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ANALOG CIRCUITS

(V18ECET08)

II-B.Tech II- Sem-ECE & ECT

(V18 Regulation)

Prepared

Dr.U Yedukondalu

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UNIT-1

WAVE SHAPING CIRCUITS

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Wave Shaping

Definition: It is the process of changing the shape of input signal with linear / non-linear circuits.

Types:

  1. Linear Wave Shaping
  2. Non-linear Wave Shaping

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Linear Wave Shaping

Definition: The process where by the form of a non-sinusoidal signal is changed by transmission through a linear network is called Linear Wave Shaping.

Types:

  1. High Pass RC Circuit.
  2. Low Pass RC Circuit.

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Non-sinusoidal wave forms

  1. Step
  2. Pulse
  3. Square wave
  4. Ramp
  5. Exponential wave forms.

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Step Waveform

t

t=0

i

Vi=0 t<0

V =V t>0

A step voltage is one which maintains the value zero for all times t<0 and maintains the value V for all times t>0.

Vi

V

Pulse

The pulse amplitude is „V‟ and the pulse duration is tp.

0≤t≤tp

Otherwise

Vi=V

Vi=0

t=tp

t

Vi

V

t=0

0

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Square Wave

  • A wave form which maintains itself at one constant level v1 for a time T1 and at other constant Level V11 for a time T2 and which is repetitive with a period T=T1+T2 is called a square-wave.

T1

T2

Ramp

A waveform which is zero for t<0 and which increases linearly with time for t>0.

Vi

Vi =αt

Vi =αt , t>0

0

t

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Exponential

0

t

  • The exponential waveform input is given by

where T is the time constant of the exponential input

Vi

V

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High Pass RC Circuit

R

+

V

o

C

+

-

V

i

-

If f=low, Xc becomes high

C act as open circuit, so the Vo=0.

If f=high, Xc becomes low

C acts as short circuit, so we get the output.

The higher frequency components in the input signal appear at the output with less attenuation due to this behavior the circuit is called “High Pass Filter”.

XC =

1

2ΠfC

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Sinusoidal input

+

V

O

i

+

Vin

_

_

  • For Sinusoidal input, the output increases in amplitude with increasing frequency.

C

R

V

in

R - j XC

V

i =

=

R -

in

j

2πf C

Vin

i=

R 1-

j

2πfRC

O

Vin ×R

Vin

V =i R=

=

1-

j

2πfRC

j

R 1- 2πfR C

Vo= iR

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VO

1

=

Vin

1+j -f1

f

1

=

VO

V in

1 +

2

f1

f

θ =-tan -1-f1 = tan-1f1

f f

At the frequency f = f1

Vin

VO =

1 = 1 =0.707

1+1 2

A =0.707

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At f = f1 the gain is 0.707 or this level corresponds to a signal reduction of 3

decibels(dB).

f1 is referred to as Lower 3-dB frequency.

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Square wave input

  • Percentage Tilt ( 0 0 Tilt)

Tilt is defined as the decay in the amplitude of the output voltage wave due to the input voltage maintaining constant level

2

1

X 100

P =

1

V

V V 1

1

- T 1

R C

= V 1. e

V

'

2

- T 2

RC

V

'

= V2 . e

1

2

V

'

- V = V

V - V ' = V

1 2

(1)

(2)

(3)

(4)

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& because of

  • A symmetrical square wave is one for which T1=T2 =

symmetry V1 = - V2

By substituting these in above equation (3)

-T2RC -

V=V1.e V2

-T2RC+

V=V1.e V1

-T2RC

V=V1(1+e )

I

Equation (1)

II

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ForRC>>T theequation(I)&(II)becomesas

1

2

V1 V (1+ T

2 4RC 2 4RC

) & V1 V (1- T )

1

V1 -V1

Thepercentage tilt ‘P’ is definedby P=

V

2

× 100

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High Pass RC Circuit acts as Differentiator:-

  • The time constant of high pass RC circuit in very small in comparison within the time required for the input signal to make an appreciable change, the circuit is called a “differentiator”.
  • Under this circumstances the voltage drop across R will be very small in comparison with the drop across C. Hence we may consider that the total input Vi appears across C, so that the current is determined entirely by the capacitance.

and the output signal across R is

  • Then the current is i = C

V0 = iR

V0 = RC

  • hence the output is proportional to the derivative of the input.

