1 of 3

Q.

1.2m

30o

A

B

C

D

E

P

R

A 1.2 m tall girl spots a balloon moving with the wind in a horizontal

line at a height of 88.2 m from the ground. The angle of elevation of the

balloon from the eye of girl is 60º. After some time, angle of elevation reduces to 30º. Find the distance travelled by the balloon during the interval.

line of sight

Horizontal line

88.2m

88.2m

line of sight

Q

?

60o

2 of 3

A 1.2 m tall girl spots a balloon moving with

the wind in a horizontal line at a height of

88.2 m from the ground. The angle of

elevation of the balloon from the eyes of

girl is 60º. After some time, angle of elevation

reduces to 30º. Find the distance travelled

by the balloon during the interval.

Q.

87 m

88.2 m

Height of balloon from the ground

(AB) = 88.2 m

Height of the girl (PE) = 1.2 m

PE =

QA =

RC

BQ = BA – QA

=

88.2

– 1.2

= 87 m

In right ΔBQP,

tan 60º =

BQ

PQ

=

87

PQ

PQ

=

87

PQ

=

87

×

PQ

=

87

3

PQ

=

P

B

E

A

C

R

D

Q

1.2 m

60º

30º

3

3

3

3

3

3

29

3

= 1.2m

BQ

Observe ‘BA’

Find : QR

QR is a part of PR

Observe ‘QR’

QR = PR – PQ

PQ belongs to right angled triangle BQP

Ratio of opposite side and Adjacent side reminds us of _________

‘tan’

tan 60o =

?

 

29

3

Opposite

side

Adjacent side

Observe ∠P

BA is made up of

BQ and QA

For ∠BPQ

Opposite side →

Adjacent side →

BQ

PQ

Sol.

Now, let us rationalise the denominator

3 of 3

88.2 m

In right ΔPRD,

tan 30º =

DR

PR

=

87

PR

1

PR

=

87

– PQ

PR

Distance travelled by the balloon is

100.34 m

3

3

QR

29

3

=

87

3

QR

=

58

3

P

E

A

C

R

Q

1.2 m

60º

30º

Opposite

side

29

3

QR

=

58

× 1.73

QR

=

100.34 m

A 1.2 m tall girl spots a balloon moving with

the wind in a horizontal line at a height of

88.2 m from the ground. The angle of

elevation of the balloon from the eyes of

girl is 60º. After some time, angle of elevation

reduces to 30º. Find the distance travelled

by the balloon during the interval.

Sol.

QR = PR – PQ

Ratio of opposite side and Adjacent side reminds us of _________

‘tan’

PR belongs to

right angled triangle PRD

tan 30o =

?

1

 

Observe ∠P

For ∠P

Opposite side →

Adjacent side →

DR

PR

 

Q.

Adjacent side

87 m

QR =

B

D