Measures of Dispersion
Dr Anshul Singh Thapa
INTRODUCTION
Sr. No | Family I | Family II | Family III |
1 | 12,000 | 7,000 | 0 |
2 | 14,000 | 10,000 | 7,000 |
3 | 16,000 | 14,000 | 8,000 |
4 | 18,000 | 17,000 | 10,000 |
5 | ------------- | 20,000 | 50,000 |
6 | -------------- | 22,000 | -------------- |
Total income | 60,000 | 90,000 | 75,000 |
Average income | 15,000 | 15,000 | 15,000 |
It is quite obvious that averages try to tell only one aspect of a distribution i.e. a representative size of the values. To understand it better, you need to know the spread of values also.
MEASURES BASED UPON SPREAD OF�VALUES
Range
Quartiles
Quartile Deviation
2
Calculation of Range and Q.D. for ungrouped data
2
4
4
2 2
Example
4 4
= 2.75th item
= 2nd item + ¾ (3rd item – 2nd item)
= 150 + ¾ (170 - 150)
Q1 = 165
4 4
= 8.25th item
= 8th item + ¼ (9th item – 8th item)
= 192 + ¼ (200 - 192)
Q3 = 194
2 2 2
Calculation of Range for a frequency distribution
Discrete Series
Size: | 10 | 11 | 12 | 13 | 14 | 15 | 16 | 18 |
Frequency | 1 | 13 | 24 | 14 | 15 | 13 | 16 | 20 |
Range (R) = H – L = 18 – 10 = 8 (Ans)
Calculation of Range for a frequency distribution
Continuous Series:
Find out Range of the following Series:
Size: | 5 – 10 | 10 – 15 | 15 – 20 | 20 – 25 | 25 – 30 |
Frequencies: | 4 | 9 | 15 | 30 | 40 |
Size | Mid- value | Frequency |
5 – 10 | 7.5 | 4 |
10 – 15 | 12.5 | 9 |
15 – 20 | 17.5 | 15 |
20 – 25 | 22.5 | 30 |
25 – 30 | 27.5 | 40 |
Range = H – L = 27.5 – 7.5 = 20 (Ans)
Calculation of Q.D. for grouped data
Wages | 10 | 20 | 30 | 40 | 50 | 60 | 70 | 80 | 90 | 100 |
No. of Workers | 2 | 8 | 20 | 35 | 42 | 20 | 28 | 26 | 16 | 2 |
4 4 4
4 4 4
QD = Q3 – Q1 = 70 – 40 = 30 = 15
2 2 2
Wages | Frequency | Cumulative Frequency |
10 | 2 | 2 |
20 | 8 | 10 |
30 | 20 | 30 |
40 | 35 | 65 |
50 | 42 | 107 |
60 | 20 | 127 |
70 | 28 | 155 |
80 | 26 | 181 |
90 | 16 | 197 |
100 | 2 | 199 |
| N = 199 | |
Calculation of Q.D. for a frequency distribution
Continuous Series:
Find out Quartile Deviation of the following Series
Age (Yrs.) | 0 – 20 | 20 – 40 | 40 – 60 | 60 – 80 | 80 - 100 |
Person | 4 | 10 | 15 | 20 | 11 |
Age (Years) | No. of Person | Cumulative Frequency |
0 – 20 | 4 | 4 |
20 – 40 | 10 | 14 |
40 – 60 | 15 | 29 |
60 – 80 | 20 | 49 |
80 – 100 | 11 | 60 |
Q1 = Size of N/4 th item = 60/4 = 15th item
15th item lies in group 40 – 60 and falls within 29th cumulative frequency of the series.
Q1 = l1 + N/4 – c.f. x i
f
(l1 = lower limit of the class interval, N = sum total of the frequencies, c.f. = cumulative frequency of the class preceding the first quartile class, f = frequency of the quartile class, i = class interval)
Thus, Q1 = 40 + 15 – 14 x 20 = 41.33
15
Age (Years) | No. of Person | Cumulative Frequency |
33 – 35 | 14 | |
35 – 37 | 62 | |
38 – 40 | 99 | |
41 – 43 | 18 | |
43 – 45 | 7 | |
Q3 = Size of 3(N/4)th item = 3(60/4) = 45th item
45th item lies in group 60 – 80 and falls within 49th cumulative frequency of the series.
Q3 = l1 + 3(N/4) – c.f. x i
f
(l1 = lower limit of the class interval, N = sum total of the frequencies, c.f. = cumulative frequency of the class preceding the third quartile class, f = frequency of the quartile class, i = class interval)
Thus, Q3 = 60 + 45 – 29 x 20 = 76
15
Having known the values of Q1 and Q3, Quartile Deviation QD is found as;
QD = Q3 – Q1 = 76 – 41.33 = 17.34
2 2