K
Practice: I Do
4NH3 (g) + 7O2 (g) → 4NO2 (g) + 6H2O (g)
ΔS°rxn = ΣΔS°products - ΔS°reactants
NO2 : 960.4 J/K NH3: 771.2 J/K
H2O: 1132.8 J/K O2: 1437.1 J/K
ΔS°rxn = [(960.4 + 1132.8) - (771.2 + 1437.1)] = -115.1 J/K