Strength of Materials - Lecture Notes / Mehmet Zor
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Separation Principle
and the Concept of Stress
1.2
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1.2.1 Stress in humans - Stress in objects
1.2 Separation Principle and Concept of Stress
Figure 1.2.1
Figure 1.2.2
Strength of Materials - Lecture Notes / Mehmet Zor
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« If a system subject to the influence of external forces is in equilubrium, each of its parts, which we have separated on an imaginary basis, is also in eqilibrium separately. » This is called the separation principle.
In the free body diagram of each part that we have imaginarily separated, in addition to external forces, internal forces and internal moments are also affected by the separation surface. Each part is in static eqilibrium under the influence of internal and external forces.
stresses
1.2.2 Separation Principle:
Left piece in eqilibrium:
The Whole System is in eqilibrium:
stresses
1.2 Separation Principle and Concept of Stress
The right piece is in eqilibrium:
Figure 1.2.3.a
Figure 1.2.3.b
Figure 1.2.3.c
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1.2.3. Concept of Stress:
I
F int.
I
Mint.
Sa
σ a
τ a
a
b
S b
S
Resultant stress
normal stress
n
Shear stress
//n
Plane Normal
n
S: f ( F int. , M int. , geometry)
II section lower part
1.2 Separation Principle and Concept of Stress
Figure 1.2.4.a
Figure 1.2.4.b
Figure 1.2.4.c
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Let's keep in mind : Stress calculation formulas always include internal force or internal moment and values depending on the section geometry. Material properties are (usually) not included in stress formulas. This means that stresses do not depend on the type of material. This is actually an important tip of STRENGTH OF MATERIALS.
Imaginary
Separation Surface
1.2 Separation Principle and Concept of Stress
Normal Stresses
We think that in the body below, no internal moment occurs on the separation surface (Mint. = 0) and only the internal force (Fint.) occurs and is distributed homogeneously. In this case, we can define stress as internal force per unit.
Fint.
Fint.
Figure 1.2.5.a
Figure 1.2.5.b
Figure 1.2.5.c
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W all
W head
F int.-1
A neck
1.2.4. Separation Principle - Example
I
I
I
I
Examine the stresses occurring in different parts of a standing person due to his body weight. Please note that imaginary cuts are made for the regions, and only internal force occurs in each cut.
II
II
W body+head
II
II
1.2 Separation Principle and Concept of Stress
A body
Figure 1.2.6.a
Figure 1.2.6.b
Figure 1.2.6.c
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W head
F int-1
I
I
I
I
II section Upper part
II section Lower part
1.2 Separation Principle and Concept of Stress
A neck
W all / 2
W all / 2
Figure 1.2.6.d
Figure 1.2.6.e
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1.2.5 Stress Types
1.2.5.1 Normal Stress: The stress parallel to the plane normal, in other words, perpendicular to the plane, is called normal stress; It is denoted by σ .
Imaginary
separation surface
Upside
Under Part
(1.1)
1.2 Separation Principle and Concept of Stress
Fint.=F
Fint.=F
Fint.
(a)
Figure 1.2.7
(b)
(c)
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1.2.5.2 Shear Stress : The stress that is perpendicular to the plane normal, in other words parallel to the plane, is called normal stress; It is denoted by τ .
right part
In this example, since we neglect the difference in perpendicular distance between Fint. and F the internal moment is zero.
(1.2)
1.2 Separation Principle and Concept of Stress
Imaginary
separation surface
Fint.=F
Fint. / A
Figure 1.2.8
(a)
(b)
(c)
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1.2.5.3 Stress indices
σ or τ We define the stresses in more detail and accurately by adding 2 indices:
x
z
y
1st subscript : i : It shows the normal of the plane where the stress is located.
2nd subscript : j :Indicates the axis of stress.
plane normal
Stress
axis
?
1.2 Separation Principle and Concept of Stress
Figure 1.2.9
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Let's show the shear stresses on each surface of a cubic differential element, having a.b.t dimensions, at a point O in the xy plane.( t: thickness ) :…>>>
Similarly, the same results are found for other planes:
This element must be in static eqilibrium. Equilibrium equations should be written for forces.
1.2.5.4 Specific information on shear stresses
This can be proven as follows:
a
b
O.
x
y
a-) Shear stresses with the same indices but different subscript orders have equal intensity.
Force = stress x area
1.2 Separation Principle and Concept of Stress
From these 3 equations
a
b
O.
x
y
is available.
If we express the stresses with their indices :
plane normal
stress direction
τ i j = τ j i
Figure 1.2.11
Figure 1.2.10
Strength of Materials - Lecture Notes / Mehmet Zor
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A ( mm2 ) | (Rope Material - 1, brittle material) F break (N) | (Rope Material - 2, brittle material) F break (N) |
10 | 100 | 50 |
20 | 200 | 100 |
30 | 300 | 150 |
40 | 400 | 200 |
| | |
It should not be forgotten that if the material of the rope changes, the load W that can be carried will also change.
1.2.6 Damage Stress
Let's consider the load W hanging on the rope in the figure. At any time the force in the rope is Fint. = W from static equilibrium .