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Low Pass RC Circuit

C

X =

1

2Πf

C

If f=low, Xc becomes high

C act as open circuit, so we get the output.

If f=high, Xc becomes low

C acts as short circuit, so Vo=0.

As the lower frequency signals appear at the output, it is called as

“Low pass RC circuit”.

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Sinusoidal input

in

V

× XC

j XC

O

V =

R +

j

1

2πfC

C

X =

in

V

×

1

j ω C

1

O

V =

R +

j ω C

wh

ere

O

Vin Vin

V=

=

jωRC+1 1+j2πfRC

CS

o

V = 1 i

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O

Vin

V =

1+ j f

f

2

2

1

2πRC

where f =

A = VO

Vin

=

1

1 + j

f

f2

A

= 1

2

1 + f

f

2

θ=- tan -1 f

f

2

and

At the frequency f = f2

Vin

VO =

1 = 1 =0.707

1+1 2

A =0.707

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At f = f2 the gain is 0.707 or this level corresponds to a signal reduction of 3 decibels(dB).

f2 or fh is referred to as upper 3-dB frequency.

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Square wave input

0 0to

  • Rise Time( tr):

The time required for the voltage to rise from 10 900 0of the final steady value is called “Rise Time”.

Vd.c.

V’

V01

V02

V’

V2

V2

V1

T1

V’’

T2

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= V1 + (V1-V 1 ) . e -T 1 RC

The output voltage V01 & V02 is givenby

………………… (1)

………………… (2)

V01

V

02

= V11 + (V2-V 11 ) . e - T 2 RC

if we set

and

V01 = V2 at t=T1

V02 = V1 at t= T1+T2

1 1

V2= V +( V1-V ) e

11 11

1

V =V +( V2-V )

-

- T 1 RC

T

2

RC

e

Since the average across R is zero then the d.c voltage at the output is same as that of the

input. This average value is indicated as Vd.c.

Consider a symmetrical square wave with zero average value, so that

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- T

V 1 - e - T 2RC

V =

2

1 + e

2RC ⎥⎦

T

V e T 2RC - 1

V2 = 2

e

2RC + 1⎥⎦

T 4RC

2

2 e2x + 1

V = V . e2x - 1

where x =

2

V = V tan hx

2

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Low pass RC circuit acts as an integrator

  • The time constant is very large in comparison with the time required for the input signal to make an appreciable change, the circuit is called an

“Integrator”.

  • As RC>>T the voltage drop across C will be very small in comparison to the voltage drop across R and we may consider that the total input Vi appear and across R, then

Vi =iR

For low pass RC circuit the output voltage Vo is given by

O

V

= 1

i dt

C

O

V = 1 Vi

dt

CR

O

i

V = 1

V dt

RC

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Advantages of Integrator over differentiator

  • Integrators are almost invariably preferred over differentiators in analog

computer applications for the following reasons.

  • The gain of the integrator decreases with frequency where as the gain of the differentiator increases linearly with frequency. It is easier to stabilize the former than the latter with respect to spurious oscillations.

  • As a result of its limited band width an integrator is less sensitive to noise voltages than a differentiator.

  • If the input wave form changes very rapidly, the amplifier of a

differentiator may over load.

  • It is more convenient to introduce initial conditions in an integrator.

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Non-Linear Wave Shaping

Definition:

The process where by the form of a sinusoidal signals are going to be altered by transmission through a non-linear network is called Non-linear Wave Shaping.

