1 of 2

Find the mean of each of the following frequency distributions: (5 – 14)

Class interval

Frequency

0 - 8

5

8 - 16

6

16 - 24

4

24 - 32

3

32 - 40

2

(3 marks)

Sol.

Class

interval

Class Mark

(xi)

di =

fidi

4

Total

--

--

Σ fidi =

72

Class width

= 8

–8

0

8

16

–16

Frequency (fi)

Σ fi =

20

4 + 8

20

28

36

12 + 8

20 + 8

28 + 8

= xi

20

Assumed Mean (A) =

20

4 - 20

12 - 20

20 - 20

28 - 20

36 - 20

×

×

×

×

×

12

+

+

+

+

6

4

3

2

5

0

0 - 8

8 - 16

16 - 24

24 - 32

32 - 40

A

0 + 8

2

– 128

56

80

48

24

32

xi

– A

20

+

+

+

+

Lower limit + upper limit

2

Class mark =

Q.

Σ fi

 

A

Mean

 

=

+

 

Σ fidi

RD – 15.23 - Level-1 – Q11

2 of 2

Find the mean of each of the following frequency distributions: (5 – 14)

Class interval

Frequency

0 - 8

5

8 - 16

6

16 - 24

4

24 - 32

3

32 - 40

2

(3 marks)

Sol.

Q.

d

=

Σ fidi

Σ fi

=

– 72

20

=

d

A

+

d

=

20

( 3.6)

=

16.4

Σ fidi =

72

Σ fi =

20

Assumed Mean (A) =

20

1

3

=

16.4

 

6

0

+

Mean

 

– 3.6

=

20

3.6