ARITHMETIC
PROGRESSIONS
of an A.P.
1,
3,
5,
7,
…
a1
a2
a3
a4
For a given AP
a = a1
= 1
d = a2 – a1
= 3 – 1
= 2
By adding d to a term of an AP,
we get its next term
a2 =
a1 + d
= 1 + 2
= 3
a3 =
a2 + d
= 3 + 2
= 5
a4 =
a3 + d
= 5 + 2
= 7
Lets find a & d