Non-linear elements (like Diode, transistor) in combination with resistors can function as clipper circuit.

Types:

  1. Clippers.
  2. Clampers.

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Clipper Classifications

According to biasing, the clippers may be classified as

  • Unbiased clippers and
  • Biased clippers.

According to configuration used the clippers may be

  • Series diode clippers
  • Parallel or shunt diode clippers
  • A series combination of diode, resistor and reference supply
  • Multi-diode clippers consisting of several diodes, resistors

and reference voltages

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Contd…

According to level of clipping the clippers may be

  • Positive clippers
  • Negative clippers
  • Biased clippers and
  • Combination clippers

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Clipper

  • Clipping circuits are used to remove the part of a signal that is above or below some defined reference level.
  • Clippers also known as

Voltage limiters

Current limiters Amplitude selectors Slicers

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Unbiased Clippers( Parallel Positive Clippers)

  • Without the battery, the output of the circuit below would

be the negative portion of the input wave (assuming the

bottom node is grounded). When vi > 0, the diode is on (short-circuited), vi is dropped across R and vo=0. When vi

<0, the diode is off (open-circuited), the voltage across R is

zero and vo=vi.

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Unbiased Clippers( Parallel Negative Clippers)

+ive cycle :- anode is at ground potential and cathode sees variable +ive voltage from 0 to +Vm So complete cycle, the diode is reverse biased and Vo =Vin.At positive peak Vo=+5V

-ive cycle :- anode is at ground potential and cathode sees variable -ive vols from 0 to –Vm. When magnitude of in put volatge i.e / Vin/ >Vd, the diode become forward biased and hence Vo =-Vd =0.7V

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Series Positive Clipper

+ive cycle :- anode is at ground potential and cathode sees variable +ive voltage from 0 to +Vm.For comlpete, cycle, diode become reverse biased and hence Vo =0V

-ive cycle :- anode is at ground potential and cathode sees variable -ive voltage from 0 to –Vm. So in complete cycle, the diode is forward biased and Vo= Vin + Vd andAt negative peak, Vo= -Vm+ Vd = -5v

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Series Negative clipper

+ive cycle :- anode is at positive potential from 0 to +Vm.For comlpete, cycle, diode become forward biased and hence vo= 5v

-ive cycle :- Cathode is at ground potential and cathode sees variable - ive voltage from 0 to –Vm. So in complete cycle, the diode is Reverse biased and negative peak, Vo= 0

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Positive Shunt clipping with zero reference Rvoltage

D

Vo

Vi

Transfer characteristics equations:

VO=0for Vi>0 VO = Vi for Vi< 0

D– ON

VO=Vγfor Vi >Vγ VO=Vi for Vi < Vγ

D– OFF

[Ideal]

V

O

V

i

V

O

V

i

Slope =1

Input

Input

Output

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Positive Shunt clipping with positive reference Voltage

D

Vi Vo

Transfer characteristics equations:

Vi < VR+Vγ

D – OFF

VO = Vi

D – ON

Vi > VR+Vγ

VO = VR+Vγ

Input

VR + Vγ VR + Vγ Output

VO

VR VO

Vi

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Positive Shunt clipping with negative

reference voltage

R

D

VR

Vi

Vo

Transfer characteristics equation:

Vi > Vγ - VR

D – ON VO

D – OFF

= Vγ - VR Vi < Vγ - VR VO = Vi

VO

VO

Vi

V

i

Input

Output

Vi

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Negative Shunt clipping with zero reference voltage

R

Vi

Vo

D

Transfer Characteristic

Equations:

Vi > -Vγ D – OFF

VO = Vγ

Vi < -Vγ D – ON

VO = -Vγ

-Vγ

-Vγ

VO

VO

Vi

Vi

Input

Output

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Negative Shunt clipping with positive

reference voltage

R

D

VR

Vi

Vo

Transfer Characteristics

Equations:

D – ON

Vi < VR-Vγ

VO = VR-Vγ

Vi > VR-Vγ

D – OFF

VO = Vi

VR - Vγ

VO

Vi

Vi

VO

DOFF

DON

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Negative Shunt clipping with negative reference voltage

R

D

V

R

Vi

Vo

Transfer characteristic

equations:

D – ON VO

Vi < -( Vγ + VR)

= -( Vγ + VR)

Vi < -( Vγ + VR) D – OFF

VO = Vi

V

O

VO

Vi

Vi

- (Vγ + VR

Input

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Negative Series clipper with zero

reference

R

Vi

Vo

D

Transfer characteristicequations:

Vi<0

Vi>0

D–OFF

D–ON

VO=0

VO=Vi

IdealDiode

Vi<Vγ

D–OFF

VO=0

Vi>Vγ

D–ON

VO=Vi-Vγ

PracticalDiode

VO

VO

Vi

Vi

Output

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CLIPPING AT TWO

INDEPENDENT LEVELS

R

D

VR

Vi

Vo

D

VR

Transfercharacteristic equations:

Inp

ut

(Vi)

DiodeState

Outp

ut

(VO)

Vi VR

1

D1 –ON,D2 – OFF

VO =VR

1

VR < Vi < VR

1 2

D1 –OFF,D2 – OFF

VO =Vi

Vi VR2

D1 –OFF,D2 – ON

VO=VR

2

V

O

VO

Vi

Vi

Input

Output

VR

1

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Contd..

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CLAMPING CIRCUIT

  • The need to establish the extremity of the positive (or) negative signal excursion at some reference level. When the signal is passed through a capacitive coupling network such a signal has lost its d.c. component. The clamping circuit introduces the d.c. components at the outside, for this reason the coupling circuits are referred to as d.c. restore (or) d.c. reinserter.

  • Def : “ A clamping circuit is one that takes an input waveform and provides an output i.e., a faithful replica of its shape, but has one edge clamped to the zero voltage reference point.

There are two types of clamping circuits.

  • 1) Negative clamping circuit.
  • 2) Positive clamping circuit.

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Diode :- Clamper

Positive Clamper

The circuit for a positive clamper is shown in the figure. During the negative half cycle of the input signal, the diode conducts and acts like a short circuit. The output voltage Vo

0 volts . The capacitor is charged to the peak value of input voltage Vm. and it behaves like a battery. During the positive half of the input signal, the diode does not conduct and acts as an open circuit. Hence the output voltage Vo Vm+ Vm This gives a positively clamped

voltage.

Vo Vm+ Vm = 2

V

m

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Negative Clamper

During the positive half cycle the diode conducts and acts like a short circuit. The capacitor charges to peak value of input voltage Vm.

During this interval the output Vo which is taken across the short circuit will be zero During the negative half cycle, the diode is open. The output voltage can be found by applying KVL.

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Biased Clamper

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CLAMPING CIRCUIT THEOREM

  • Therefore the charge acquired by the capacitor during the forward interval

Af = Rf

Ar R

Consider a square wave input is applied to a clamping circuit under steady state condition

If Vf (t) is the output waveform in the forward direction, then from below figure

the capacitor charging current is

V

if = f

Rf

Therefore the charge acquired by the capacitor during the

forward interval

i dt =

V dt =

T1 T1

f

1

Rf

A

f

Rf

f

0 0

…………….. (1)

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  • Similarly if Vf (t) is the output voltage in the reverse direction, then the current which discharges by the capacitor is

1 Ar

T2 T2

ir dt = R Vr dt = R

…………….. (2)

T1 T2

In the steady-state the net charge acquired by the capacitor must be zero.

Therefore from equation (1) & (2) this equation says that

for any input waveform the ratio of the area under the output voltage curve in the forward direction to the reverse direction is equal to the ratio .

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Clamping Circuit taking Source and Diode Resistances into account

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Practical Clamping circuit

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Effect of diode characteristics on clamping voltage

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Synchronized Clamping