In the table below, the force (Fbreak) values in the rope that occur at the instant of breaking are shown according to the cross-sectional area of the rope.We know that as the cross-section grows, that is, the thicker the rope, it will carry more W load.
Question: Is there a value that remains constant according to this table?
(1.3)
1.2 Separation Principle and Concept of Stress
Figure 1.2.12
Tablo 1.2.1
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Tensile Testing Machine
Ductile (formable) materials, the time when permanent deformation (plastic zone) begins should be considered as the instant of damage. Because an element exposed to permanent deformation will lose its functionality. Therefore, the damage stress is:
Note: The yield strengths (yield stresses) of ductile materials in tension and compression are the same. In brittle materials, the compressive strength is greater than the tensile strength (may be 3-4 times).
1.2.7 Damage Stress detection
(1.4)
(1.5)
1.2 Separation Principle and Concept of Stress
Figure 1.2.14
Figure 1.2.13
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1.2.8. Damage Condition for Tension-Compression Situations
Damage condition for ductile materials:
Damage requirement for brittle materials:
(The reason why we included it in absolute value is to cover the damage condition in case of compression. There is no need to take it in absolute value in case of tension.)
It hasn't broken yet.
instant of rupture
Pull !
a little more
Okey brother
I’m pulling
Finally! We broke it off
Why did we break this now???
P=270N
P=270N
P=350N
P=350N
Cross-sectional area: A=10mm 2
for rope
Try to understand the concepts thoroughly by carefully examining the rope breaking example below.
LATER
I
I
P.
Cut I-I
I
I
Normal stress occurs in a material subjected to tensile loading. As the force increases, the tension also increases. If the force is increased significantly, the stress reaches the damage stress and damage occurs in the material. Then, in general terms, the damage condition is that the current stress is equal to or greater than the damage stress.
(Damage condition).
1.2 Separation Principle and Concept of Stress
Figure 1.2.15.a
Figure 1.2.15.b
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1.2.9 Let's explain the damage conditions with some different symbols.
For ductile materials , the yield stress in tension is
Tensile breaking stress for brittle materials
For ductile materials , the yield stress in compression is
Breaking stress in compression for brittle materials
In other words, if at least one of the two inequalities above is met, at that point, yielding occurs in ductile materials and breaking occurs in brittle materials.
or
whereas,
The breaking stresses of brittle materials in compression are significantly greater than those in tension.
Tensile and compressive yield stresses of ductile materials are equal in intensity.
This is because the internal structure of brittle materials is porous. The pores in the material close in case of compression, the surface area expands and the material can withstand more compressive load.
Attention: Since these symbols are used in some sources, it is useful to learn them.
At this point;
1.2 Separation Principle and Concept of Stress
Figure 1.2.16
Figure 1.2.17
Strength of Materials - Lecture Notes / Mehmet Zor
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A.
P.
1.2.10 We can now explain some of the things we know from experience in a more technical way:
Stress occurring in case of compression or tension:
We learned that it was.
Because the contact area of the sharp corners of a table or object is very small, like the tip of a needle, even the slightest blow to the sharp corners instantly causes exceeding the damage stress in that part of our body and serious injuries occur.
If the tips of our fingers were not rounded, we would probably feel great pain when touching something and we would not be able to use our hands fully. Similarly, see the other roundings on your body, realize that you are a perfect design even from this aspect alone .
For this reason, when designing a product, we increase the contact area by giving fillet (rounding) to sharp corners and reduce the instantaneous stress.
Protective apparatus for babies..
1.2 Separation Principle and Concept of Stress
Figure 1.2.18
(a)
(b)
Figure 1.2.19
Figure 1.2.20
(c)
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Fint. / A
1.2.11 Damage Condition in Case of Shearing
For ductile materials:
For brittle materilas:
(Whether the sign of the shear stress is + or – is not important in terms of strength. It is considered as + here.)
(The reason for this equality will be better understood from the Mohr circle topic, which will be seen.later.)
Damage condition:
upper part of cut E-E
We think that there is a tensile load on the plates.
Forces acting on the bolt
Internal force(Fint.) in cross-section of the bolt
Stress occurring in cross-section of the bolt
(1.6)
(1.7)
1.2 Separation Principle and Concept of Stress
An example : We check the damage of the steel bolt connecting two plates with the following steps.
Fint.=P
Figure 1.2.21
(a)
(b)
(c)
(d)
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1.2.12 Factor of safety and allowable stress
Safety condition:
or
Reasons for Using the Safety Coefficient:
(1.8)
(1.9a,b)
1.2 Separation Principle and Concept of Stress
Figure 1.2.22
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one
2
4
3
1-) In an object or system in equilibrium, unknown forces are first found through static calculations.
2-) The maximum stress on the object is calculated.
(Calculation method and formulas vary depending on the loading method and sometimes geometry.)
1.2.13 General Road Map in Strength Calculations
3-) The maximum stress is equal to the yield stress in ductile materials and the breaking stress in brittle materials. From this equality,
a-) minimum size calculation (if force + material is certain) or
b-) material selection (if force + dimensions are certain) or
c-) Strength (strength) control is performed (if force + dimensions + material type is known).
1.2 Separation Principle and Concept of Stress
Figure 1.2.23