1 of 8

Quadrilateral Speed - time Curve

1

2 of 8

Quadrilateral speed time curve

Let

α = Acceleration in km per hour per second

βC = Coasting retardation in km per hour per second

β = Braking retardation in km per hour per second

V1 = Maximum speed at the end of acceleration ( km per hour )

2

3 of 8

3

4 of 8

V2 = Speed at the end of coasting period ( km per hour )

T = Total time of run ( second )

Acceleration time in second t1 = V1 / α …. ( 1 )

Coasting time in second t2 = V1 – V2 / βC ….. ( 2 )

Braking time in second t3 = V2 / β …… ( 3 )

Total distance travelled in ( km )( S ) = Distance travelled during acceleration ( Area ABC ) + Distance travelled during coasting ( Area BDEF ) + Distance travelled during retardation ( DEF )

4

5 of 8

S = ( ½ V1t1 / 3600 ) + { ( V1 + V2 ) / 2 × ( t2 / 3600 ) } + ( ½ V2t3 / 3600 )

S = ( V1t1 / 7200 ) + { ( V1t2 / 7200 ) + V2t2 / 7200 ) } + ( V2t3 / 7200 )

S = { V1 ( t1 + t2 ) / 7200 } + { V2 ( t2 + t3 ) / 7200 }

As t1 + t2 + t3 = T

S = { V1 ( T – t3 ) / 7200 } + { V2 ( T – t1 ) / 7200 }

S = V1T / 7200 + V2T / 7200 – V1t3 / 7200 – V2t1 / 7200

Now t = V1 / α and t3 = V2 / β

5

6 of 8

S = { T ( V1 + V2 ) / 7200 } – ( V1 × V2 ) / 7200 β – ( V1 × V2 ) / 7200 α

S = { T ( V1 + V2 ) / 7200 } – V1V2 / 7200 β – V1V2 / 7200 α

7200S = T ( V1 + V2 ) – V1V2 ( 1 / α + 1 / β )

From equation ( 2 )

t2 βC = V1 – V2

V2 = V1 – t2 βC

V2 = V1 – βC ( T – t1 – t3 )

V2 = V1 – βC ( T – V1 / α – V2 / β )

6

7 of 8

V2 = V1 – βC T + βC V1 / α + βC V2 / β

V2 – βC V2 / β = V1 – βC T + βC V1 / α

V2 ( 1 – βC / β ) = V1 – βC ( T + V1 / α )

V2 = V1 – βC ( T + V1 / α ) / ( 1 – βC / β )

7

8 of 8

Thank You

www.myelectrical2015.com

8