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Lesson 14:

Sine, Cosine, and Tangent, Angles of Elevation and Depression, Rectangular and Polar Coordinates, Coordinate Conversion

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Warm Up:

Identify the Parts of the Right Triangle in relation to Angle A:

A

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Vocabulary:

Opposite (side): The side directly across from selected angle

Adjacent (side): the side next to the selected angle that is not the hypotenuse

Hypotenuse: The side of a right triangle directly across from the right angle

Sine:o/h

Cosine:a/h

Tangent:o/a

Unit Vector: A vector with a length of one.

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Sine, Cosine, Tangent:

Sin A: Opposite/Hypotenuse

Cos A: Adjacent/Hypotenuse

Tan A: Opposite/Adjacent

SohCahToa

A

Opposite

Adjacent

Hypotenuse

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Sine, Cosine, Tangent(2):

Uses of Sine, Cosine, and Tangent:

Use Sin and Tan to find x and y:

8/y=sin 15’ 8/x=tan 15’

8=ysin 15’ 8=xtan 15’

8/sin 15’=y 8/tan 15’=x

y~~30.9’ x~~29.9’

Use cos to find j, and the pythagorean theorem to find k:

cos j=8/13 13^2-8^2=k^2

cos j~~0.61538461538….. 169-64=k^2

Inverse cos= cos^-1 0.61538461538~~52.0 105=k^2

j~~52’ 105^½=k

k~~10.2

15 ‘

8

x

y

j

8

13

k

Note: Be SURE your calculator is set to degrees

~~: Approximately equal to

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Angles of Depression/Elevation:

Measured upward from horizontal

Measured downward from horizontal

Horizontal

Line of sight

Angle of Elevation

Horizontal

Line of sight

Angle of Depression

Angle of Elevation

Angle of Depression

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Angles of Depression/Elevation(2):

A 5th tall man is 20 ft away from a tree, and measures the angle of elevation to the top of the tree is 30’. How tall is the tree?

Solve for y using tan:

y/20=tan 30’

y=20tan 30’

y~~11.55

Now add the man’s height as well!

5+11.55=16.55

Height of the tree:16.55ft

5 ft

20 ft

30’

y

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Angles of Depression/Elevation(3):

An unmanned drone is flying at an altitude of 2000ft. The village that is about to be blown up is at an angle of depression of 30’. What is the slant length from the drone to the village?

2000ft

30’

60’

Angle of Depression: 30’

Angle A: 60’

Find s using cos:

cos 60’ = 2000/s

s=2000/cos 60’

s~~4000

s

=4000

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Regular/Polar Coordinates:

Regular Coordinates: (-8, 6) = 8 to the left of the origin, 6 up from the origin

Written without the parentheses: -8i^ + 6j^

i^=Used to indicate positive x direction. Unit Vector.

j^=Used to indicate positive y direction. Unit Vector.

Ordered Pair: (-8,6)

Vector Form: -8i^+6j^

8

-8

-6

6

(-8,6) or -8i^+6j^

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Regular/Polar Coordinates(2):

Polar Coordinates: Uses a distance and an angle

Positive Angles: Counterclockwise from positive x axis

Negative Angles: Clockwise from positive x axis

-200’

7

Can be written in two ways:

(7,-220’) or 7 -200’

Note: (-7, 290’) ,(7, 160’) and (-7,-20) get you to the same place!

160’

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Coordinate Conversation:

To convert from polar to regular coordinates:

1. Draw a diagram

2. Determine the length of the hypotenuse

3. Measure the angle

4. Measure the polar angle from the positive x axis

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Coordinate Conversation(2):

Convert (2,3)/2i^ + 3j^ to polar coordinates.

(3,2)

(3,0)

(0,0)

r

2

r^2=3^2 + 2^2

r^2=13

r=13^1/2

tan x = ⅔=0.6667

tan^-1=33.69’

33.69’

(13^½,-326.31’)

Other ways to write it:

(13^½, 33.69’)

(-13^½, -146.31’)

(-13^½, -213.69)

=13^1/2

-326.31’

3

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Coordinate Conversation (3):

Convert (-13, -253’) to Rectangular Form:

Step 1: Draw the angle first

-253’

73’

Step 2: Go down 13 units from the origin in the direction c is pointing

c

13

a

b

a=13cos 73’

a~~3.80

b=13sin 73’

b~~12.43

(3.80, -12.43) or 3.80i^ - 12.43j^

73’

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Practice 1:

Find x and y:

8

9

x’

y

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Practice 2:

A 6ft tall man is 50 feet from a streetlight, and he measures the angle of elevation at 20’. How tall is the streetlight?

6ft

20’

50 ft

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Practice 3:

Convert (2,2) or 2i^ + 2j^ to Polar Coordinates.

(2,2)

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Summary:

Sine: o/h

Cosine: a/h

Tan: o/a

Angle of Elevation: Measured upward from the horizontal

Angle of Depression: Measured downward from the horizontal

Regular Coordinates: Uses two numbers, one indicating the distance of the point to the right or left of the origin, the other the distance above or below the axis

Polar Coordinates: Uses a distance and an angle

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Homework:

Pg 113

4-17 all

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Sources Cited:

Saxon, John H., Jr. "Lesson 14." Advanced Mathematics: An Incremental Development. 2nd ed. Norman, OK: Saxon, 1997. 108-112. Print.

"Unit Vector." Wolfram MathWorld. N.p., n.d. Web. 28 Sept. 2013.